Chapter 11.6, Problem 1E

To determine

To find: the distance between the given points to the nearest tenth.

Answer to Problem 1E

  $d=10$

Explanation of Solution

Given:

The given points are $\left(-6,0\right),\left(4,0\right)$ .

Calculation:

As the given pairs of point are $\left(-6,0\right),\left(4,0\right)$ .

Since, the distance formula is $d=\sqrt{{\left(x_2-x_1\right)}^2+{\left(y_2-y_1\right)}^2}$ .

Therefore, the distance between the given points is

  $\begin{array}{l}d=\sqrt{{\left(x_2-x_1\right)}^2+{\left(y_2-y_1\right)}^2}\\ d=\sqrt{{\left(4-\left(-6\right)\right)}^2+{\left(0-0\right)}^2}\left\{\text{substitutes the given value}\right\}\\ d=\sqrt{{\left(10\right)}^2+{\left(0\right)}^2}\left\{\text{simplify}\right\}\\ \therefore d=\sqrt{100+0}\{\because {10}^2=100\}\\ \Rightarrow d=\sqrt{100}\left\{\text{add the both terms}\right\}\\ \therefore d=\sqrt{{10}^2}=10\{\sqrt{a^2}=a\}\end{array}$

Hence, the distance between the given points to the nearest tenth is $d=10$ .