Chapter 11.6, Problem 10ST

To determine

To find: the value of c corrects up to the nearest hundred under given condition.

Answer to Problem 10ST

  $c=22.022$ .

Explanation of Solution

Given:

  $a=14,b=17$ .

The given triangle is shown below:

  

Calculation:

As the given triangle is right angle tringle.

Therefore, by using Pythagoras theorem, $c^2=a^2+b^2$

Thus,

  $\begin{array}{l}{c}^2=a^2+b^2\\ ={14}^2+{17}^2\left\{\text{substitutes the given value}\right\}\\ =196+289\{\because {14}^2=196,{17}^2=289\}\\ =485\left\{\text{add the both terms}\right\}\end{array}$

  $\begin{array}{l}\therefore c=\sqrt{485}\left\{\text{taking square root on both the sides}\right\}\\ \Rightarrow c=22.022\{\text{round up to nearest hundred}}\end{array}$

Hence, the solution of the given expression is $c=22.022$ .