Chapter 11.10, Problem 8P

To determine

To find: The distance covered by the object in $15\text{sec}$ .

Answer to Problem 8P

The distance covered is $1102.5\text{m}$ .

Explanation of Solution

Given:

The formula for the time is $t=\sqrt{\frac{2s}{g}}$ .

The acceleration due to gravity is $g=9.8\text{m}/{\text{s}}^2$ .

The time is $15\text{sec}$ .

Calculation:

Consider the object under free fall takes a time to cover the particular distance is,

  $t=\sqrt{\frac{2s}{g}}$

Then, for time of $15\text{sec}$ .

  $\begin{array}{l}15\text{sec}=\sqrt{\frac{2s}{9.8\text{m}/{\text{s}}^2}}\\ \frac{2s}{9.8\text{m}/{\text{s}}^2}=225{\sec }^2\\ 2s=2205\\ s=1102.5\text{m}\end{array}$