Chapter 11, Problem 8MPS

To determine

To find:The amount of water to be added to form the solution 15% of acid.

Answer to Problem 8MPS

The amount of water to be added to form the solution 15% of acidis $0.85\text{ L}$ .

Explanation of Solution

Given information: The 24 liters of water has the 18% acid.

Calculation:

Assume the amount of water added is $x$ .

The amount of solution becomes $24+x$ . Since the strength should be 15% then the amount must be $0.15\left(24+x\right)$ .

The amount in concentrated solution is $0.18\left(24\right)=4.32$ .

The water in new solution is $4.32-x$ .

Equate the amount of water in new and existing solution.

  $\begin{array}{l}0.15\left(24+x\right)=4.32-x\\ 3.6+0.15x=4.32-x\\ -0.72=-0.85x\\ x=0.85\text{ L}\end{array}$

Thus, the amount of water to be added to form the solution 15% of acid is $0.85\text{ L}$ .