EBK BASIC CHEMISTRY
5th Edition
ISBN: 8220101472335
Author: Timberlake
Publisher: PEARSON
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Chapter 11.7, Problem 11.63QAP
Interpretation Introduction
Interpretation: Calculate volume of oxygen needed to react with 55.2 gram of butane at 0.850atm and 25°C
Conceptual Introduction: Molar mass of substance are given in periodic table. Element molar mass is in gram/mole. We can determine chemical amount of known substance in moles by dividing the substance mass in grams by substance molar mass.
The
Equation as follows-
PV = nRT
Where, P = pressure of gas
V =volume of gas
N= no. of moles of gas (amount of substance in gas)
R = Universal gas constant
The gas constant R has a value 8.314J/mole Kelvin
Given:
Mass of butane: 55.2 grams
Pressure = 0.850 atm
Temperature = 25°C
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Chapter 11 Solutions
EBK BASIC CHEMISTRY
Ch. 11.1 - Prob. 11.1QAPCh. 11.1 - Prob. 11.2QAPCh. 11.1 - Prob. 11.3QAPCh. 11.1 - Prob. 11.4QAPCh. 11.1 - Prob. 11.5QAPCh. 11.1 - Prob. 11.6QAPCh. 11.1 - Prob. 11.7QAPCh. 11.1 - Prob. 11.8QAPCh. 11.2 - Why do scuba divers need to exhale air when they...Ch. 11.2 - Why does a sealed bag of chips expand when you...
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