
Concept explainers
Interpretation:
The final pressure of air in the lungs of a scuba diver who is 60ft below the ocean surface should be calculated if the final volume of air is 150.0 ml at a temperature of37°C. Given that the air inhaled by the diver has an initial volume of 50.0 ml, pressure of 3.00 atm and at a temperature of8°C
Concept introduction:
► As per Charles law, volume is directly related to temperature:
► As per Boyles law, pressure is inversely related to volume:
► As per Gay-Lussac’s law, pressure is directly related to temperature:
► Equations (1), (2) and (3) give the combined
► Volume conversion:
1 ml = 0.001L (or) 1L = 1000 ml
Temperature conversion:
K = °C + 273 (or) °C = K - 273
Pressure conversion:
1 atm = 760 torr = 760 mmHg
1 torr = 1 mmHg
Given:
Initial volume V1 = 50.0 mL
Initial pressure P1 = 3.00 atm
Initial temperature T1 = 8°C = (8 + 273) K = 281 K
Final temperature T2 = 37°C = (37 + 273) K = 310 K
Final volume = V2 = 150.0 mL
Final pressure = P2

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Chapter 11 Solutions
EBK BASIC CHEMISTRY
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