(a)
Interpretation: For the given set of compounds, the net molecular dipole moment has to be indicated.
Concept Introduction:
Dipole moment is the measure of net molecular polarity. Dipole moment can be determined experimentally and its value can give an idea of the polar character of a molecule. It is a vector quantity as it has a direction as well as magnitude.
The direction of dipole moment is usually represented by an arrow pointing from positive end towards the negative end. The sum of all vectors in a compound is called the molecular dipole moment. It can be given by considering both magnitude and the direction of each individual dipole moment involved in that compound.
If dipole moments of the individual bonds are equal in magnitude but in opposite direction, there is no net molecular dipole moment. If dipole moments of the individual bonds aren’t in opposite direction, there is a net molecular dipole moment.
According to VSEPR (Valence Shell Electron Pair Repulsion) theory, each molecule gets a unique structure. That structure is explained by considering steric number of that molecule. The steric number is the combination of both number of σ-bonds and number of lone pairs involved in a particular molecule.
σ-bonds are formed by the mutual sharing of electrons between the two atoms. As a result, bond between two atoms is formed. This type of bond is called covalent bond. In this process, bonding electron pairs are involved. Non-bonding electrons are not involved in the bond formation. They are called lone pairs.
The geometry of the central atom will be determined by counting the steric number followed by the hybridization state of that central atom and finally electronic arrangement of atoms in space.
If the steric number is 4, the central atom has sp3 hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be tetrahedral. If the steric number is 3, the central atom has sp2 hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be trigonal planar. If the steric number is 2, the central atom has sp hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be linear.
To find: Indicate the direction of the net molecular dipole moment for the compound (a).
(b)
Interpretation: For the given set of compounds, the net molecular dipole moment has to be indicated.
Concept Introduction:
Dipole moment is the measure of net molecular polarity. Dipole moment can be determined experimentally and its value can give an idea of the polar character of a molecule. It is a vector quantity as it has a direction as well as magnitude.
The direction of dipole moment is usually represented by an arrow pointing from positive end towards the negative end. The sum of all vectors in a compound is called the molecular dipole moment. It can be given by considering both magnitude and the direction of each individual dipole moment involved in that compound.
If dipole moments of the individual bonds are equal in magnitude but in opposite direction, there is no net molecular dipole moment. If dipole moments of the individual bonds aren’t in opposite direction, there is a net molecular dipole moment.
According to VSEPR (Valence Shell Electron Pair Repulsion) theory, each molecule gets a unique structure. That structure is explained by considering steric number of that molecule. The steric number is the combination of both number of σ-bonds and number of lone pairs involved in a particular molecule.
σ-bonds are formed by the mutual sharing of electrons between the two atoms. As a result, bond between two atoms is formed. This type of bond is called covalent bond. In this process, bonding electron pairs are involved. Non-bonding electrons are not involved in the bond formation. They are called lone pairs.
The geometry of the central atom will be determined by counting the steric number followed by the hybridization state of that central atom and finally electronic arrangement of atoms in space.
If the steric number is 4, the central atom has sp3 hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be tetrahedral. If the steric number is 3, the central atom has sp2 hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be trigonal planar. If the steric number is 2, the central atom has sp hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be linear.
To find: Indicate the direction of the net molecular dipole moment for the compound (b)

Want to see the full answer?
Check out a sample textbook solution
Chapter 1 Solutions
Organic Chemistry
- true or false The equilibrium constant for this reaction is 0.20. N2O4(g) ⇔ 2NO2(g) Based on the above, the equilibrium constant for the following reaction is 5. 4NO2(g) ⇔ 2N2O4(g)arrow_forwardtrue or false The equilibrium constant for this reaction is 0.20. N2O4(g) ⇔ 2NO2(g) Based on the above, the equilibrium constant for the following reaction is 0.4. 2N2O4(g) ⇔ 4NO2(g)arrow_forwardtrue or false Using the following equilibrium, if heat is added the equilibrium will shift toward the reactants. N2(g) + 3H2(g) ⇔ 2NH3(g) + heatarrow_forward
- True or False Using the following equilibrium, if heat is added the equilibrium will shift toward the products. N2O4(g) + heat ⇔ 2NO2(g)arrow_forwardtrue or false Using the following equilibrium, if solid carbon is added the equilibrium will shift toward the products. C(s) + CO2(g) ⇔ 2CO(g)arrow_forwardProvide the complete mechanism for the reaction below. You must include appropriate arrows,intermediates, and formal charges. Please also provide a reason to explain why the 1,4-adduct is preferred over the 1,3-adduct.arrow_forward
- Which of the following pairs are resonance structures of one another? I. III. || III IV + II. :0: n P !༠ IV. EN: Narrow_forwardPredict the major organic product(s) and byproducts (either organic or inorganic) for thefollowing reactions.arrow_forwardA 8.25 g sample of aluminum at 55°C released 2500 J of heat. The specific heat of aluminum is 0.900 J/g°C. The density of aluminum is 2.70 g/mL. Calculate the final temperature of the aluminum sample in °C.arrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY





