Brock Biology of Microorganisms (15th Edition)
Brock Biology of Microorganisms (15th Edition)
15th Edition
ISBN: 9780134261928
Author: Michael T. Madigan, Kelly S. Bender, Daniel H. Buckley, W. Matthew Sattley, David A. Stahl
Publisher: PEARSON
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Chapter 11.1, Problem 3MQ
Summary Introduction

Genome encompasses all the information essential for the survival of that organism. Heritable modification in the nucleotide sequence of the genome that is passed from parent to next generation (progeny cells) is regarded as mutation. Such mutations may result in altering the characteristics of that organism. Selectable mutations confer some advantage on the mutant possessing them, whereas others are referred to as non-selectable mutations. Such non-selectable mutations may result in a remarkable modification in the organism’s phenotype.

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After you feel comfortable with your counting method and identifying cells in the various stages of mitosis, use the four images below of whitefish blastula to count the cells in each stage until you reach 100 total cells, recording your data below in Data Table 1. (You may not need to use all four images. Stop counting when you reach 100 total cells.) After totaling the cells in each stage, calculate the percent of cells in each stage. (Divide total of stage by overall total of 100 and then multiply by 100 to obtain percentage.)   Data Table 1Stage    Totals    PercentInterphase        Mitosis:        Prophase        Metaphase        Anaphase        Telophase        Cytokinesis        Totals    100    100% To find the length of time whitefish blastula cells spend in each stage, multiply the percent (recorded as a decimal, in other words take the percent number and divide by 100) by 24 hours. (Example: If percent is 20%, then Time in Hours = .2 * 24 = 4.8) Record your data in Data…

Chapter 11 Solutions

Brock Biology of Microorganisms (15th Edition)

Ch. 11.4 - Prob. 1MQCh. 11.4 - Prob. 2MQCh. 11.4 - Prob. 1CRCh. 11.5 - Which protein, found in virtually all cells,...Ch. 11.5 - Explain the fate of transferred chromosomal DNA if...Ch. 11.5 - Prob. 3MQCh. 11.5 - What are heteroduplex regions of DNA and what...Ch. 11.6 - During transformation a cell usually incorporates...Ch. 11.6 - In genetic transformation, what is meant by the...Ch. 11.6 - QExplain why recipient cells do not successfully...Ch. 11.7 - Prob. 1MQCh. 11.7 - What is the major difference between generalized...Ch. 11.7 - Why is phage conversion considered beneficial to...Ch. 11.7 - QExplain how a generalized transducing particle...Ch. 11.8 - In conjugation, how are donor and recipient cells...Ch. 11.8 - Explain how rolling circle DNA replication allows...Ch. 11.8 - QWhat is a sex pilus and which cell type, F or F+,...Ch. 11.9 - In conjugation involving the F plasmid of...Ch. 11.9 - Prob. 2MQCh. 11.9 - Prob. 3MQCh. 11.9 - QWhat is a merodiploid and how does an F plasmid...Ch. 11.10 - Why is it usually more difficult to select...Ch. 11.10 - Why do penicillins not kill species of Archaea?Ch. 11.10 - Explain one type of conjugation in Archaea and how...Ch. 11.11 - Prob. 1MQCh. 11.11 - What is the significance of the terminal inverted...Ch. 11.11 - How can transposons be used in bacterial genetics?Ch. 11.11 - Prob. 1CRCh. 11.12 - Why is the CRISPR system considered a prokaryotic...Ch. 11.12 - Prob. 2MQCh. 11.12 - QExplain why incoming DNA recognized by a short...Ch. 11 - A constitutive mutant is a strain that...Ch. 11 - Although a large number of mutagenic chemicals are...Ch. 11 - Why is it difficult in a single experiment to...Ch. 11 - Prob. 4AQ
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