(a) Interpretation: The water of hydration for the compound NiCl 2 ⋅ X H 2 O is to be calculated which contains 21.7 % water. The chemical formula of the compound NiCl 2 ⋅ X H 2 O is to be stated. Concept introduction: The water of crystallization is the number of water molecules present in crystals compounds. The water of crystallization is also known as water of hydration. The water molecules present in the crystal helps the crystal to impart color. These water molecules can be easily removed from the crystal by heating them.

Question

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Answer 1

Question

Chapter 11, Problem 78E

Interpretation Introduction

(a)

Interpretation:

The water of hydration for the compound $NiCl2⋅XH2O$ is to be calculated which contains $21.7%$ water. The chemical formula of the compound $NiCl2⋅XH2O$ is to be stated.

Concept introduction:

The water of crystallization is the number of water molecules present in crystals compounds. The water of crystallization is also known as water of hydration. The water molecules present in the crystal helps the crystal to impart color. These water molecules can be easily removed from the crystal by heating them.

Expert Solution

Answer to Problem 78E

The water of hydration for the compound $NiCl2⋅XH2O$ is $2$ and the chemical formula of the compound is $NiCl2⋅2H2O$ .

Explanation of Solution

The compound $NiCl2⋅XH2O$ contains $21.7%$ water. Therefore, $100 g$ of the compound will have $21.7 g$ of water in it.

The mass of $NiCl2$ unit in $100 g$ of the compound is calculated as shown below.

$mNiCl2=100 g−21.7 g=78.3 g$

The molar mass of water is $18.02 g/mol$ .

The molar mass of $NiCl2$ is $129.5994 g/mol$ .

The number of moles of a substance is given by the expression as shown below.

$n=mM$ …(1)

Where,

• $m$ is the mass of the substance.

• $M$ is the molar mass of the substance.

Substitute the values of mass and molar mass of water in the equation (1).

$n=21.7 g18.02 g/mol=1.2042 mol$

Substitute the values of mass and molar mass of $NiCl2$ in the equation (1).

$n=78.3 g129.5994 g/mol=0.6019 mol$

The molar ratio of $NiCl2:H2O$ can be obtained by dividing the number of moles with the lowest number of mole that is $0.6019 mol$ .

$NiCl2:H2O=0.6019 mol0.6019 mol:1.2042 mol0.6019 molNiCl2:H2O=1:2.001NiCl2:H2O≈1:2$

Therefore, the water of hydration for the compound $NiCl2⋅XH2O$ is $2$ and the chemical formula of the compound is $NiCl2⋅2H2O$ .

Conclusion

The water of hydration for the compound $NiCl2⋅2H2O$ is to $2$ .

Interpretation Introduction

(b)

Interpretation:

The water of hydration for the compound $Ni(NO3)2⋅XH2O$ is to be calculated which contains $37.2%$ water. The chemical formula of the compound $Ni(NO3)2⋅XH2O$ is to be stated.

Concept introduction:

The water of crystallization is the number of water molecules present in crystals compounds. The water of crystallization is also known as the water of hydration. The water molecules present in the crystal helps the crystal to impart color. These water molecules can be easily removed from the crystal by heating them.

Expert Solution

Answer to Problem 78E

The water of hydration for the compound $Ni(NO3)2⋅XH2O$ is $6$ and the chemcial formula of the compound is $Ni(NO3)2⋅6H2O$ .

Explanation of Solution

The compound $Ni(NO3)2⋅XH2O$ contains $37.2%$ water. Therefore, $100 g$ of the compound will have $37.2 g$ of water in it.

The mass of $Ni(NO3)2$ unit in $100 g$ of the compound is calculated as shown below.

$mNi(NO3)2=100 g−37.2 g=62.8 g$

The molar mass of water is $18.02 g/mol$ .

The molar mass of $Ni(NO3)2$ is $182.7032 g/mol$ .

The number of moles of a substance is given by the expression as shown below.

$n=mM$ … (1)

Where,

• $m$ is the mass of the substance.

• $M$ is the molar mass of the substance.

Substitute the values of mass and molar mass of water in the equation (1).

$n=37.2 g18.02 g/mol=2.064 mol$

Substitute the values of mass and molar mass of $Ni(NO3)2$ in the equation (1).

$n=62.8 g182.7032 g/mol=0.344 mol$

The molar ratio of $Ni(NO3)2:H2O$ can be obtained by dividing the number of moles with the lowest number of mole that is $0.344 mol$ .

$Ni(NO3)2:H2O=0.344 mol0.344 mol:2.064 mol0.344 molNi(NO3)2:H2O=1:6$

Therefore, the water of hydration for the compound $Ni(NO3)2⋅XH2O$ is $6$ and the chemcial formula of the compound is $Ni(NO3)2⋅6H2O$ .

Conclusion

The water of hydration for the compound $Ni(NO3)2⋅6H2O$ is to $6$ .

Interpretation Introduction

(c)

Interpretation:

The water of hydration for the compound $CoSO4⋅XH2O$ is to be calculated which contains $30.5%$ water. The chemical formula of the compound $CoSO4⋅XH2O$ is to be stated.

Concept introduction:

The water of crystallization is the number of water molecules present in crystals compounds. The water of crystallization is also known as the water of hydration. The water molecules present in the crystal helps the crystal to impart color. These water molecules can be easily removed from the crystal by heating them.

Expert Solution

Answer to Problem 78E

The water of hydration for the compound $CoSO4⋅XH2O$ is $1$ and the chemical formula of the compound is $CoSO4⋅H2O$ .

Explanation of Solution

The compound $CoSO4⋅XH2O$ contains $10.4%$ water. Therefore, $100 g$ of the compound will have $10.4 g$ of water in it.

The mass of $CoSO4$ unit in $100 g$ of the compound is calculated as shown below.

$mCoSO4=100 g−10.4 g=89.6 g$

The molar mass of water is $18.02 g/mol$ .

The molar mass of $CoSO4$ is $154.9958 g/mol$ .

The number of moles of a substance is given by the expression as shown below.

$n=mM$ …(1)

Where,

• $m$ is the mass of the substance.

• $M$ is the molar mass of the substance.

Substitute the values of mass and molar mass of water in the equation (1).

$n=10.4 g18.02 g/mol=0.577 mol$

Substitute the values of mass and molar mass of $CoSO4$ in the equation (1).

$n=89.6 g154.9958 g/mol=0.578 mol$

The molar ratio of $CoSO4:H2O$ can be obtained by dividing the number of moles with the lowest number of mole that is $0.577 mol$ .

$CoSO4:H2O=0.578 mol0.577 mol:0.577 mol0.577 molCoSO4:H2O≈1:1$

Therefore, the water of hydration for the compound $CoSO4⋅XH2O$ is $1$ and the chemical formula of the compound is $CoSO4⋅H2O$ .

Conclusion

The water of hydration for the compound $CoSO4⋅H2O$ is to $1$ .

Interpretation Introduction

(d)

Interpretation:

The water of hydration for the compound $CrI3⋅XH2O$ is to be calculated which contains $27.2%$ water. The chemical formula of the compound $CrI3⋅XH2O$ is to be stated.

Concept introduction:

The water of crystallization is the number of water molecules present in crystals compounds. The water of crystallization is also known as the water of hydration. The water molecules present in the crystal helps the crystal to impart color. These water molecules can be easily removed from the crystal by heating them.

Expert Solution

Answer to Problem 78E

The water of hydration for the compound $CrI3⋅XH2O$ is $9$ and the chemical formula of the compound is $CrI3⋅9H2O$ .

Explanation of Solution

The compound $CrI3⋅XH2O$ contains $27.2%$ water. Therefore, $100 g$ of the compound will have $27.2 g$ of water in it.

The mass of $CrI3$ unit in $100 g$ of the compound is calculated as shown below.

$mCrI3=100 g−27.2 g=72.8 g$

The molar mass of water is $18.02 g/mol$ .

The molar mass of $CrI3$ is $432.7095 g/mol$ .

The number of moles of a substance is given by the expression as shown below.

$n=mM$ …(1)

Where,

• $m$ is the mass of the substance.

• $M$ is the molar mass of the substance.

Substitute the values of mass and molar mass of water in the equation (1).

$n=27.2 g18.02 g/mol=1.51 mol$

Substitute the values of mass and molar mass of $CrI3$ water in the equation (1).

$n=72.8 g432.7095 g/mol=0.168 mol$

The molar ratio of $CrI3:H2O$ can be obtained by dividing the number of moles with the lowest number of mole that is $0.168 mol$ .

$CrI3:H2O=0.168 mol0.168 mol:1.51 mol0.168 molCrI3:H2O=1:8.99CrI3:H2O≈1:9$

Therefore, the water of hydration for the compound $CrI3⋅XH2O$ is $9$ and the chemical formula of the compound is $CrI3⋅9H2O$ .

Conclusion

The water of hydration for the compound $CrI3⋅9H2O$ is to $9$ .

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Answer 2

Question

Chapter 11, Problem 78E

Interpretation Introduction

(a)

Interpretation:

The water of hydration for the compound $NiCl2⋅XH2O$ is to be calculated which contains $21.7%$ water. The chemical formula of the compound $NiCl2⋅XH2O$ is to be stated.

Concept introduction:

The water of crystallization is the number of water molecules present in crystals compounds. The water of crystallization is also known as water of hydration. The water molecules present in the crystal helps the crystal to impart color. These water molecules can be easily removed from the crystal by heating them.

Expert Solution

Answer to Problem 78E

The water of hydration for the compound $NiCl2⋅XH2O$ is $2$ and the chemical formula of the compound is $NiCl2⋅2H2O$ .

Explanation of Solution

The compound $NiCl2⋅XH2O$ contains $21.7%$ water. Therefore, $100 g$ of the compound will have $21.7 g$ of water in it.

The mass of $NiCl2$ unit in $100 g$ of the compound is calculated as shown below.

$mNiCl2=100 g−21.7 g=78.3 g$

The molar mass of water is $18.02 g/mol$ .

The molar mass of $NiCl2$ is $129.5994 g/mol$ .

The number of moles of a substance is given by the expression as shown below.

$n=mM$ …(1)

Where,

• $m$ is the mass of the substance.

• $M$ is the molar mass of the substance.

Substitute the values of mass and molar mass of water in the equation (1).

$n=21.7 g18.02 g/mol=1.2042 mol$

Substitute the values of mass and molar mass of $NiCl2$ in the equation (1).

$n=78.3 g129.5994 g/mol=0.6019 mol$

The molar ratio of $NiCl2:H2O$ can be obtained by dividing the number of moles with the lowest number of mole that is $0.6019 mol$ .

$NiCl2:H2O=0.6019 mol0.6019 mol:1.2042 mol0.6019 molNiCl2:H2O=1:2.001NiCl2:H2O≈1:2$

Therefore, the water of hydration for the compound $NiCl2⋅XH2O$ is $2$ and the chemical formula of the compound is $NiCl2⋅2H2O$ .

Conclusion

The water of hydration for the compound $NiCl2⋅2H2O$ is to $2$ .

Interpretation Introduction

(b)

Interpretation:

The water of hydration for the compound $Ni(NO3)2⋅XH2O$ is to be calculated which contains $37.2%$ water. The chemical formula of the compound $Ni(NO3)2⋅XH2O$ is to be stated.

Concept introduction:

The water of crystallization is the number of water molecules present in crystals compounds. The water of crystallization is also known as the water of hydration. The water molecules present in the crystal helps the crystal to impart color. These water molecules can be easily removed from the crystal by heating them.

Expert Solution

Answer to Problem 78E

The water of hydration for the compound $Ni(NO3)2⋅XH2O$ is $6$ and the chemcial formula of the compound is $Ni(NO3)2⋅6H2O$ .

Explanation of Solution

The compound $Ni(NO3)2⋅XH2O$ contains $37.2%$ water. Therefore, $100 g$ of the compound will have $37.2 g$ of water in it.

The mass of $Ni(NO3)2$ unit in $100 g$ of the compound is calculated as shown below.

$mNi(NO3)2=100 g−37.2 g=62.8 g$

The molar mass of water is $18.02 g/mol$ .

The molar mass of $Ni(NO3)2$ is $182.7032 g/mol$ .

The number of moles of a substance is given by the expression as shown below.

$n=mM$ … (1)

Where,

• $m$ is the mass of the substance.

• $M$ is the molar mass of the substance.

Substitute the values of mass and molar mass of water in the equation (1).

$n=37.2 g18.02 g/mol=2.064 mol$

Substitute the values of mass and molar mass of $Ni(NO3)2$ in the equation (1).

$n=62.8 g182.7032 g/mol=0.344 mol$

The molar ratio of $Ni(NO3)2:H2O$ can be obtained by dividing the number of moles with the lowest number of mole that is $0.344 mol$ .

$Ni(NO3)2:H2O=0.344 mol0.344 mol:2.064 mol0.344 molNi(NO3)2:H2O=1:6$

Therefore, the water of hydration for the compound $Ni(NO3)2⋅XH2O$ is $6$ and the chemcial formula of the compound is $Ni(NO3)2⋅6H2O$ .

Conclusion

The water of hydration for the compound $Ni(NO3)2⋅6H2O$ is to $6$ .

Interpretation Introduction

(c)

Interpretation:

The water of hydration for the compound $CoSO4⋅XH2O$ is to be calculated which contains $30.5%$ water. The chemical formula of the compound $CoSO4⋅XH2O$ is to be stated.

Concept introduction:

The water of crystallization is the number of water molecules present in crystals compounds. The water of crystallization is also known as the water of hydration. The water molecules present in the crystal helps the crystal to impart color. These water molecules can be easily removed from the crystal by heating them.

Expert Solution

Answer to Problem 78E

The water of hydration for the compound $CoSO4⋅XH2O$ is $1$ and the chemical formula of the compound is $CoSO4⋅H2O$ .

Explanation of Solution

The compound $CoSO4⋅XH2O$ contains $10.4%$ water. Therefore, $100 g$ of the compound will have $10.4 g$ of water in it.

The mass of $CoSO4$ unit in $100 g$ of the compound is calculated as shown below.

$mCoSO4=100 g−10.4 g=89.6 g$

The molar mass of water is $18.02 g/mol$ .

The molar mass of $CoSO4$ is $154.9958 g/mol$ .

The number of moles of a substance is given by the expression as shown below.

$n=mM$ …(1)

Where,

• $m$ is the mass of the substance.

• $M$ is the molar mass of the substance.

Substitute the values of mass and molar mass of water in the equation (1).

$n=10.4 g18.02 g/mol=0.577 mol$

Substitute the values of mass and molar mass of $CoSO4$ in the equation (1).

$n=89.6 g154.9958 g/mol=0.578 mol$

The molar ratio of $CoSO4:H2O$ can be obtained by dividing the number of moles with the lowest number of mole that is $0.577 mol$ .

$CoSO4:H2O=0.578 mol0.577 mol:0.577 mol0.577 molCoSO4:H2O≈1:1$

Therefore, the water of hydration for the compound $CoSO4⋅XH2O$ is $1$ and the chemical formula of the compound is $CoSO4⋅H2O$ .

Conclusion

The water of hydration for the compound $CoSO4⋅H2O$ is to $1$ .

Interpretation Introduction

(d)

Interpretation:

The water of hydration for the compound $CrI3⋅XH2O$ is to be calculated which contains $27.2%$ water. The chemical formula of the compound $CrI3⋅XH2O$ is to be stated.

Concept introduction:

The water of crystallization is the number of water molecules present in crystals compounds. The water of crystallization is also known as the water of hydration. The water molecules present in the crystal helps the crystal to impart color. These water molecules can be easily removed from the crystal by heating them.

Expert Solution

Answer to Problem 78E

The water of hydration for the compound $CrI3⋅XH2O$ is $9$ and the chemical formula of the compound is $CrI3⋅9H2O$ .

Explanation of Solution

The compound $CrI3⋅XH2O$ contains $27.2%$ water. Therefore, $100 g$ of the compound will have $27.2 g$ of water in it.

The mass of $CrI3$ unit in $100 g$ of the compound is calculated as shown below.

$mCrI3=100 g−27.2 g=72.8 g$

The molar mass of water is $18.02 g/mol$ .

The molar mass of $CrI3$ is $432.7095 g/mol$ .

The number of moles of a substance is given by the expression as shown below.

$n=mM$ …(1)

Where,

• $m$ is the mass of the substance.

• $M$ is the molar mass of the substance.

Substitute the values of mass and molar mass of water in the equation (1).

$n=27.2 g18.02 g/mol=1.51 mol$

Substitute the values of mass and molar mass of $CrI3$ water in the equation (1).

$n=72.8 g432.7095 g/mol=0.168 mol$

The molar ratio of $CrI3:H2O$ can be obtained by dividing the number of moles with the lowest number of mole that is $0.168 mol$ .

$CrI3:H2O=0.168 mol0.168 mol:1.51 mol0.168 molCrI3:H2O=1:8.99CrI3:H2O≈1:9$

Therefore, the water of hydration for the compound $CrI3⋅XH2O$ is $9$ and the chemical formula of the compound is $CrI3⋅9H2O$ .

Conclusion

The water of hydration for the compound $CrI3⋅9H2O$ is to $9$ .

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Answer 3

Question

Chapter 11, Problem 78E

Interpretation Introduction

(a)

Interpretation:

The water of hydration for the compound $NiCl2⋅XH2O$ is to be calculated which contains $21.7%$ water. The chemical formula of the compound $NiCl2⋅XH2O$ is to be stated.

Concept introduction:

The water of crystallization is the number of water molecules present in crystals compounds. The water of crystallization is also known as water of hydration. The water molecules present in the crystal helps the crystal to impart color. These water molecules can be easily removed from the crystal by heating them.

Expert Solution

Answer to Problem 78E

The water of hydration for the compound $NiCl2⋅XH2O$ is $2$ and the chemical formula of the compound is $NiCl2⋅2H2O$ .

Explanation of Solution

The compound $NiCl2⋅XH2O$ contains $21.7%$ water. Therefore, $100 g$ of the compound will have $21.7 g$ of water in it.

The mass of $NiCl2$ unit in $100 g$ of the compound is calculated as shown below.

$mNiCl2=100 g−21.7 g=78.3 g$

The molar mass of water is $18.02 g/mol$ .

The molar mass of $NiCl2$ is $129.5994 g/mol$ .

The number of moles of a substance is given by the expression as shown below.

$n=mM$ …(1)

Where,

• $m$ is the mass of the substance.

• $M$ is the molar mass of the substance.

Substitute the values of mass and molar mass of water in the equation (1).

$n=21.7 g18.02 g/mol=1.2042 mol$

Substitute the values of mass and molar mass of $NiCl2$ in the equation (1).

$n=78.3 g129.5994 g/mol=0.6019 mol$

The molar ratio of $NiCl2:H2O$ can be obtained by dividing the number of moles with the lowest number of mole that is $0.6019 mol$ .

$NiCl2:H2O=0.6019 mol0.6019 mol:1.2042 mol0.6019 molNiCl2:H2O=1:2.001NiCl2:H2O≈1:2$

Therefore, the water of hydration for the compound $NiCl2⋅XH2O$ is $2$ and the chemical formula of the compound is $NiCl2⋅2H2O$ .

Conclusion

The water of hydration for the compound $NiCl2⋅2H2O$ is to $2$ .

Interpretation Introduction

(b)

Interpretation:

The water of hydration for the compound $Ni(NO3)2⋅XH2O$ is to be calculated which contains $37.2%$ water. The chemical formula of the compound $Ni(NO3)2⋅XH2O$ is to be stated.

Concept introduction:

The water of crystallization is the number of water molecules present in crystals compounds. The water of crystallization is also known as the water of hydration. The water molecules present in the crystal helps the crystal to impart color. These water molecules can be easily removed from the crystal by heating them.

Expert Solution

Answer to Problem 78E

The water of hydration for the compound $Ni(NO3)2⋅XH2O$ is $6$ and the chemcial formula of the compound is $Ni(NO3)2⋅6H2O$ .

Explanation of Solution

The compound $Ni(NO3)2⋅XH2O$ contains $37.2%$ water. Therefore, $100 g$ of the compound will have $37.2 g$ of water in it.

The mass of $Ni(NO3)2$ unit in $100 g$ of the compound is calculated as shown below.

$mNi(NO3)2=100 g−37.2 g=62.8 g$

The molar mass of water is $18.02 g/mol$ .

The molar mass of $Ni(NO3)2$ is $182.7032 g/mol$ .

The number of moles of a substance is given by the expression as shown below.

$n=mM$ … (1)

Where,

• $m$ is the mass of the substance.

• $M$ is the molar mass of the substance.

Substitute the values of mass and molar mass of water in the equation (1).

$n=37.2 g18.02 g/mol=2.064 mol$

Substitute the values of mass and molar mass of $Ni(NO3)2$ in the equation (1).

$n=62.8 g182.7032 g/mol=0.344 mol$

The molar ratio of $Ni(NO3)2:H2O$ can be obtained by dividing the number of moles with the lowest number of mole that is $0.344 mol$ .

$Ni(NO3)2:H2O=0.344 mol0.344 mol:2.064 mol0.344 molNi(NO3)2:H2O=1:6$

Therefore, the water of hydration for the compound $Ni(NO3)2⋅XH2O$ is $6$ and the chemcial formula of the compound is $Ni(NO3)2⋅6H2O$ .

Conclusion

The water of hydration for the compound $Ni(NO3)2⋅6H2O$ is to $6$ .

Interpretation Introduction

(c)

Interpretation:

The water of hydration for the compound $CoSO4⋅XH2O$ is to be calculated which contains $30.5%$ water. The chemical formula of the compound $CoSO4⋅XH2O$ is to be stated.

Concept introduction:

The water of crystallization is the number of water molecules present in crystals compounds. The water of crystallization is also known as the water of hydration. The water molecules present in the crystal helps the crystal to impart color. These water molecules can be easily removed from the crystal by heating them.

Expert Solution

Answer to Problem 78E

The water of hydration for the compound $CoSO4⋅XH2O$ is $1$ and the chemical formula of the compound is $CoSO4⋅H2O$ .

Explanation of Solution

The compound $CoSO4⋅XH2O$ contains $10.4%$ water. Therefore, $100 g$ of the compound will have $10.4 g$ of water in it.

The mass of $CoSO4$ unit in $100 g$ of the compound is calculated as shown below.

$mCoSO4=100 g−10.4 g=89.6 g$

The molar mass of water is $18.02 g/mol$ .

The molar mass of $CoSO4$ is $154.9958 g/mol$ .

The number of moles of a substance is given by the expression as shown below.

$n=mM$ …(1)

Where,

• $m$ is the mass of the substance.

• $M$ is the molar mass of the substance.

Substitute the values of mass and molar mass of water in the equation (1).

$n=10.4 g18.02 g/mol=0.577 mol$

Substitute the values of mass and molar mass of $CoSO4$ in the equation (1).

$n=89.6 g154.9958 g/mol=0.578 mol$

The molar ratio of $CoSO4:H2O$ can be obtained by dividing the number of moles with the lowest number of mole that is $0.577 mol$ .

$CoSO4:H2O=0.578 mol0.577 mol:0.577 mol0.577 molCoSO4:H2O≈1:1$

Therefore, the water of hydration for the compound $CoSO4⋅XH2O$ is $1$ and the chemical formula of the compound is $CoSO4⋅H2O$ .

Conclusion

The water of hydration for the compound $CoSO4⋅H2O$ is to $1$ .

Interpretation Introduction

(d)

Interpretation:

The water of hydration for the compound $CrI3⋅XH2O$ is to be calculated which contains $27.2%$ water. The chemical formula of the compound $CrI3⋅XH2O$ is to be stated.

Concept introduction:

The water of crystallization is the number of water molecules present in crystals compounds. The water of crystallization is also known as the water of hydration. The water molecules present in the crystal helps the crystal to impart color. These water molecules can be easily removed from the crystal by heating them.

Expert Solution

Answer to Problem 78E

The water of hydration for the compound $CrI3⋅XH2O$ is $9$ and the chemical formula of the compound is $CrI3⋅9H2O$ .

Explanation of Solution

The compound $CrI3⋅XH2O$ contains $27.2%$ water. Therefore, $100 g$ of the compound will have $27.2 g$ of water in it.

The mass of $CrI3$ unit in $100 g$ of the compound is calculated as shown below.

$mCrI3=100 g−27.2 g=72.8 g$

The molar mass of water is $18.02 g/mol$ .

The molar mass of $CrI3$ is $432.7095 g/mol$ .

The number of moles of a substance is given by the expression as shown below.

$n=mM$ …(1)

Where,

• $m$ is the mass of the substance.

• $M$ is the molar mass of the substance.

Substitute the values of mass and molar mass of water in the equation (1).

$n=27.2 g18.02 g/mol=1.51 mol$

Substitute the values of mass and molar mass of $CrI3$ water in the equation (1).

$n=72.8 g432.7095 g/mol=0.168 mol$

The molar ratio of $CrI3:H2O$ can be obtained by dividing the number of moles with the lowest number of mole that is $0.168 mol$ .

$CrI3:H2O=0.168 mol0.168 mol:1.51 mol0.168 molCrI3:H2O=1:8.99CrI3:H2O≈1:9$

Therefore, the water of hydration for the compound $CrI3⋅XH2O$ is $9$ and the chemical formula of the compound is $CrI3⋅9H2O$ .

Conclusion

The water of hydration for the compound $CrI3⋅9H2O$ is to $9$ .

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Answer 4

Question

Chapter 11, Problem 78E

Interpretation Introduction

(a)

Interpretation:

The water of hydration for the compound $NiCl2⋅XH2O$ is to be calculated which contains $21.7%$ water. The chemical formula of the compound $NiCl2⋅XH2O$ is to be stated.

Concept introduction:

The water of crystallization is the number of water molecules present in crystals compounds. The water of crystallization is also known as water of hydration. The water molecules present in the crystal helps the crystal to impart color. These water molecules can be easily removed from the crystal by heating them.

Expert Solution

Answer to Problem 78E

The water of hydration for the compound $NiCl2⋅XH2O$ is $2$ and the chemical formula of the compound is $NiCl2⋅2H2O$ .

Explanation of Solution

The compound $NiCl2⋅XH2O$ contains $21.7%$ water. Therefore, $100 g$ of the compound will have $21.7 g$ of water in it.

The mass of $NiCl2$ unit in $100 g$ of the compound is calculated as shown below.

$mNiCl2=100 g−21.7 g=78.3 g$

The molar mass of water is $18.02 g/mol$ .

The molar mass of $NiCl2$ is $129.5994 g/mol$ .

The number of moles of a substance is given by the expression as shown below.

$n=mM$ …(1)

Where,

• $m$ is the mass of the substance.

• $M$ is the molar mass of the substance.

Substitute the values of mass and molar mass of water in the equation (1).

$n=21.7 g18.02 g/mol=1.2042 mol$

Substitute the values of mass and molar mass of $NiCl2$ in the equation (1).

$n=78.3 g129.5994 g/mol=0.6019 mol$

The molar ratio of $NiCl2:H2O$ can be obtained by dividing the number of moles with the lowest number of mole that is $0.6019 mol$ .

$NiCl2:H2O=0.6019 mol0.6019 mol:1.2042 mol0.6019 molNiCl2:H2O=1:2.001NiCl2:H2O≈1:2$

Therefore, the water of hydration for the compound $NiCl2⋅XH2O$ is $2$ and the chemical formula of the compound is $NiCl2⋅2H2O$ .

Conclusion

The water of hydration for the compound $NiCl2⋅2H2O$ is to $2$ .

Interpretation Introduction

(b)

Interpretation:

The water of hydration for the compound $Ni(NO3)2⋅XH2O$ is to be calculated which contains $37.2%$ water. The chemical formula of the compound $Ni(NO3)2⋅XH2O$ is to be stated.

Concept introduction:

The water of crystallization is the number of water molecules present in crystals compounds. The water of crystallization is also known as the water of hydration. The water molecules present in the crystal helps the crystal to impart color. These water molecules can be easily removed from the crystal by heating them.

Expert Solution

Answer to Problem 78E

The water of hydration for the compound $Ni(NO3)2⋅XH2O$ is $6$ and the chemcial formula of the compound is $Ni(NO3)2⋅6H2O$ .

Explanation of Solution

The compound $Ni(NO3)2⋅XH2O$ contains $37.2%$ water. Therefore, $100 g$ of the compound will have $37.2 g$ of water in it.

The mass of $Ni(NO3)2$ unit in $100 g$ of the compound is calculated as shown below.

$mNi(NO3)2=100 g−37.2 g=62.8 g$

The molar mass of water is $18.02 g/mol$ .

The molar mass of $Ni(NO3)2$ is $182.7032 g/mol$ .

The number of moles of a substance is given by the expression as shown below.

$n=mM$ … (1)

Where,

• $m$ is the mass of the substance.

• $M$ is the molar mass of the substance.

Substitute the values of mass and molar mass of water in the equation (1).

$n=37.2 g18.02 g/mol=2.064 mol$

Substitute the values of mass and molar mass of $Ni(NO3)2$ in the equation (1).

$n=62.8 g182.7032 g/mol=0.344 mol$

The molar ratio of $Ni(NO3)2:H2O$ can be obtained by dividing the number of moles with the lowest number of mole that is $0.344 mol$ .

$Ni(NO3)2:H2O=0.344 mol0.344 mol:2.064 mol0.344 molNi(NO3)2:H2O=1:6$

Therefore, the water of hydration for the compound $Ni(NO3)2⋅XH2O$ is $6$ and the chemcial formula of the compound is $Ni(NO3)2⋅6H2O$ .

Conclusion

The water of hydration for the compound $Ni(NO3)2⋅6H2O$ is to $6$ .

Interpretation Introduction

(c)

Interpretation:

The water of hydration for the compound $CoSO4⋅XH2O$ is to be calculated which contains $30.5%$ water. The chemical formula of the compound $CoSO4⋅XH2O$ is to be stated.

Concept introduction:

The water of crystallization is the number of water molecules present in crystals compounds. The water of crystallization is also known as the water of hydration. The water molecules present in the crystal helps the crystal to impart color. These water molecules can be easily removed from the crystal by heating them.

Expert Solution

Answer to Problem 78E

The water of hydration for the compound $CoSO4⋅XH2O$ is $1$ and the chemical formula of the compound is $CoSO4⋅H2O$ .

Explanation of Solution

The compound $CoSO4⋅XH2O$ contains $10.4%$ water. Therefore, $100 g$ of the compound will have $10.4 g$ of water in it.

The mass of $CoSO4$ unit in $100 g$ of the compound is calculated as shown below.

$mCoSO4=100 g−10.4 g=89.6 g$

The molar mass of water is $18.02 g/mol$ .

The molar mass of $CoSO4$ is $154.9958 g/mol$ .

The number of moles of a substance is given by the expression as shown below.

$n=mM$ …(1)

Where,

• $m$ is the mass of the substance.

• $M$ is the molar mass of the substance.

Substitute the values of mass and molar mass of water in the equation (1).

$n=10.4 g18.02 g/mol=0.577 mol$

Substitute the values of mass and molar mass of $CoSO4$ in the equation (1).

$n=89.6 g154.9958 g/mol=0.578 mol$

The molar ratio of $CoSO4:H2O$ can be obtained by dividing the number of moles with the lowest number of mole that is $0.577 mol$ .

$CoSO4:H2O=0.578 mol0.577 mol:0.577 mol0.577 molCoSO4:H2O≈1:1$

Therefore, the water of hydration for the compound $CoSO4⋅XH2O$ is $1$ and the chemical formula of the compound is $CoSO4⋅H2O$ .

Conclusion

The water of hydration for the compound $CoSO4⋅H2O$ is to $1$ .

Interpretation Introduction

(d)

Interpretation:

The water of hydration for the compound $CrI3⋅XH2O$ is to be calculated which contains $27.2%$ water. The chemical formula of the compound $CrI3⋅XH2O$ is to be stated.

Concept introduction:

The water of crystallization is the number of water molecules present in crystals compounds. The water of crystallization is also known as the water of hydration. The water molecules present in the crystal helps the crystal to impart color. These water molecules can be easily removed from the crystal by heating them.

Expert Solution

Answer to Problem 78E

The water of hydration for the compound $CrI3⋅XH2O$ is $9$ and the chemical formula of the compound is $CrI3⋅9H2O$ .

Explanation of Solution

The compound $CrI3⋅XH2O$ contains $27.2%$ water. Therefore, $100 g$ of the compound will have $27.2 g$ of water in it.

The mass of $CrI3$ unit in $100 g$ of the compound is calculated as shown below.

$mCrI3=100 g−27.2 g=72.8 g$

The molar mass of water is $18.02 g/mol$ .

The molar mass of $CrI3$ is $432.7095 g/mol$ .

The number of moles of a substance is given by the expression as shown below.

$n=mM$ …(1)

Where,

• $m$ is the mass of the substance.

• $M$ is the molar mass of the substance.

Substitute the values of mass and molar mass of water in the equation (1).

$n=27.2 g18.02 g/mol=1.51 mol$

Substitute the values of mass and molar mass of $CrI3$ water in the equation (1).

$n=72.8 g432.7095 g/mol=0.168 mol$

The molar ratio of $CrI3:H2O$ can be obtained by dividing the number of moles with the lowest number of mole that is $0.168 mol$ .

$CrI3:H2O=0.168 mol0.168 mol:1.51 mol0.168 molCrI3:H2O=1:8.99CrI3:H2O≈1:9$

Therefore, the water of hydration for the compound $CrI3⋅XH2O$ is $9$ and the chemical formula of the compound is $CrI3⋅9H2O$ .

Conclusion

The water of hydration for the compound $CrI3⋅9H2O$ is to $9$ .

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Answer 5

Chapter 11, Problem 78E

Interpretation Introduction

(a)

Interpretation:

The water of hydration for the compound $NiCl2⋅XH2O$ is to be calculated which contains $21.7%$ water. The chemical formula of the compound $NiCl2⋅XH2O$ is to be stated.

Concept introduction:

The water of crystallization is the number of water molecules present in crystals compounds. The water of crystallization is also known as water of hydration. The water molecules present in the crystal helps the crystal to impart color. These water molecules can be easily removed from the crystal by heating them.

Expert Solution

Answer to Problem 78E

The water of hydration for the compound $NiCl2⋅XH2O$ is $2$ and the chemical formula of the compound is $NiCl2⋅2H2O$ .

Explanation of Solution

The compound $NiCl2⋅XH2O$ contains $21.7%$ water. Therefore, $100 g$ of the compound will have $21.7 g$ of water in it.

The mass of $NiCl2$ unit in $100 g$ of the compound is calculated as shown below.

$mNiCl2=100 g−21.7 g=78.3 g$

The molar mass of water is $18.02 g/mol$ .

The molar mass of $NiCl2$ is $129.5994 g/mol$ .

The number of moles of a substance is given by the expression as shown below.

$n=mM$ …(1)

Where,

• $m$ is the mass of the substance.

• $M$ is the molar mass of the substance.

Substitute the values of mass and molar mass of water in the equation (1).

$n=21.7 g18.02 g/mol=1.2042 mol$

Substitute the values of mass and molar mass of $NiCl2$ in the equation (1).

$n=78.3 g129.5994 g/mol=0.6019 mol$

The molar ratio of $NiCl2:H2O$ can be obtained by dividing the number of moles with the lowest number of mole that is $0.6019 mol$ .

$NiCl2:H2O=0.6019 mol0.6019 mol:1.2042 mol0.6019 molNiCl2:H2O=1:2.001NiCl2:H2O≈1:2$

Therefore, the water of hydration for the compound $NiCl2⋅XH2O$ is $2$ and the chemical formula of the compound is $NiCl2⋅2H2O$ .

Conclusion

The water of hydration for the compound $NiCl2⋅2H2O$ is to $2$ .

Interpretation Introduction

(b)

Interpretation:

The water of hydration for the compound $Ni(NO3)2⋅XH2O$ is to be calculated which contains $37.2%$ water. The chemical formula of the compound $Ni(NO3)2⋅XH2O$ is to be stated.

Concept introduction:

The water of crystallization is the number of water molecules present in crystals compounds. The water of crystallization is also known as the water of hydration. The water molecules present in the crystal helps the crystal to impart color. These water molecules can be easily removed from the crystal by heating them.

Expert Solution

Answer to Problem 78E

The water of hydration for the compound $Ni(NO3)2⋅XH2O$ is $6$ and the chemcial formula of the compound is $Ni(NO3)2⋅6H2O$ .

Explanation of Solution

The compound $Ni(NO3)2⋅XH2O$ contains $37.2%$ water. Therefore, $100 g$ of the compound will have $37.2 g$ of water in it.

The mass of $Ni(NO3)2$ unit in $100 g$ of the compound is calculated as shown below.

$mNi(NO3)2=100 g−37.2 g=62.8 g$

The molar mass of water is $18.02 g/mol$ .

The molar mass of $Ni(NO3)2$ is $182.7032 g/mol$ .

The number of moles of a substance is given by the expression as shown below.

$n=mM$ … (1)

Where,

• $m$ is the mass of the substance.

• $M$ is the molar mass of the substance.

Substitute the values of mass and molar mass of water in the equation (1).

$n=37.2 g18.02 g/mol=2.064 mol$

Substitute the values of mass and molar mass of $Ni(NO3)2$ in the equation (1).

$n=62.8 g182.7032 g/mol=0.344 mol$

The molar ratio of $Ni(NO3)2:H2O$ can be obtained by dividing the number of moles with the lowest number of mole that is $0.344 mol$ .

$Ni(NO3)2:H2O=0.344 mol0.344 mol:2.064 mol0.344 molNi(NO3)2:H2O=1:6$

Therefore, the water of hydration for the compound $Ni(NO3)2⋅XH2O$ is $6$ and the chemcial formula of the compound is $Ni(NO3)2⋅6H2O$ .

Conclusion

The water of hydration for the compound $Ni(NO3)2⋅6H2O$ is to $6$ .

Interpretation Introduction

(c)

Interpretation:

The water of hydration for the compound $CoSO4⋅XH2O$ is to be calculated which contains $30.5%$ water. The chemical formula of the compound $CoSO4⋅XH2O$ is to be stated.

Concept introduction:

The water of crystallization is the number of water molecules present in crystals compounds. The water of crystallization is also known as the water of hydration. The water molecules present in the crystal helps the crystal to impart color. These water molecules can be easily removed from the crystal by heating them.

Expert Solution

Answer to Problem 78E

The water of hydration for the compound $CoSO4⋅XH2O$ is $1$ and the chemical formula of the compound is $CoSO4⋅H2O$ .

Explanation of Solution

The compound $CoSO4⋅XH2O$ contains $10.4%$ water. Therefore, $100 g$ of the compound will have $10.4 g$ of water in it.

The mass of $CoSO4$ unit in $100 g$ of the compound is calculated as shown below.

$mCoSO4=100 g−10.4 g=89.6 g$

The molar mass of water is $18.02 g/mol$ .

The molar mass of $CoSO4$ is $154.9958 g/mol$ .

The number of moles of a substance is given by the expression as shown below.

$n=mM$ …(1)

Where,

• $m$ is the mass of the substance.

• $M$ is the molar mass of the substance.

Substitute the values of mass and molar mass of water in the equation (1).

$n=10.4 g18.02 g/mol=0.577 mol$

Substitute the values of mass and molar mass of $CoSO4$ in the equation (1).

$n=89.6 g154.9958 g/mol=0.578 mol$

The molar ratio of $CoSO4:H2O$ can be obtained by dividing the number of moles with the lowest number of mole that is $0.577 mol$ .

$CoSO4:H2O=0.578 mol0.577 mol:0.577 mol0.577 molCoSO4:H2O≈1:1$

Therefore, the water of hydration for the compound $CoSO4⋅XH2O$ is $1$ and the chemical formula of the compound is $CoSO4⋅H2O$ .

Conclusion

The water of hydration for the compound $CoSO4⋅H2O$ is to $1$ .

Interpretation Introduction

(d)

Interpretation:

The water of hydration for the compound $CrI3⋅XH2O$ is to be calculated which contains $27.2%$ water. The chemical formula of the compound $CrI3⋅XH2O$ is to be stated.

Concept introduction:

The water of crystallization is the number of water molecules present in crystals compounds. The water of crystallization is also known as the water of hydration. The water molecules present in the crystal helps the crystal to impart color. These water molecules can be easily removed from the crystal by heating them.

Expert Solution

Answer to Problem 78E

The water of hydration for the compound $CrI3⋅XH2O$ is $9$ and the chemical formula of the compound is $CrI3⋅9H2O$ .

Explanation of Solution

The compound $CrI3⋅XH2O$ contains $27.2%$ water. Therefore, $100 g$ of the compound will have $27.2 g$ of water in it.

The mass of $CrI3$ unit in $100 g$ of the compound is calculated as shown below.

$mCrI3=100 g−27.2 g=72.8 g$

The molar mass of water is $18.02 g/mol$ .

The molar mass of $CrI3$ is $432.7095 g/mol$ .

The number of moles of a substance is given by the expression as shown below.

$n=mM$ …(1)

Where,

• $m$ is the mass of the substance.

• $M$ is the molar mass of the substance.

Substitute the values of mass and molar mass of water in the equation (1).

$n=27.2 g18.02 g/mol=1.51 mol$

Substitute the values of mass and molar mass of $CrI3$ water in the equation (1).

$n=72.8 g432.7095 g/mol=0.168 mol$

The molar ratio of $CrI3:H2O$ can be obtained by dividing the number of moles with the lowest number of mole that is $0.168 mol$ .

$CrI3:H2O=0.168 mol0.168 mol:1.51 mol0.168 molCrI3:H2O=1:8.99CrI3:H2O≈1:9$

Therefore, the water of hydration for the compound $CrI3⋅XH2O$ is $9$ and the chemical formula of the compound is $CrI3⋅9H2O$ .

Conclusion

The water of hydration for the compound $CrI3⋅9H2O$ is to $9$ .

Answer 6

Chapter 11, Problem 78E

Interpretation Introduction

(a)

Interpretation:

The water of hydration for the compound $NiCl2⋅XH2O$ is to be calculated which contains $21.7%$ water. The chemical formula of the compound $NiCl2⋅XH2O$ is to be stated.

Concept introduction:

The water of crystallization is the number of water molecules present in crystals compounds. The water of crystallization is also known as water of hydration. The water molecules present in the crystal helps the crystal to impart color. These water molecules can be easily removed from the crystal by heating them.

Expert Solution

Answer to Problem 78E

The water of hydration for the compound $NiCl2⋅XH2O$ is $2$ and the chemical formula of the compound is $NiCl2⋅2H2O$ .

Explanation of Solution

The compound $NiCl2⋅XH2O$ contains $21.7%$ water. Therefore, $100 g$ of the compound will have $21.7 g$ of water in it.

The mass of $NiCl2$ unit in $100 g$ of the compound is calculated as shown below.

$mNiCl2=100 g−21.7 g=78.3 g$

The molar mass of water is $18.02 g/mol$ .

The molar mass of $NiCl2$ is $129.5994 g/mol$ .

The number of moles of a substance is given by the expression as shown below.

$n=mM$ …(1)

Where,

• $m$ is the mass of the substance.

• $M$ is the molar mass of the substance.

Substitute the values of mass and molar mass of water in the equation (1).

$n=21.7 g18.02 g/mol=1.2042 mol$

Substitute the values of mass and molar mass of $NiCl2$ in the equation (1).

$n=78.3 g129.5994 g/mol=0.6019 mol$

The molar ratio of $NiCl2:H2O$ can be obtained by dividing the number of moles with the lowest number of mole that is $0.6019 mol$ .

$NiCl2:H2O=0.6019 mol0.6019 mol:1.2042 mol0.6019 molNiCl2:H2O=1:2.001NiCl2:H2O≈1:2$

Therefore, the water of hydration for the compound $NiCl2⋅XH2O$ is $2$ and the chemical formula of the compound is $NiCl2⋅2H2O$ .

Conclusion

The water of hydration for the compound $NiCl2⋅2H2O$ is to $2$ .

Answer 7

Chapter 11, Problem 78E

Interpretation Introduction

(a)

Interpretation:

The water of hydration for the compound $NiCl2⋅XH2O$ is to be calculated which contains $21.7%$ water. The chemical formula of the compound $NiCl2⋅XH2O$ is to be stated.

Concept introduction:

The water of crystallization is the number of water molecules present in crystals compounds. The water of crystallization is also known as water of hydration. The water molecules present in the crystal helps the crystal to impart color. These water molecules can be easily removed from the crystal by heating them.

Answer 8

Expert Solution

Answer to Problem 78E

The water of hydration for the compound $NiCl2⋅XH2O$ is $2$ and the chemical formula of the compound is $NiCl2⋅2H2O$ .

Answer 9

Expert Solution

Answer 10

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

The compound $NiCl2⋅XH2O$ contains $21.7%$ water. Therefore, $100 g$ of the compound will have $21.7 g$ of water in it.

The mass of $NiCl2$ unit in $100 g$ of the compound is calculated as shown below.

$mNiCl2=100 g−21.7 g=78.3 g$

The molar mass of water is $18.02 g/mol$ .

The molar mass of $NiCl2$ is $129.5994 g/mol$ .

The number of moles of a substance is given by the expression as shown below.

$n=mM$ …(1)

Where,

• $m$ is the mass of the substance.

• $M$ is the molar mass of the substance.

Substitute the values of mass and molar mass of water in the equation (1).

$n=21.7 g18.02 g/mol=1.2042 mol$

Substitute the values of mass and molar mass of $NiCl2$ in the equation (1).

$n=78.3 g129.5994 g/mol=0.6019 mol$

The molar ratio of $NiCl2:H2O$ can be obtained by dividing the number of moles with the lowest number of mole that is $0.6019 mol$ .

$NiCl2:H2O=0.6019 mol0.6019 mol:1.2042 mol0.6019 molNiCl2:H2O=1:2.001NiCl2:H2O≈1:2$

Therefore, the water of hydration for the compound $NiCl2⋅XH2O$ is $2$ and the chemical formula of the compound is $NiCl2⋅2H2O$ .

Answer 13

Conclusion

The water of hydration for the compound $NiCl2⋅2H2O$ is to $2$ .

Answer 14

Interpretation Introduction

(b)

Interpretation:

The water of hydration for the compound $Ni(NO3)2⋅XH2O$ is to be calculated which contains $37.2%$ water. The chemical formula of the compound $Ni(NO3)2⋅XH2O$ is to be stated.

Concept introduction:

The water of crystallization is the number of water molecules present in crystals compounds. The water of crystallization is also known as the water of hydration. The water molecules present in the crystal helps the crystal to impart color. These water molecules can be easily removed from the crystal by heating them.

Expert Solution

Answer to Problem 78E

The water of hydration for the compound $Ni(NO3)2⋅XH2O$ is $6$ and the chemcial formula of the compound is $Ni(NO3)2⋅6H2O$ .

Explanation of Solution

The compound $Ni(NO3)2⋅XH2O$ contains $37.2%$ water. Therefore, $100 g$ of the compound will have $37.2 g$ of water in it.

The mass of $Ni(NO3)2$ unit in $100 g$ of the compound is calculated as shown below.

$mNi(NO3)2=100 g−37.2 g=62.8 g$

The molar mass of water is $18.02 g/mol$ .

The molar mass of $Ni(NO3)2$ is $182.7032 g/mol$ .

The number of moles of a substance is given by the expression as shown below.

$n=mM$ … (1)

Where,

• $m$ is the mass of the substance.

• $M$ is the molar mass of the substance.

Substitute the values of mass and molar mass of water in the equation (1).

$n=37.2 g18.02 g/mol=2.064 mol$

Substitute the values of mass and molar mass of $Ni(NO3)2$ in the equation (1).

$n=62.8 g182.7032 g/mol=0.344 mol$

The molar ratio of $Ni(NO3)2:H2O$ can be obtained by dividing the number of moles with the lowest number of mole that is $0.344 mol$ .

$Ni(NO3)2:H2O=0.344 mol0.344 mol:2.064 mol0.344 molNi(NO3)2:H2O=1:6$

Therefore, the water of hydration for the compound $Ni(NO3)2⋅XH2O$ is $6$ and the chemcial formula of the compound is $Ni(NO3)2⋅6H2O$ .

Conclusion

The water of hydration for the compound $Ni(NO3)2⋅6H2O$ is to $6$ .

Answer 15

Interpretation Introduction

(b)

Interpretation:

The water of hydration for the compound $Ni(NO3)2⋅XH2O$ is to be calculated which contains $37.2%$ water. The chemical formula of the compound $Ni(NO3)2⋅XH2O$ is to be stated.

Concept introduction:

The water of crystallization is the number of water molecules present in crystals compounds. The water of crystallization is also known as the water of hydration. The water molecules present in the crystal helps the crystal to impart color. These water molecules can be easily removed from the crystal by heating them.

Answer 16

Expert Solution

Answer to Problem 78E

The water of hydration for the compound $Ni(NO3)2⋅XH2O$ is $6$ and the chemcial formula of the compound is $Ni(NO3)2⋅6H2O$ .

Answer 17

Expert Solution

Answer 18

Expert Solution

Answer 19

Expert Solution

Answer 20

Explanation of Solution

The compound $Ni(NO3)2⋅XH2O$ contains $37.2%$ water. Therefore, $100 g$ of the compound will have $37.2 g$ of water in it.

The mass of $Ni(NO3)2$ unit in $100 g$ of the compound is calculated as shown below.

$mNi(NO3)2=100 g−37.2 g=62.8 g$

The molar mass of water is $18.02 g/mol$ .

The molar mass of $Ni(NO3)2$ is $182.7032 g/mol$ .

The number of moles of a substance is given by the expression as shown below.

$n=mM$ … (1)

Where,

• $m$ is the mass of the substance.

• $M$ is the molar mass of the substance.

Substitute the values of mass and molar mass of water in the equation (1).

$n=37.2 g18.02 g/mol=2.064 mol$

Substitute the values of mass and molar mass of $Ni(NO3)2$ in the equation (1).

$n=62.8 g182.7032 g/mol=0.344 mol$

The molar ratio of $Ni(NO3)2:H2O$ can be obtained by dividing the number of moles with the lowest number of mole that is $0.344 mol$ .

$Ni(NO3)2:H2O=0.344 mol0.344 mol:2.064 mol0.344 molNi(NO3)2:H2O=1:6$

Therefore, the water of hydration for the compound $Ni(NO3)2⋅XH2O$ is $6$ and the chemcial formula of the compound is $Ni(NO3)2⋅6H2O$ .

Answer 21

Conclusion

The water of hydration for the compound $Ni(NO3)2⋅6H2O$ is to $6$ .

Answer 22

Interpretation Introduction

(c)

Interpretation:

The water of hydration for the compound $CoSO4⋅XH2O$ is to be calculated which contains $30.5%$ water. The chemical formula of the compound $CoSO4⋅XH2O$ is to be stated.

Concept introduction:

The water of crystallization is the number of water molecules present in crystals compounds. The water of crystallization is also known as the water of hydration. The water molecules present in the crystal helps the crystal to impart color. These water molecules can be easily removed from the crystal by heating them.

Expert Solution

Answer to Problem 78E

The water of hydration for the compound $CoSO4⋅XH2O$ is $1$ and the chemical formula of the compound is $CoSO4⋅H2O$ .

Explanation of Solution

The compound $CoSO4⋅XH2O$ contains $10.4%$ water. Therefore, $100 g$ of the compound will have $10.4 g$ of water in it.

The mass of $CoSO4$ unit in $100 g$ of the compound is calculated as shown below.

$mCoSO4=100 g−10.4 g=89.6 g$

The molar mass of water is $18.02 g/mol$ .

The molar mass of $CoSO4$ is $154.9958 g/mol$ .

The number of moles of a substance is given by the expression as shown below.

$n=mM$ …(1)

Where,

• $m$ is the mass of the substance.

• $M$ is the molar mass of the substance.

Substitute the values of mass and molar mass of water in the equation (1).

$n=10.4 g18.02 g/mol=0.577 mol$

Substitute the values of mass and molar mass of $CoSO4$ in the equation (1).

$n=89.6 g154.9958 g/mol=0.578 mol$

The molar ratio of $CoSO4:H2O$ can be obtained by dividing the number of moles with the lowest number of mole that is $0.577 mol$ .

$CoSO4:H2O=0.578 mol0.577 mol:0.577 mol0.577 molCoSO4:H2O≈1:1$

Therefore, the water of hydration for the compound $CoSO4⋅XH2O$ is $1$ and the chemical formula of the compound is $CoSO4⋅H2O$ .

Conclusion

The water of hydration for the compound $CoSO4⋅H2O$ is to $1$ .

Answer 23

Interpretation Introduction

(c)

Interpretation:

The water of hydration for the compound $CoSO4⋅XH2O$ is to be calculated which contains $30.5%$ water. The chemical formula of the compound $CoSO4⋅XH2O$ is to be stated.

Concept introduction:

The water of crystallization is the number of water molecules present in crystals compounds. The water of crystallization is also known as the water of hydration. The water molecules present in the crystal helps the crystal to impart color. These water molecules can be easily removed from the crystal by heating them.

Answer 24

Expert Solution

Answer to Problem 78E

The water of hydration for the compound $CoSO4⋅XH2O$ is $1$ and the chemical formula of the compound is $CoSO4⋅H2O$ .

Answer 25

Expert Solution

Answer 26

Expert Solution

Answer 27

Expert Solution

Answer 28

Explanation of Solution

The compound $CoSO4⋅XH2O$ contains $10.4%$ water. Therefore, $100 g$ of the compound will have $10.4 g$ of water in it.

The mass of $CoSO4$ unit in $100 g$ of the compound is calculated as shown below.

$mCoSO4=100 g−10.4 g=89.6 g$

The molar mass of water is $18.02 g/mol$ .

The molar mass of $CoSO4$ is $154.9958 g/mol$ .

The number of moles of a substance is given by the expression as shown below.

$n=mM$ …(1)

Where,

• $m$ is the mass of the substance.

• $M$ is the molar mass of the substance.

Substitute the values of mass and molar mass of water in the equation (1).

$n=10.4 g18.02 g/mol=0.577 mol$

Substitute the values of mass and molar mass of $CoSO4$ in the equation (1).

$n=89.6 g154.9958 g/mol=0.578 mol$

The molar ratio of $CoSO4:H2O$ can be obtained by dividing the number of moles with the lowest number of mole that is $0.577 mol$ .

$CoSO4:H2O=0.578 mol0.577 mol:0.577 mol0.577 molCoSO4:H2O≈1:1$

Therefore, the water of hydration for the compound $CoSO4⋅XH2O$ is $1$ and the chemical formula of the compound is $CoSO4⋅H2O$ .

Answer 29

Conclusion

The water of hydration for the compound $CoSO4⋅H2O$ is to $1$ .

Answer 30

Interpretation Introduction

(d)

Interpretation:

The water of hydration for the compound $CrI3⋅XH2O$ is to be calculated which contains $27.2%$ water. The chemical formula of the compound $CrI3⋅XH2O$ is to be stated.

Concept introduction:

The water of crystallization is the number of water molecules present in crystals compounds. The water of crystallization is also known as the water of hydration. The water molecules present in the crystal helps the crystal to impart color. These water molecules can be easily removed from the crystal by heating them.

Expert Solution

Answer to Problem 78E

The water of hydration for the compound $CrI3⋅XH2O$ is $9$ and the chemical formula of the compound is $CrI3⋅9H2O$ .

Explanation of Solution

The compound $CrI3⋅XH2O$ contains $27.2%$ water. Therefore, $100 g$ of the compound will have $27.2 g$ of water in it.

The mass of $CrI3$ unit in $100 g$ of the compound is calculated as shown below.

$mCrI3=100 g−27.2 g=72.8 g$

The molar mass of water is $18.02 g/mol$ .

The molar mass of $CrI3$ is $432.7095 g/mol$ .

The number of moles of a substance is given by the expression as shown below.

$n=mM$ …(1)

Where,

• $m$ is the mass of the substance.

• $M$ is the molar mass of the substance.

Substitute the values of mass and molar mass of water in the equation (1).

$n=27.2 g18.02 g/mol=1.51 mol$

Substitute the values of mass and molar mass of $CrI3$ water in the equation (1).

$n=72.8 g432.7095 g/mol=0.168 mol$

The molar ratio of $CrI3:H2O$ can be obtained by dividing the number of moles with the lowest number of mole that is $0.168 mol$ .

$CrI3:H2O=0.168 mol0.168 mol:1.51 mol0.168 molCrI3:H2O=1:8.99CrI3:H2O≈1:9$

Therefore, the water of hydration for the compound $CrI3⋅XH2O$ is $9$ and the chemical formula of the compound is $CrI3⋅9H2O$ .

Conclusion

The water of hydration for the compound $CrI3⋅9H2O$ is to $9$ .

Answer 31

Interpretation Introduction

(d)

Interpretation:

The water of hydration for the compound $CrI3⋅XH2O$ is to be calculated which contains $27.2%$ water. The chemical formula of the compound $CrI3⋅XH2O$ is to be stated.

Concept introduction:

The water of crystallization is the number of water molecules present in crystals compounds. The water of crystallization is also known as the water of hydration. The water molecules present in the crystal helps the crystal to impart color. These water molecules can be easily removed from the crystal by heating them.

Answer 32

Expert Solution

Answer to Problem 78E

The water of hydration for the compound $CrI3⋅XH2O$ is $9$ and the chemical formula of the compound is $CrI3⋅9H2O$ .

Answer 33

Expert Solution

Answer 34

Expert Solution

Answer 35

Expert Solution

Answer 36

Explanation of Solution

The compound $CrI3⋅XH2O$ contains $27.2%$ water. Therefore, $100 g$ of the compound will have $27.2 g$ of water in it.

The mass of $CrI3$ unit in $100 g$ of the compound is calculated as shown below.

$mCrI3=100 g−27.2 g=72.8 g$

The molar mass of water is $18.02 g/mol$ .

The molar mass of $CrI3$ is $432.7095 g/mol$ .

The number of moles of a substance is given by the expression as shown below.

$n=mM$ …(1)

Where,

• $m$ is the mass of the substance.

• $M$ is the molar mass of the substance.

Substitute the values of mass and molar mass of water in the equation (1).

$n=27.2 g18.02 g/mol=1.51 mol$

Substitute the values of mass and molar mass of $CrI3$ water in the equation (1).

$n=72.8 g432.7095 g/mol=0.168 mol$

The molar ratio of $CrI3:H2O$ can be obtained by dividing the number of moles with the lowest number of mole that is $0.168 mol$ .

$CrI3:H2O=0.168 mol0.168 mol:1.51 mol0.168 molCrI3:H2O=1:8.99CrI3:H2O≈1:9$

Therefore, the water of hydration for the compound $CrI3⋅XH2O$ is $9$ and the chemical formula of the compound is $CrI3⋅9H2O$ .

Answer 37

Conclusion

The water of hydration for the compound $CrI3⋅9H2O$ is to $9$ .

Answer 38

Ch. 11 - Prob. 1CE Ch. 11 - Prob. 2CE Ch. 11 - Prob. 3CE Ch. 11 - Prob. 4CE Ch. 11 - Prob. 5CE Ch. 11 - Prob. 6CE Ch. 11 - Prob. 7CE Ch. 11 - Prob. 8CE Ch. 11 - Prob. 1KT Ch. 11 - Prob. 2KT

Answer to Problem 78E

Explanation of Solution

Answer to Problem 78E

Explanation of Solution

Answer to Problem 78E

Explanation of Solution

Answer to Problem 78E

Explanation of Solution

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