EP INTRODUCTORY CHEM.-MOD.MASTERINGCHEM
EP INTRODUCTORY CHEM.-MOD.MASTERINGCHEM
8th Edition
ISBN: 9780134554433
Author: CORWIN
Publisher: PEARSON CO
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Chapter 11, Problem 68E
Interpretation Introduction

(a)

Interpretation:

The balanced chemical equation for the reaction between butane and oxygen gas is to be stated.

Concept introduction:

A chemical reaction is a process in which rearrangement of atom or ions takes place between two reacting species. A balanced chemical equation represents an equation in which all the reactants and products are written with their stoichiometric coefficient and physical states. The number of atoms of an element on both sides of the equation is equal.

Expert Solution
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Answer to Problem 68E

The balanced chemical equation for the reaction between butane and oxygen gas is shown below.

2C4H10(g)+14O2(g)spark8CO2(g)+10H2O(g)

Explanation of Solution

Hydrocarbons react in the presence of oxygen to give carbon dioxide and water. This reaction is called combustion reaction. Butane reacts with oxygen to form carbon dioxide and water.

The unbalanced chemical equation for the reaction between butane and oxygen gas is as shown below.

C4H10(g)+O2(g)sparkCO2(g)+H2O(g)

The numbers of atoms of elements on the left side of the reaction are not equal to the right side of the reaction. Therefore, the reaction is unbalanced.

Butane is multiplied by the coefficient two, oxygen gas by thirteen. On the right side, carbon dioxide is multiplied by eight and water is multiplied by ten.

Therefore, the balanced chemical equation for the reaction between butane and oxygen gas is shown below.

2C4H10(g)+14O2(g)spark8CO2(g)+10H2O(g)

The numbers of atoms of each element on the left side of the reaction are equal to the right side of the reaction. Therefore, the reaction is balanced.

Conclusion

The balanced chemical equation for the reaction between butane and oxygen gas has been stated.

Interpretation Introduction

(b)

Interpretation:

The balanced chemical equation for the heating of Co(C2H3O2)24H2O is to be stated.

Concept introduction:

A chemical reaction is a process in which rearrangement of atom or ions takes place between two reacting species. A balanced chemical equation represents an equation in which all the reactants and products are written with their stoichiometric coefficient and physical states. The number of atoms of an element on both sides of the equation is equal.

Expert Solution
Check Mark

Answer to Problem 68E

The balanced chemical equation for the heating of Co(C2H3O2)24H2O is shown below.

Co(C2H3O2)24H2O(s)ΔCo(C2H3O2)2(s)+4H2O(g)

Explanation of Solution

A hydrated salt on heating evaporates water molecules to form anhydrous salt. Therefore, Cobalt acetate tetrahydrate on heating gives anhydrous cobalt acetate and water vapour.

The completed chemical equation of the reaction for the heating of Co(C2H3O2)24H2O is shown below.

Co(C2H3O2)24H2O(s)ΔCo(C2H3O2)2(s)+H2O(g)

The numbers of atoms of elements on the left side of the reaction are not equal to the right side of the reaction. Therefore, the reaction is unbalanced.

Water molecule is multiplied by four for balancing the equation.

Therefore, the balanced chemical equation for the reaction for the heating of hydrated salt of sodium dichromate is shown below.

Co(C2H3O2)24H2O(s)ΔCo(C2H3O2)2(s)+4H2O(g)

The numbers of atoms of each element on the left side of the reaction are equal to the right side of the reaction. Therefore, the reaction is balanced.

Conclusion

The balanced chemical equation of the reaction for heating of Co(C2H3O2)24H2O is stated above.

Interpretation Introduction

(c)

Interpretation:

The balanced chemical equation for the reaction between nitric acid and barium hydroxide is to be stated.

Concept introduction:

A chemical reaction is a process in which rearrangement of atom or ions takes place between two reacting species. A balanced chemical equation represents an equation in which all the reactants and products are written with their stoichiometric coefficient and physical states. The number of atoms of an element on both sides of the equation is equal.

Expert Solution
Check Mark

Answer to Problem 68E

The balanced chemical equation for the reaction between nitric acid and barium hydroxide is shown below.

2HNO3(aq)+Ba(OH)2(aq)Ba(NO3)2(aq)+2H2O(l)

Explanation of Solution

An acid and base reacts to form salt and water. Nitric acid reacts with barium hydroxide to give barium nitrate(salt) and water.

The unbalanced chemical equation for the reaction between nitric acid and barium hydroxide is shown below.

HNO3(aq)+Ba(OH)2(aq)Ba(NO3)2(aq)+H2O(l)

The numbers of atoms of elements on the left side of the reaction are not equal to the right side of the reaction. Therefore, the reaction is unbalanced.

A coefficient of 2 is placed in front of HNO3 a coefficient of 2 is placed in front of H2O to balance the chemical equation.

Therefore, the balanced chemical equation for the reaction between nitric acid and barium hydroxide is shown below.

2HNO3(aq)+Ba(OH)2(aq)Ba(NO3)2(aq)+2H2O(l)

The numbers of atoms of each element on the left side of the reaction are equal to the right side of the reaction. Therefore, the reaction is balanced.

Conclusion

The balanced chemical equation for the reaction between nitric acid and barium hydroxide is stated above.

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Chapter 11 Solutions

EP INTRODUCTORY CHEM.-MOD.MASTERINGCHEM

Ch. 11 - Prob. 3KTCh. 11 - Prob. 4KTCh. 11 - Prob. 5KTCh. 11 - Prob. 6KTCh. 11 - Prob. 7KTCh. 11 - Prob. 8KTCh. 11 - Prob. 9KTCh. 11 - Prob. 10KTCh. 11 - Prob. 11KTCh. 11 - Prob. 12KTCh. 11 - Prob. 13KTCh. 11 - Prob. 14KTCh. 11 - Prob. 15KTCh. 11 - Prob. 16KTCh. 11 - Prob. 17KTCh. 11 - Prob. 18KTCh. 11 - Prob. 19KTCh. 11 - Prob. 20KTCh. 11 - Prob. 21KTCh. 11 - Prob. 22KTCh. 11 - Prob. 23KTCh. 11 - Prob. 24KTCh. 11 - Prob. 25KTCh. 11 - Prob. 26KTCh. 11 - Prob. 1ECh. 11 - Prob. 2ECh. 11 - Prob. 3ECh. 11 - Prob. 4ECh. 11 - Prob. 5ECh. 11 - Prob. 6ECh. 11 - Prob. 7ECh. 11 - Prob. 8ECh. 11 - Prob. 9ECh. 11 - Prob. 10ECh. 11 - Prob. 11ECh. 11 - Prob. 12ECh. 11 - Prob. 13ECh. 11 - Prob. 14ECh. 11 - Prob. 15ECh. 11 - Prob. 16ECh. 11 - Prob. 17ECh. 11 - Prob. 18ECh. 11 - Prob. 19ECh. 11 - Prob. 20ECh. 11 - Prob. 21ECh. 11 - Prob. 22ECh. 11 - Prob. 23ECh. 11 - Prob. 24ECh. 11 - Prob. 25ECh. 11 - Prob. 26ECh. 11 - Prob. 27ECh. 11 - Prob. 28ECh. 11 - Prob. 29ECh. 11 - Prob. 30ECh. 11 - Prob. 31ECh. 11 - Prob. 32ECh. 11 - Prob. 33ECh. 11 - Prob. 34ECh. 11 - Prob. 35ECh. 11 - Prob. 36ECh. 11 - Prob. 37ECh. 11 - Prob. 38ECh. 11 - Prob. 39ECh. 11 - Prob. 40ECh. 11 - Prob. 41ECh. 11 - Prob. 42ECh. 11 - Prob. 43ECh. 11 - Prob. 44ECh. 11 - Prob. 45ECh. 11 - Prob. 46ECh. 11 - Prob. 47ECh. 11 - Prob. 48ECh. 11 - Prob. 49ECh. 11 - Prob. 50ECh. 11 - Prob. 51ECh. 11 - Prob. 52ECh. 11 - Prob. 53ECh. 11 - Prob. 54ECh. 11 - Prob. 55ECh. 11 - Prob. 56ECh. 11 - Prob. 57ECh. 11 - Prob. 58ECh. 11 - Prob. 59ECh. 11 - Prob. 60ECh. 11 - Prob. 61ECh. 11 - Prob. 62ECh. 11 - Prob. 63ECh. 11 - Prob. 64ECh. 11 - Prob. 65ECh. 11 - Prob. 66ECh. 11 - Prob. 67ECh. 11 - Prob. 68ECh. 11 - Prob. 69ECh. 11 - Prob. 70ECh. 11 - Prob. 71ECh. 11 - Prob. 72ECh. 11 - Prob. 73ECh. 11 - Prob. 74ECh. 11 - Prob. 75ECh. 11 - Prob. 76ECh. 11 - Prob. 77ECh. 11 - Prob. 78ECh. 11 - Prob. 79ECh. 11 - Prob. 80ECh. 11 - Prob. 81ECh. 11 - Prob. 82ECh. 11 - Prob. 83ECh. 11 - Prob. 84ECh. 11 - Prob. 85ECh. 11 - Prob. 86ECh. 11 - Prob. 87ECh. 11 - Prob. 88ECh. 11 - Prob. 1STCh. 11 - Prob. 2STCh. 11 - Prob. 3STCh. 11 - Prob. 4STCh. 11 - Prob. 5STCh. 11 - Prob. 6STCh. 11 - Prob. 7STCh. 11 - Prob. 8STCh. 11 - Prob. 9STCh. 11 - Prob. 10STCh. 11 - Prob. 11STCh. 11 - Prob. 12STCh. 11 - Prob. 13STCh. 11 - Prob. 14ST
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