EP INTRODUCTORY CHEM.-MOD.MASTERINGCHEM
8th Edition
ISBN: 9780134554433
Author: CORWIN
Publisher: PEARSON CO
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Chapter 11, Problem 6KT
Interpretation Introduction
Interpretation:
The key term corresponding to the definition “the resistance of a liquid to flow” is to be stated.
Concept introduction:
Viscosity is called the property of a fluid that is “a measure of its resistance to flow”. It is the consequence of a molecular attraction and denotes the internal friction of a moving fluid. A fluid with high viscosity resists motion due to its high molecular interaction. The substances with low intermolecular interaction have lower viscosity.
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Complete the reaction in the drawing area below by adding the major products to the right-hand side.
If there won't be any products, because nothing will happen under these reaction conditions, check the box under the drawing area instead.
Note: if the products contain one or more pairs of enantiomers, don't worry about drawing each enantiomer with dash and wedge bonds. Just draw one molecule
to represent each pair of enantiomers, using line bonds at the chiral center.
More...
No reaction.
my
ㄖˋ
+
1. Na O Me
Click and drag to start
drawing a structure.
2. H
+
Predict the intermediate 1 and final product 2 of this organic reaction:
NaOMe
H+
+
1
2
H
H
work up
You can draw 1 and 2 in any arrangement you like.
Note: if either 1 or 2 consists of a pair of enantiomers, just draw one structure using line bonds instead of 3D (dash and wedge) bonds at the chiral center.
Click and drag to start drawing a structure.
X
$
dm
Predict the major products of this organic reaction:
1. NaH (20°C)
2. CH3Br
?
Some notes:
• Draw only the major product, or products. You can draw them in any arrangement you like.
• Be sure to use wedge and dash bonds where necessary, for example to distinguish between major products that are enantiomers.
• If there are no products, just check the box under the drawing area.
No reaction.
Click and drag to start drawing a structure.
G
Cr
Chapter 11 Solutions
EP INTRODUCTORY CHEM.-MOD.MASTERINGCHEM
Ch. 11 - Prob. 1CECh. 11 - Prob. 2CECh. 11 - Prob. 3CECh. 11 - Prob. 4CECh. 11 - Prob. 5CECh. 11 - Prob. 6CECh. 11 - Prob. 7CECh. 11 - Prob. 8CECh. 11 - Prob. 1KTCh. 11 - Prob. 2KT
Ch. 11 - Prob. 3KTCh. 11 - Prob. 4KTCh. 11 - Prob. 5KTCh. 11 - Prob. 6KTCh. 11 - Prob. 7KTCh. 11 - Prob. 8KTCh. 11 - Prob. 9KTCh. 11 - Prob. 10KTCh. 11 - Prob. 11KTCh. 11 - Prob. 12KTCh. 11 - Prob. 13KTCh. 11 - Prob. 14KTCh. 11 - Prob. 15KTCh. 11 - Prob. 16KTCh. 11 - Prob. 17KTCh. 11 - Prob. 18KTCh. 11 - Prob. 19KTCh. 11 - Prob. 20KTCh. 11 - Prob. 21KTCh. 11 - Prob. 22KTCh. 11 - Prob. 23KTCh. 11 - Prob. 24KTCh. 11 - Prob. 25KTCh. 11 - Prob. 26KTCh. 11 - Prob. 1ECh. 11 - Prob. 2ECh. 11 - Prob. 3ECh. 11 - Prob. 4ECh. 11 - Prob. 5ECh. 11 - Prob. 6ECh. 11 - Prob. 7ECh. 11 - Prob. 8ECh. 11 - Prob. 9ECh. 11 - Prob. 10ECh. 11 - Prob. 11ECh. 11 - Prob. 12ECh. 11 - Prob. 13ECh. 11 - Prob. 14ECh. 11 - Prob. 15ECh. 11 - Prob. 16ECh. 11 - Prob. 17ECh. 11 - Prob. 18ECh. 11 - Prob. 19ECh. 11 - Prob. 20ECh. 11 - Prob. 21ECh. 11 - Prob. 22ECh. 11 - Prob. 23ECh. 11 - Prob. 24ECh. 11 - Prob. 25ECh. 11 - Prob. 26ECh. 11 - Prob. 27ECh. 11 - Prob. 28ECh. 11 - Prob. 29ECh. 11 - Prob. 30ECh. 11 - Prob. 31ECh. 11 - Prob. 32ECh. 11 - Prob. 33ECh. 11 - Prob. 34ECh. 11 - Prob. 35ECh. 11 - Prob. 36ECh. 11 - Prob. 37ECh. 11 - Prob. 38ECh. 11 - Prob. 39ECh. 11 - Prob. 40ECh. 11 - Prob. 41ECh. 11 - Prob. 42ECh. 11 - Prob. 43ECh. 11 - Prob. 44ECh. 11 - Prob. 45ECh. 11 - Prob. 46ECh. 11 - Prob. 47ECh. 11 - Prob. 48ECh. 11 - Prob. 49ECh. 11 - Prob. 50ECh. 11 - Prob. 51ECh. 11 - Prob. 52ECh. 11 - Prob. 53ECh. 11 - Prob. 54ECh. 11 - Prob. 55ECh. 11 - Prob. 56ECh. 11 - Prob. 57ECh. 11 - Prob. 58ECh. 11 - Prob. 59ECh. 11 - Prob. 60ECh. 11 - Prob. 61ECh. 11 - Prob. 62ECh. 11 - Prob. 63ECh. 11 - Prob. 64ECh. 11 - Prob. 65ECh. 11 - Prob. 66ECh. 11 - Prob. 67ECh. 11 - Prob. 68ECh. 11 - Prob. 69ECh. 11 - Prob. 70ECh. 11 - Prob. 71ECh. 11 - Prob. 72ECh. 11 - Prob. 73ECh. 11 - Prob. 74ECh. 11 - Prob. 75ECh. 11 - Prob. 76ECh. 11 - Prob. 77ECh. 11 - Prob. 78ECh. 11 - Prob. 79ECh. 11 - Prob. 80ECh. 11 - Prob. 81ECh. 11 - Prob. 82ECh. 11 - Prob. 83ECh. 11 - Prob. 84ECh. 11 - Prob. 85ECh. 11 - Prob. 86ECh. 11 - Prob. 87ECh. 11 - Prob. 88ECh. 11 - Prob. 1STCh. 11 - Prob. 2STCh. 11 - Prob. 3STCh. 11 - Prob. 4STCh. 11 - Prob. 5STCh. 11 - Prob. 6STCh. 11 - Prob. 7STCh. 11 - Prob. 8STCh. 11 - Prob. 9STCh. 11 - Prob. 10STCh. 11 - Prob. 11STCh. 11 - Prob. 12STCh. 11 - Prob. 13STCh. 11 - Prob. 14ST
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- Predict the major products of this organic reaction: 1. LDA (-78°C) ? 2. Br Some notes: • Draw only the major product, or products. You can draw them in any arrangement you like. . • Be sure to use wedge and dash bonds where necessary, for example to distinguish between major products that are enantiomers. • If there are no products, just check the box under the drawing area. No reaction. Click and drag to start drawing a structure. Xarrow_forwardPlease draw the structuresarrow_forwardDraw the missing intermediates 1 and 2, plus the final product 3, of this synthesis: 0 1. Eto 1. Eto- 1 2 2. MeBr 2. EtBr H3O+ A 3 You can draw the three structures in any arrangement you like. Explanation Check Click and drag to start drawing a structure.arrow_forward
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