
Concept explainers
(a)
The total energy of the earth-satellite system.
(a)

Answer to Problem 60P
The total energy of the earth-satellite system is
Explanation of Solution
Write the expression for the total energy of the earth-satellite system.
Here,
Write the expression for the
Here,
Write the expression for
Here,
Use equation (II) and (III) in (I) to solve for
Conclusion:
Substitute
Therefore, the total energy of the earth-satellite system is
(b)
The magnitude of the
(b)

Answer to Problem 60P
The magnitude of the angular momentum of the satellite is
Explanation of Solution
Write the expression for the angular momentum of the satellite.
Here,
The velocity vector and the position vector are perpendicular to each other at point of the orbit.
Conclusion:
Substitute
Therefore, the magnitude of the angular momentum of the satellite is
(c)
The speed of the satellite at apogee and the distance from the center of the earth.
(c)

Answer to Problem 60P
The speed of the satellite at apogee is
Explanation of Solution
The energy and angular momentum of the earth-satellite system is conserved.
Write the expression for the earth-satellite system at apogee.
Here,
Use equation (V) to solve for
Use equation (VII) in (VI) to solve for
Conclusion:
Substitute
The smaller value of represents the velocity at the apogee while the larger value refers to the velocity at perigee.
Substitute
Therefore, the speed of the satellite at apogee is
(d)
The semi-major axis of the orbit.
(d)

Answer to Problem 60P
The semi-major axis of the orbit is
Explanation of Solution
Write the expression for the major axis.
Use equation (IX) to solve for
Conclusion:
Substitute
Therefore, the semi-major axis of the orbit is
(e)
The period of the revolution around the orbit.
(e)

Answer to Problem 60P
The period of the revolution is
Explanation of Solution
Write the expression for the period of revolution using Kepler law of planetary motion.
Here,
Conclusion:
Substitute
Therefore, the period of the revolution is
Want to see more full solutions like this?
Chapter 11 Solutions
Bundle: Principles of Physics: A Calculus-Based Text, 5th + WebAssign Printed Access Card for Serway/Jewett's Principles of Physics: A Calculus-Based Text, 5th Edition, Multi-Term
- What is the 27 energy absorbed in this endothermic Auclear reaction 2] Al + 'n → 27 Mg + ! H? (The atom mass of "Al is 26.981539u. and that of 11 Mg is 26.984341u) MeVarrow_forwardWhat is the energy released in this nuclear reaction 1 F + "', H-1 O+ He? 19 19 16 (The atomic mass of 1F is 18.998403 u, and that of 20 is 15.9949154) MeV.arrow_forwardWhat is the energy released in this B+ nuclear reaction خالد 2½ Al w/ Mg + ie? (The atomic mass of 11 Al is 23.9999394 and that > of 12 Mg is 23.985041 u) MeV.arrow_forward
- What is the energy released / absorbed in this nuclear reaction 14 N+ & He → » O + ! N? (The atomic mass of 14 N is 14.003074u. 17N+ and that of 10 is 16.9991324). MeVarrow_forwardCan someone help me answer this question thanks.arrow_forwardCan someone help me with this question thanks.arrow_forward
- 4B. Four electrons are located on the corners of a square, one on each corner, with the sides of the square being 25 cm long. a) Draw a sketch of the scenario and use your sketch to b) Determine the total force (magnitude and direction) on one of the electrons from the other three?arrow_forwardPortfolio Problem 3. A ball is thrown vertically upwards with a speed vo from the floor of a room of height h. It hits the ceiling and then returns to the floor, from which it rebounds, managing just to hit the ceiling a second time. Assume that the coefficient of restitution between the ball and the floor, e, is equal to that between the ball and the ceiling. Compute e.arrow_forwardPortfolio Problem 4. Consider two identical springs, each with natural length and spring constant k, attached to a horizontal frame at distance 2l apart. Their free ends are attached to the same particle of mass m, which is hanging under gravity. Let z denote the vertical displacement of the particle from the hori- zontal frame, so that z < 0 when the particle is below the frame, as shown in the figure. The particle has zero horizontal velocity, so that the motion is one dimensional along z. 000000 0 eeeeee (a) Show that the total force acting on the particle is X F-mg k-2kz 1 (1. l k. (b) Find the potential energy U(x, y, z) of the system such that U x = : 0. = O when (c) The particle is pulled down until the springs are each of length 3l, and then released. Find the velocity of the particle when it crosses z = 0.arrow_forward
- In the figure below, a semicircular conductor of radius R = 0.260 m is rotated about the axis AC at a constant rate of 130 rev/min. A uniform magnetic field of magnitude 1.22 T fills the entire region below the axis and is directed out of the page. R Pout (a) Calculate the maximum value of the emf induced between the ends of the conductor. 1.77 v (b) What is the value of the average induced emf for each complete rotation? 0 v (c) How would your answers to parts (a) and (b) change if the magnetic field were allowed to extend a distance R above the axis of rotation? (Select all that apply.) The value in part (a) would increase. The value in part (a) would remain the same. The value in part (a) would decrease. The value in part (b) would increase. The value in part (b) would remain the same. The value in part (b) would decrease. × (d) Sketch the emf versus time when the field is as drawn in the figure. Choose File No file chosen This answer has not been graded yet. (e) Sketch the emf…arrow_forwardPortfolio Problem 2. A particle of mass m slides in a straight line (say along i) on a surface, with initial position x ©0 and initial velocity Vo > 0 at t = 0. The = particle is subject to a constant force F = -mai, with a > 0. While sliding on the surface, the particle is also subject to a friction force v Ff = -m fo = −m fov, with fo > 0, i.e., the friction force has constant magnitude mfo and is always opposed to the motion. We also assume fo 0, and solve it to find v(t) and x(t). How long does it take for the particle to come to a stop? How far does it travel? (b) After coming to a stop, the particle starts sliding backwards with negative velocity. Write the equation of motion in this case, and solve it to find the time at which the particle returns to the original position, x = 0. Show that the final speed at x 0 is smaller than Vo. = Express all your answers in terms of a, fo and Vo.arrow_forward= Portfolio Problem 1. A particle of mass m is dropped (i.e., falls down with zero initial velocity) at time t 0 from height h. If the particle is subject to gravitational acceleration only, i.e., a = −gk, determine its speed as it hits the ground by solving explicitly the expressions for its velocity and position. Next, verify your result using dimensional analysis, assuming that the general relation is of the form v = khag³m, where k is a dimensionless constant.arrow_forward
- Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningClassical Dynamics of Particles and SystemsPhysicsISBN:9780534408961Author:Stephen T. Thornton, Jerry B. MarionPublisher:Cengage LearningCollege PhysicsPhysicsISBN:9781285737027Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning
- University Physics Volume 1PhysicsISBN:9781938168277Author:William Moebs, Samuel J. Ling, Jeff SannyPublisher:OpenStax - Rice UniversityPhysics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage LearningPhysics for Scientists and Engineers, Technology ...PhysicsISBN:9781305116399Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning





