The picture has to be draw for the given explanation. Concept Introduction: Osmotic pressure: Osmosis can be prevented by applying a pressure to the solution. The minimum pressure that stops the osmosis is equal to the osmotic pressure of the solution. Colligative properties of a substance include the depression in the freezing point, elevation of boiling-point and osmotic pressure. These are dependant only on the number present and not based on the solute particles present in an ideal solution. The osmotic pressure can be given by the equation, Π=MRT Here,Π=Osmotic pressure M=Molarity of solution R= Gas law constant T=Temperature
The picture has to be draw for the given explanation. Concept Introduction: Osmotic pressure: Osmosis can be prevented by applying a pressure to the solution. The minimum pressure that stops the osmosis is equal to the osmotic pressure of the solution. Colligative properties of a substance include the depression in the freezing point, elevation of boiling-point and osmotic pressure. These are dependant only on the number present and not based on the solute particles present in an ideal solution. The osmotic pressure can be given by the equation, Π=MRT Here,Π=Osmotic pressure M=Molarity of solution R= Gas law constant T=Temperature
Solution Summary: The author explains that osmosis can be prevented by applying a pressure to the solution.
Interpretation: The picture has to be draw for the given explanation.
Concept Introduction:
Osmotic pressure: Osmosis can be prevented by applying a pressure to the solution. The minimum pressure that stops the osmosis is equal to the osmotic pressure of the solution.
Colligative properties of a substance include the depression in the freezing point, elevation of boiling-point and osmotic pressure. These are dependant only on the number present and not based on the solute particles present in an ideal solution.
The osmotic pressure can be given by the equation,
Fill in the blanks by selecting the appropriate term from below:
For a process that is non-spontaneous and that favors products at equilibrium, we know that a) ΔrG∘ΔrG∘ _________, b) ΔunivSΔunivS _________, c) ΔsysSΔsysS _________, and d) ΔrH∘ΔrH∘ _________.
Highest occupied molecular orbital
Lowest unoccupied molecular orbital
Label all nodes and regions of highest and lowest electron density for both orbitals.
Relative Intensity
Part VI. consider the multi-step reaction below for compounds A, B, and C.
These compounds were subjected to mass spectrometric analysis and
the following spectra for A, B, and C was obtained.
Draw the structure of B and C and match all three compounds
to the correct spectra.
Relative Intensity
Relative Intensity
20
NaоH
0103
Br
(B)
H2504
→ (c)
(A)
100-
MS-NU-0547
80
40
20
31
10
20
100-
MS2016-05353CM
80
60
100
MS-NJ-09-3
80
60
40
20
45
J.L
80
S1
84
M+
absent
राग
135 137
S2
62
164 166
11
S3
25
50
75
100
125
150
175
m/z