ENGINEERING CIRCUIT...(LL)>CUSTOM PKG.<
ENGINEERING CIRCUIT...(LL)>CUSTOM PKG.<
9th Edition
ISBN: 9781260540666
Author: Hayt
Publisher: MCG CUSTOM
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Chapter 11, Problem 24E

(a)

To determine

Find the value of load impedance to draw the maximum average power from the source.

(b)

To determine

Find the maximum average power supplied to the load.

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MY code is experiencing a problem as I want to show both the magnitude ratio on low pass, high pass, and bandbass based on passive filters: Code: % Define frequency range for the plot f = logspace(1, 5, 500); % Frequency range from 10 Hz to 100 kHz w = 2*pi*f; % Angular frequency   % Parameters for the filters (you can modify these) R = 1e3; % Resistance in ohms (1 kOhm) C = 1e-6; % Capacitance in farads (1 uF) L = 10e-3; % Inductance in henries (10 mH)   % Transfer function for Low-pass filter: H_low = 1 / (1 + jωRC) H_low = 1 ./ (1 + 1i*w*R*C);   % Transfer function for High-pass filter: H_high = jωRC / (1 + jωRC) H_high = 1i*w*R*C ./ (1 + 1i*w*R*C);   % Transfer function for Band-pass filter: H_band = jωRC / (1 + jωL/R + jωRC) H_band = 1i*w*R*C ./ (1 + 1i*w*L/R + 1i*w*R*C);   % Plot magnitude responses figure; subplot(3,1,1); semilogx(f, 20*log10(abs(H_low))); % Low-pass filter title('Magnitude Response of Low-pass Filter'); xlabel('Frequency (Hz)'); ylabel('Magnitude (dB)'); grid…
*10. For the network of Fig. 7.83, determine: a. Ip. b. VDS. c. VD. d. Vs. 20 V 2.2 ΚΩ ID -4 V IDSS = 4.5 mA VDS Vp = -5V 0.68 ΚΩ
4. a. Determine VDs for VGS = 0 V and ID = 6 mA using the characteristics of Fig. 6.11. b. Using the results of part (a), calculate the resistance of the JFET for the region ID = 0 to 6 mA for VGS = 0 V. c. Determine VDs for VGS = -1 V and ID = 3 mA. d. Using the results of part (c), calculate the resistance of the JFET for the region ID = 0 to 3 mA for VGS = -1 V. e. Determine VDs for VGS = -2 V and ID = 1.5 mA. f. Using the results of part (e), calculate the resistance of the JFET for the region ID 1.5 mA for VGS = -2 V. g. Defining the result of part (b) as ro, determine the resistance for VGS Eq. (6.1) and compare with the results of part (d). = 0 to = -1 V using h. Repeat part (g) for VGS = -2 V using the same equation, and compare the results with part (f). i. Based on the results of parts (g) and (h), does Eq. (6.1) appear to be a valid approximation?

Chapter 11 Solutions

ENGINEERING CIRCUIT...(LL)>CUSTOM PKG.<

Ch. 11 - Determine the power absorbed at t = 1.5 ms by each...Ch. 11 - Calculate the power absorbed at t = 0, t = 0+, and...Ch. 11 - Three elements are connected in parallel: a 1 k...Ch. 11 - Let is = 4u(t) A in the circuit of Fig. 11.28. (a)...Ch. 11 - Prob. 6ECh. 11 - Assuming no transients are present, calculate the...Ch. 11 - Prob. 8ECh. 11 - Prob. 9ECh. 11 - Prob. 10ECh. 11 - The phasor current I=915mA (corresponding to a...Ch. 11 - A phasor voltage V=10045V (the sinusoid operates...Ch. 11 - Prob. 13ECh. 11 - Prob. 14ECh. 11 - Find the average power for each element in the...Ch. 11 - (a) Calculate the average power absorbed by each...Ch. 11 - Prob. 17ECh. 11 - Prob. 18ECh. 11 - Prob. 19ECh. 11 - The circuit in Fig. 11.36 has a series resistance...Ch. 11 - Prob. 21ECh. 11 - Prob. 22ECh. 11 - Prob. 23ECh. 11 - Prob. 24ECh. 11 - Prob. 25ECh. 11 - Prob. 26ECh. 11 - Prob. 27ECh. 11 - Prob. 28ECh. 11 - Prob. 29ECh. 11 - Prob. 30ECh. 11 - Prob. 31ECh. 11 - Prob. 32ECh. 11 - Prob. 33ECh. 11 - (a) Calculate both the average and rms values of...Ch. 11 - Prob. 35ECh. 11 - FIGURE 11.43 Calculate the power factor of the...Ch. 11 - Prob. 37ECh. 11 - Prob. 38ECh. 11 - Prob. 40ECh. 11 - Prob. 41ECh. 11 - Prob. 42ECh. 11 - Prob. 43ECh. 11 - Compute the complex power S (in polar form) drawn...Ch. 11 - Calculate the apparent power, power factor, and...Ch. 11 - Prob. 46ECh. 11 - Prob. 48ECh. 11 - Prob. 49ECh. 11 - Prob. 50ECh. 11 - Prob. 51ECh. 11 - Prob. 52ECh. 11 - FIGURE 11.49 Instead of including a capacitor as...Ch. 11 - Prob. 54ECh. 11 - A load is drawing 10 A rms when connected to a...Ch. 11 - For the circuit of Fig. 11.50, assume the source...Ch. 11 - Prob. 57ECh. 11 - A source 45 sin 32t V is connected in series with...Ch. 11 - Prob. 60ECh. 11 - FIGURE 11.51 The circuit in Fig. 11.51 uses a Pi...Ch. 11 - Prob. 62ECh. 11 - Prob. 63ECh. 11 - You would like to maximize power transfer to a 50 ...
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