
(a)
Interpretation: The
Concept Introduction : Spontaneous reaction are those which is a spontaneous process under given conditions without any intervention. Such reactions are accompanied by certain distortion or change in entropy.
Cell potential under standard conditions is calculated as follows:
The reaction is spontaneous if the value of
(a)

Answer to Problem 20E
As
Explanation of Solution
The given reaction with oxidation state is:
From the reaction is it clear that Mn undergo reduction and I undergoes oxidation.
So, the half cells can be balanced as,
Reduction half cell:
Oxidation half cell:
Multiply oxidation half with 2 and reduction half with 5 to balance the electron gained and electron lost we get:
Adding both the reaction we get the balanced equation:
Now calculate cell potential using values from Table 11.1 as,
As
(b)
Interpretation: The
Concept Introduction : Spontaneous reaction are those which is a spontaneous process under given conditions without any intervention. Such reactions are accompanied by certain distortion or change in entropy.
Cell potential under standard conditions is calculated as follows:
The reaction is spontaneous if the value of
(b)

Answer to Problem 20E
As
Explanation of Solution
The given reaction with oxidation state is:
From the reaction is it clear that Mn undergo reduction and F undergoes oxidation.
So, the half cells can be balanced as,
Reduction half cell:
Oxidation half cell:
Multiply oxidation half with 2 and reduction half with 5 to balance the electron gained and electron lost we get:
Adding both the reaction we get the balanced equation:
Now calculate cell potential using values from Table 11.1 as,
As
(c)
Interpretation: The
Concept Introduction :: Spontaneous reaction are those which is a spontaneous process under given conditions without any intervention. Such reactions are accompanied by certain distortion or change in entropy.
Cell potential under standard conditions is calculated as follows:
The reaction is spontaneous if the value of
(c)

Answer to Problem 20E
As
Explanation of Solution
The given reaction with oxidation state is:
From the reaction is it clear that H undergo reduction as well as oxidation.
The reaction is already balanced.
Now calculate cell potential using values from Table 11.1 as,
As
(d)
Interpretation: The
Concept Introduction :: Spontaneous reaction are those which is a spontaneous process under given conditions without any intervention. Such reactions are accompanied by certain distortion or change in entropy.
Cell potential under standard conditions is calculated as follows:
The reaction is spontaneous if the value of
(d)

Answer to Problem 20E
As
Explanation of Solution
The given reaction with oxidation state is:
From the reaction is it clear that Ag undergo oxidation and Au undergoes reduction.
Multiply oxidation half with 2 and reduction half with 5 to balance the electron gained and electron lost we get:
Adding both the reaction we get the balanced equation:
Now calculate cell potential using values from Table 11.1 as,
As
As
Want to see more full solutions like this?
Chapter 11 Solutions
Chemical Principles
- 2Helparrow_forwardplease add appropriate arrows, and tell me clearly where to add arrows, or draw itarrow_forwardWhat I Have Learned Directions: Given the following reaction and the stress applied in each reaction, answer the question below. A. H2(g) + Cl2(g) 2 HCl(g) Stress applied: Decreasing the pressure 1. What is the Keq expression? 2. What will be the effect in the number of moles of HCl(g)? 3. What will be the Equilibrium Shift or the reaction? B. Fe3O4(s) + 4 H2(g) + heat 53 Fe(s) + 4 H₂O(g) Stress applied: Increasing the temperature 1. What is the Keq expression?. 2. What will be the effect in the volume of water vapor collected? 3. What will be the Equilibrium Shift or the reaction? C. 4 NH3(g) + 5 O2(g) 4 NO(g) + 6 H2O(g) + heat Stress applied: Increasing the volume of the container 1. What is the Keq expression?. 2. What will be the effect in the amount of H₂O? 3. What will be the Equilibrium Shift or the reaction?arrow_forward
- Consider the solubility products (Ksp values) for the following compounds:SrSO4 (Ksp = 7.6 x 10−7), BaSO4 (Ksp = 1.5 x 10−9), SrCO3 (Ksp = 7.0 x 10−10), BaCO3 (Ksp = 1.6 x 10−9)Which anion is the harder base, CO32− or SO42−? Justify your answer.arrow_forwardQ1: a) Arrange the compounds in order of decreasing pKa, highest first. ОН ΟΗ ῸΗ дон ОН ОН CI Brarrow_forward(4 pts - 2 pts each part) A route that can be taken to prepare a hydrophobic (water-repellent) aerogel is to start with trichloromethylsilane, CH3SiCl3 as the silicon source. a. What is the chemical reaction that this undergoes to form a product with Si-OH groups? Write as complete of a chemical equation as you can. CI CI-SI-CH3 CI b. The formation of a byproduct is what drives this reaction - what is the byproduct (if you didn't already answer it in part (a)) and how/why does it form?arrow_forward
- b) Circle the substrate that would not efficiently generate a Grignard reagent upon reaction with Mg in ether. CI Br ד c) Circle the Grignard reagents that contain incompatible functional groups. MgBr HO MgBr MgBr MgBr MgBr HO MgBrarrow_forwardQ2: Predict all organic product(s), including stereoisomers when applicable. PCC OH a) CH2Cl2 Page 2 of 5 Chem 0310 Organic Chemistry 1 HW Problem Sets b) .OH Na2Cr2O7, H+ OH PCC CH2Cl2 c) OHarrow_forwardd) Circle the substrates that will give an achiral product after a Grignard reaction with CH3MgBr. Harrow_forward
- General Chemistry - Standalone book (MindTap Cour...ChemistryISBN:9781305580343Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; DarrellPublisher:Cengage LearningChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning
- Chemistry & Chemical ReactivityChemistryISBN:9781133949640Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage LearningChemistry: An Atoms First ApproachChemistryISBN:9781305079243Author:Steven S. Zumdahl, Susan A. ZumdahlPublisher:Cengage Learning





