
(a)
Interpretation: The galvanic cells based on given overall reaction needs to be sketched and the value of
Concept Introduction: A galvanic cell is an electro chemical cell that drives electrical energy from
In a galvanic cell the oxidation and the reduction half cells are separated by a connecting wire so that electrons can flow through the wire.
(a)

Answer to Problem 19E
Sketch of a galvanic cell is as follows:
Values of
Explanation of Solution
Below is a sketch of a galvanic cell where electrons flow from anode to cathode with a salt bridge between two to supply the required ions and complete the circuit. Cations will always flow to the anode and anions will always flow to the cathode.
By examining oxidation number of atoms in the reaction determine which compound is oxidized and which being reduced.
In above reaction Cr has +3 oxidation state and Cl has 0 oxidation state and in products Cr has +6 oxidation state and Cl has -1 oxidation state. Oxidation number increased for Cr, it is oxidized. This means that
Determine actual half reactions that have occurred.
Cr has lost three electrons because Cr atom has gone from +3 to +6. Add six electrons to the products. The half reaction is now change balanced as well.
It has been converted to
Each Cl atom required one electron because they have gone from 0 to -1, thus add two electrons in reactants for a change balance.
Add two half reactions together and cancel out the electrons to determine overall process. Because Cr half reaction has six electrons multiply Cl half reaction by three before adding two together.
Determine the standard reduction potential from reference table to calculate
Add these values together to give
(b)
Interpretation: The galvanic cells based on given overall reaction needs to be sketched and the value of
Concept Introduction: A galvanic cell is an electro chemical cell that drives electrical energy from chemical reactions taking place within a particular cell.
In a galvanic cell the oxidation and the reduction half cells are separated by a connecting wire so that electrons can flow through the wire.
(b)

Answer to Problem 19E
Sketch of a galvanic cell is as follows:
Values of
Explanation of Solution
By examining oxidation number of atoms in the reaction determine which compound is oxidized and which being reduced.
In above reaction Cu has +2 oxidation state and Mg has 0 oxidation state and in products Cu has 0 oxidation state and Mg has +2oxidation state. Oxidation number increased for Mg, it is oxidized. This means that Mg is at the anode. For Cu oxidation number decreased, it was reduced. This means that
Add two half reactions together and cancel out electrons determine overall process.
Determine the standard reduction potential from reference table to calculate
Add these values together to give
(c)
Interpretation: The galvanic cells based on given overall reaction needs to be sketched and the value of
Concept Introduction: A galvanic cell is an electro chemical cell that drives electrical energy from chemical reactions taking place within a particular cell.
In a galvanic cell the oxidation and the reduction half cells are separated by a connecting wire so that electrons can flow through the wire.
(c)

Answer to Problem 19E
Sketch of a galvanic cell is as follows:
Values of
Explanation of Solution
By examining oxidation number of atoms in the reaction determine which compound is oxidized and which being reduced.
In above reaction I has +5 oxidation state and Fe has +2 oxidation state and in products I has 0 oxidation state and Fe has +3oxidation state. Oxidation number increased for Fe, it is oxidized. This means that
Determine actual half reactions that have occurred
Each I atom has gone from +5 to 0 oxidation state, thus it has gained five electrons. Add ten electrons to reactants. Half-reaction is now charge balanced as well.
To determine overall process add two half reactions together and cancel out electrons. Because I half-reaction has ten electrons, multiply Fe half-reaction by ten before adding two together.
Determine standard reduction potentials from reference table to calculate
Add these values together to give
(d)
Interpretation: The galvanic cells based on given overall reaction needs to be sketched and the value of
Concept Introduction: A galvanic cell is an electro chemical cell that drives electrical energy from chemical reactions taking place within a particular cell.
In a galvanic cell the oxidation and the reduction half cells are separated by a connecting wire so that electrons can flow through the wire.
(d)

Answer to Problem 19E
Sketch of a galvanic cell is as follows:
Values of
Explanation of Solution
By examining oxidation number of atoms in the reaction determines which compound is oxidized and which being reduced.
In above reaction Ag has +1 oxidation state and Zn has 0 oxidation state and in products Ag has 0 oxidation state and Zn has +2 oxidation state. This means Zn is at anode. Because oxidation number decrease for Ag. It is reduced. This means that
Determine actual-half reactions that have occurred. Zn has only been converted to
Zn loses two electrons so add two electrons to products to charge balance half-reaction.
Determine standard reduction potentials from reference table to calculate
Add these values together to give
Want to see more full solutions like this?
Chapter 11 Solutions
Chemical Principles
- Calculate the pH of 0.015 M HCl.arrow_forwardCalculate the pH of 0.450 M KOH.arrow_forwardWhich does NOT describe a mole? A. a unit used to count particles directly, B. Avogadro’s number of molecules of a compound, C. the number of atoms in exactly 12 g of pure C-12, D. the SI unit for the amount of a substancearrow_forward
- 5 What would the complete ionic reaction be if aqueous solutions of potassium sulfate and barium acetate were mixed? ed of Select one: O a 2 K SO4 + Ba2 +2 C₂H3O21 K+SO4 + Ba2+ + 2 C2H3O21 K+SO42 + Ba2 +2 C2H3O2 BaSO4 +2 K+ + 2 C2H3O estion Ob. O c. Od. 2 K SO4 +Ba2 +2 C₂H₂O₂ BaSO4 + K+ + 2 C2H3O BaSO4 + K + 2 C2H301 →Ba² +SO42 +2 KC2H3O s pagearrow_forward(28 pts.) 7. Propose a synthesis for each of the following transformations. You must include the reagents and product(s) for each step to receive full credit. The number of steps is provided. (OC 4) 4 steps 4 steps OH b.arrow_forwardLTS Solid: AT=Te-Ti Trial 1 Trial 2 Trial 3 Average ΔΗ Mass water, g 24.096 23.976 23.975 Moles of solid, mol 0.01763 001767 0101781 Temp. change, °C 2.9°C 11700 2.0°C Heat of reaction, J -292.37J -170.473 -193.26J AH, kJ/mole 16.58K 9.647 kJ 10.85 kr 16.58K59.64701 KJ mol 12.35k Minimum AS, J/mol K 41.582 mol-k Remember: q = mCsAT (m = mass of water, Cs=4.184J/g°C) & qsin =-qrxn & Show your calculations for: AH in J and then in kJ/mole for Trial 1: qa (24.0969)(4.1845/g) (-2.9°C)=-292.37J qsin = qrxn = 292.35 292.37J AH in J = 292.375 0.2923kJ 0.01763m01 =1.65×107 AH in kJ/mol = = 16.58K 0.01763mol mol qrx Minimum AS in J/mol K (Hint: use the average initial temperature of the three trials, con Kelvin.) AS=AHIT (1.65×10(9.64×103) + (1.0 Jimaiarrow_forward
- General Chemistry - Standalone book (MindTap Cour...ChemistryISBN:9781305580343Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; DarrellPublisher:Cengage LearningChemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage Learning
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistry: An Atoms First ApproachChemistryISBN:9781305079243Author:Steven S. Zumdahl, Susan A. ZumdahlPublisher:Cengage Learning




