Chapter 11, Problem 1CQ

To determine

Momentum of mass blocks from largest to smallest.

Answer to Problem 1CQ

Solution:The desired order of momenta is ${(p_x)}_b>{(p_x)}_a={(p_x)}_c={(p_x)}_e>{(p_x)}_d$ .

Explanation of Solution

Formula used:

Momenta (p) = mass of the object (m) $\times$ velocity of the object (v)

Given:

Different mass blocks moving with different velocities are given. Just by multiplying the mass of the object with their velocities will give the momenta of the object.

  

  Figure.1

Calculation:

So, let’s first calculate the momentum of each block.

Momenta of block ‘a’ ${(p_x)}_a=20\text{g}\times \text{1m/s}\text{=20}\text{g-m/s}$

Momenta of block ‘b’ ${(p_x)}_b=20\text{g}\times 2\text{m/s}\text{=40}\text{g-m/s}$

Momenta of block ‘c’ ${(p_x)}_c=10\text{g}\times 2\text{m/s}\text{=20}\text{g-m/s}$

Momenta of block ‘d’ ${(p_x)}_d=10\text{g}\times \text{1m/s}\text{=10}\text{g-m/s}$

Momenta of block ‘e’ ${(p_x)}_e=200\text{g}\times 0.\text{1m/s}\text{=20}\text{g-m/s}$

In the above calculation, we find that the block b has the highest momentum, block a, c and e have the same momenta that is $\text{20}\text{g-m/s}$ and block d has the smallest momenta.

Conclusion:

By the calculation, momenta for each block has been calculated and it has been arranged in the order from largest to smallest as follows.

  ${(p_x)}_b>{(p_x)}_a={(p_x)}_c={(p_x)}_e>{(p_x)}_d$ .