Explanation Given The ball of mas 20 g undergoes a perfectly elastic collision with the ball of mass 100 g. Formula used For an elastic collision, both kinetic energy and momentum are conserved. Therefore, the formulas to be used in this problem are, Initial kinetic energy = Final kinetic energy Initial momentum = Final momentum Calculation The situation of the collision is shown in the figure below. The 100 g mass rises to a height of x after the collision. The height x can be calculated as follows. x = 1 − 1 × cos 50 0 x = 1 − 0.64 m x = 0.36 m We need to consider the potential energy of the 100 g ball for the energy conservation equation part. Let the speed of the 100 g ball be v . The kinetic energy of the 100 g ball after the collision is equal to its potential energy at the height x . 1 2 × 100 × v 2 = 100 × 9.81 × 0.36 v = 2.66 m/s The speed of the 100 g ball when it rises to the height 0.36 m at an angle of 50 0 is 2.66 m/s. Let the velocity of the 20 g ball after the collision be v 1

Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (Chs 1-42) Plus Mastering Physics with Pearson eText -- Access Card Package (4th Edition)

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Chapter 11, Problem 63EAP

To determine

The speed v0 of the 20 g ball

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Chapter 11, Problem 62EAP

Chapter 11, Problem 64EAP

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Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (Chs 1-42) Plus Mastering Physics with Pearson eText -- Access Card Package (4th Edition)

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