Chapter 11, Problem 135CP

Interpretation Introduction

Interpretation: The boiling point and freezing point has to be calculated.

Concept Introduction: The depression in freezing point, the elevation of boiling point and osmotic pressure are together known as colligative properties.

The elevation in boiling point can be given by the equation,

${\text{ΔT=K}}_{\text{b}}{\text{m}}_{\text{solute}}$

Where, $\text{ΔT}$= change in boiling point elevation

                    ${\text{K}}_{\text{b}}$ = molal boiling point elevation constant

                ${\text{m}}_{\text{solute}}$ = molality of solute

The depression in freezing point can be given by the equation,

${\text{ΔT=K}}_{\text{f}}{\text{m}}_{\text{solute}}$

Where, $\text{ΔT}$=change in freezing point depression

                         ${\text{K}}_{\text{f}}$= molal freezing point depression constant

                          ${\text{m}}_{\text{solute}}$ = molality of solute