The factors such as structure, pressure and temperature on solubility has to be discussed. Henry law and the reason why Henry law does not work for Hydrochloric acid has to be explained. The terms hydrophobic and hydrophilic has to be explained. Concept Introduction: Henry’s law can be given as the quantity of gas dissolve in a solution is proportional to the pressure of the gas above the solution. Henry’s law gives the relationship between the pressure of the gas and the concentration of gas dissolved. The equation can be given as, C=kP where, C= Concentration of the gas dissolved k=constant P=Partial pressure of the solute in gaseous solute
The factors such as structure, pressure and temperature on solubility has to be discussed. Henry law and the reason why Henry law does not work for Hydrochloric acid has to be explained. The terms hydrophobic and hydrophilic has to be explained. Concept Introduction: Henry’s law can be given as the quantity of gas dissolve in a solution is proportional to the pressure of the gas above the solution. Henry’s law gives the relationship between the pressure of the gas and the concentration of gas dissolved. The equation can be given as, C=kP where, C= Concentration of the gas dissolved k=constant P=Partial pressure of the solute in gaseous solute
Solution Summary: The author explains Henry's law and the reason why it doesn't work for Hydrochloric acid.
Interpretation: The factors such as structure, pressure and temperature on solubility has to be discussed. Henry law and the reason why Henry law does not work for Hydrochloric acid has to be explained. The terms hydrophobic and hydrophilic has to be explained.
Concept Introduction:
Henry’s law can be given as the quantity of gas dissolve in a solution is proportional to the pressure of the gas above the solution.
Henry’s law gives the relationship between the pressure of the gas and the concentration of gas dissolved. The equation can be given as,
C=kP
where, C= Concentration of the gas dissolved
k=constant
P=Partial pressure of the solute in gaseous solute
Draw the structure of the pound in the provided
CO
as a 300-1200
37(2), 11 ( 110, and 2.5 (20
Please help me with # 4 and 5. Thanks in advance!
A small artisanal cheesemaker is testing the acidity of their milk
before it coagulates. During fermentation, bacteria produce lactic
acid (K₁ = 1.4 x 104), a weak acid that helps to curdle the milk and
develop flavor. The cheesemaker has measured that the developing
mixture contains lactic acid at an initial concentration of 0.025 M.
Your task is to calculate the pH of this mixture and determine whether
it meets the required acidity for proper cheese development. To
achieve the best flavor, texture and reduce/control microbial growth,
the pH range needs to be between pH 4.6 and 5.0.
Assumptions:
Lactic acid is a monoprotic acid
H
H
:0:0:
H-C-C
H
:0:
O-H
Figure 1: Lewis Structure for Lactic Acid
For simplicity, you can use the generic formula HA to represent the acid
You can assume lactic acid dissociation is in water as milk is mostly water.
Temperature is 25°C
1. Write the K, expression for the dissociation of lactic acid in the space provided. Do not forget to
include state symbols.…
Chapter 11 Solutions
OWLv2 with MindTap Reader, 4 terms (24 months) Printed Access Card for Zumdahl/Zumdahl/DeCoste’s Chemistry, 10th Edition