Web Development and Design Foundations with HTML5 (9th Edition) (What's New in Computer Science)
9th Edition
ISBN: 9780134801148
Author: Terry Felke-Morris
Publisher: PEARSON
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Chapter 11, Problem 12FIB
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The usage of copyrighted work for various determinations like criticism, reporting, teaching, scholarship or research is referred as “fair use”.
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Character Analysis
If you have downloaded the source code you will find a file named text.txt on the Chapter 08 folder. Write a program that reads the file's contents and determines the following:
The number of uppercase letters in the file
The number of lowercase letter in the file
The number of digits in the file
The number of whitespace characters in the file
Write a program that reads the text file's contents and calculates and outputs the following in this order:
• The number of words in the file
• The number of lines in the file
• The number of uppercase letters in the file
• The number of lowercase letters in the file
• The number of digits in the file
• The number of letter H's in the file
• The number of whitespace characters in the file
NOTE: Your program should include at least one try-except error handling statement block. Your program should also validate any input that could cause your program to crash.
I'm Henery The Eighth, I Am! Henery The Eighth, I Am, I am!I got married to the widow next door,She's been married seven times before.And ev'ryone was a Henery,She wouldn't have Willie or a Sam.I'm her eighth old man named Henery,Henery the Eighth, I Am!Second verse same as the first!I'm Henery The Eighth, I Am! Henery The Eighth, I Am, I am!I got married to the widow next door,She's been married seven times before.And…
Chapter 11 Solutions
Web Development and Design Foundations with HTML5 (9th Edition) (What's New in Computer Science)
Ch. 11.3 - Prob. 1CPCh. 11.3 - Prob. 2CPCh. 11.3 - Prob. 3CPCh. 11.7 - Prob. 1CPCh. 11.7 - Prob. 2CPCh. 11.7 - Prob. 3CPCh. 11.11 - Prob. 1CPCh. 11.11 - Prob. 2CPCh. 11.11 - Prob. 3CPCh. 11 - Prob. 1MC
Ch. 11 - Prob. 2MCCh. 11 - Prob. 3MCCh. 11 - Prob. 4MCCh. 11 - Prob. 5MCCh. 11 - Prob. 6MCCh. 11 - Prob. 7MCCh. 11 - Prob. 8MCCh. 11 - A file that contains a Flash animation uses the...Ch. 11 - Prob. 10MCCh. 11 - Prob. 11FIBCh. 11 - Prob. 12FIBCh. 11 - Prob. 13FIBCh. 11 - When displaying a Java applet, the browser invokes...Ch. 11 - Prob. 15FIBCh. 11 - Prob. 16SACh. 11 - Prob. 17SACh. 11 - Prob. 1AYKCh. 11 - Prob. 2AYKCh. 11 - Prob. 3AYKCh. 11 - Prob. 1HOECh. 11 - Prob. 2HOECh. 11 - Prob. 3HOECh. 11 - Prob. 4HOECh. 11 - Prob. 5HOECh. 11 - Prob. 6HOECh. 11 - Prob. 7HOECh. 11 - Prob. 1WRCh. 11 - Prob. 2WRCh. 11 - Prob. 3WRCh. 11 - Prob. 4WR
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- Big State University The Big State University course catalog reads as follows: "To enroll in MIS 260, which is an advanced course, a student must complete two prerequisites: MIS 120 and MIS 222. A student who completes either one of these prerequisites and obtains the instructor's permission, however, will be allowed to take MIS 260." Tasks 1. Create a decision table that describes the Big State University course catalog regarding eligibility for MIS 260. Show all possible rules. 2. Simplify the table you just created. Describe the results. 3. Draw a simplified decision tree to represent the Big State University catalog. Describe the results. 4. Why might you use a decision tree rather than a decision table?arrow_forwardWhat is the ALU result if the 4-bit ALU Control signal is 0100? What happens if the ALU Control signal is 0101?arrow_forward#include int main (void) { int i, *p, count } p = &count; = 10%; for (i = 5; i >= 0; i--) { count++; (*p) ++; } printf("count return 0; = %d, Have a wonderful day.\n", count); 1. [20 pts] What is the output of the program? Please explain why. 2. [15 pts] What is the gdb command to set a breakpoint in line 6 (p = &count;)? 3. [15 pts] Explain in your own words how the [break. need to use such command? ... if expr] command works. When might youarrow_forward
- Please run and debug the following program and answer the questions.arrow_forward(OnlineGDB) #include <stdio.h>int main(void) {int a;char *s;int v0 = 4, v1 = 5, v2 = 6, v3 = 1, v4 = 2;printf("Exercise 1:\n====================\n");switch(v0) {case 0: printf("Hello October\n"); break;case 1: printf("Go Kean!\n"); break;case 2: printf("Academic Building Center \n"); break;case 3: printf("UNION \n"); break;case 4: printf("Go ");case 5: printf("Kean! \n");default: printf("Have a great semester! \n"); break;}for(a=5; a<v1; a++) {printf("Kean");}printf("\n");if (v2 == 6) {s = "Go";}else {s = "Hello";}if(v3 != v4) {printf("%s Kean!\n",s);} else {printf("%s Computer Science!\n",s);}return 0;} Assume the following codes are added between line 36 (}) and line 38 (return 0;) v0>0 ? ++v1, ++v2 : --v3; Please give the values of v0, v1, v2, v3, and v4 after this line and explain the reason. You can test the program to verify your answer if you like.arrow_forward#include <stdio.h>int main(void) {int a;char *s;int v0 = 4, v1 = 5, v2 = 6, v3 = 1, v4 = 2;printf("Exercise 1:\n====================\n");switch(v0) {case 0: printf("Hello October\n"); break;case 1: printf("Go Kean!\n"); break;case 2: printf("Academic Building Center \n"); break;case 3: printf("UNION \n"); break;case 4: printf("Go ");case 5: printf("Kean! \n");default: printf("Have a great semester! \n"); break;}for(a=5; a<v1; a++) {printf("Kean");}printf("\n");if (v2 == 6) {s = "Go";}else {s = "Hello";}if(v3 != v4) {printf("%s Kean!\n",s);} else {printf("%s Computer Science!\n",s);}return 0;} Output: Exercise 1:====================Go Kean! Have a great semester! Go Kean! Please only modify the initial value of v0, v1, v2, v3 and v4 to get the following output. Youneed to show your program output (in the screenshot) and submit the code that youmodified.Exercise 1:====================Hello OctoberKeanHello Computer Science!arrow_forward
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