ORGANIC CHEMISTRY PRINCIPLES & MECHANISM
ORGANIC CHEMISTRY PRINCIPLES & MECHANISM
2nd Edition
ISBN: 9780393681826
Author: KARTY
Publisher: NORTON
Question
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Chapter 11, Problem 11.2P
Interpretation Introduction

(a)

Interpretation:

Show how the given compound can be produced from an alkene.

Concept introduction:

The reaction in which a π bond is broken and two new σ bonds are formed is an electrophilic addition reaction. This reaction has a two-step mechanism. Step 1 is an electrophilic addition step, in which a pair of electrons from the electron rich π bond forms a bond to the acid’s electron-poor atom. Step 2 is a coordination step, in which the conjugate base forms a bond to the carbocation.

Interpretation Introduction

(b)

Interpretation:

Show how the given compound can be produced from an alkene.

Concept introduction:

The reaction in which a π bond is broken and two new σ bonds are formed is an electrophilic addition reaction. This reaction has a two-step mechanism. Step 1 is an electrophilic addition step, in which a pair of electrons from the electron rich π bond forms a bond to the acid’s electron-poor atom. Step 2 is a coordination step, in which the conjugate base forms a bond to the carbocation.

Interpretation Introduction

(c)

Interpretation:

Show how the given compound can be produced from an alkene.

Concept introduction:

The reaction in which a π bond is broken and two new σ bonds are formed is an electrophilic addition reaction. This reaction has a two-step mechanism. Step 1 is an electrophilic addition step, in which a pair of electrons from the electron rich π bond forms a bond to the acid’s electron-poor atom. Step 2 is a coordination step, in which the conjugate base forms a bond to the carbocation. Step 1 is the rate determining step of the mechanism.

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Can you please help mne with this problem. Im a visual person, so can you redraw it, potentislly color code and then as well explain it. I know im given CO2 use that to explain to me, as well as maybe give me a second example just to clarify even more with drawings (visuals) and explanations.
Part 1. Aqueous 0.010M AgNO 3 is slowly added to a 50-ml solution containing both carbonate [co32-] = 0.105 M and sulfate [soy] = 0.164 M anions. Given the ksp of Ag2CO3 and Ag₂ soy below. Answer the ff: Ag₂ CO3 = 2 Ag+ caq) + co} (aq) ksp = 8.10 × 10-12 Ag₂SO4 = 2Ag+(aq) + soy² (aq) ksp = 1.20 × 10-5 a) which salt will precipitate first? (b) What % of the first anion precipitated will remain in the solution. by the time the second anion starts to precipitate? (c) What is the effect of low pH (more acidic) condition on the separate of the carbonate and sulfate anions via silver precipitation? What is the effect of high pH (more basic)? Provide appropriate explanation per answer
Part 4. Butanoic acid (ka= 1.52× 10-5) has a partition coefficient of 3.0 (favors benzene) when distributed bet. water and benzene. What is the formal concentration of butanoic acid in each phase when 0.10M aqueous butanoic acid is extracted w❘ 25 mL of benzene 100 mL of a) at pit 5.00 b) at pH 9.00

Chapter 11 Solutions

ORGANIC CHEMISTRY PRINCIPLES & MECHANISM

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