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Concept explainers
Toexplain:
Red cards and even numbers are mutually exclusive.
![Check Mark](/static/check-mark.png)
Answer to Problem 23E
Red cards and even numbers are not mutually exclusive.
Explanation of Solution
Given information:
Total cards
Blue or Red card
Red cards drawn number
Blue cards drawn number
It is given that out of
It is required to know whether red cards and even numbers are mutually exclusive.
It is only stated that
Moreover, the numbers of red and blue colors are also not known. Without these pieces of information concluding remark is not justified.
Chapter 10 Solutions
Big Ideas Math A Bridge To Success Algebra 2: Student Edition 2015
- The only problems I need help with ae the last 8 ones, Thanksarrow_forwardGraph without using the calculator y-1 = | x+4 |arrow_forward9:43 AS く Akbar © Printed in the United States 15) Scale: 1 cmal unit on both axes .ill 64% The graph above shows a straight line QT intersecting the y-axis at T. i State the co-ordinates of T. ii Calculate the gradient of QT 16) iii Determine the equation of QT. A (-1, 9) ||| i L Г (5 marks)arrow_forward
- Pls help.arrow_forwardSolve the system of equation for y using Cramer's rule. Hint: The determinant of the coefficient matrix is -23. - 5x + y − z = −7 2x-y-2z = 6 3x+2z-7arrow_forwarderic pez Xte in z= Therefore, we have (x, y, z)=(3.0000, 83.6.1 Exercise Gauss-Seidel iteration with Start with (x, y, z) = (0, 0, 0). Use the convergent Jacobi i Tol=10 to solve the following systems: 1. 5x-y+z = 10 2x-8y-z=11 -x+y+4z=3 iteration (x Assi 2 Assi 3. 4. x-5y-z=-8 4x-y- z=13 2x - y-6z=-2 4x y + z = 7 4x-8y + z = -21 -2x+ y +5z = 15 4x + y - z=13 2x - y-6z=-2 x-5y- z=-8 realme Shot on realme C30 2025.01.31 22:35 farrow_forward
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