Chapter 10.2, Problem 23E

To determine

To calculate:

The probability value for the selection of person who will attend both football game and dance

Answer to Problem 23E

The probability value for the selection of person who will attend both football game and dance is $0.0989$

Explanation of Solution

Given information:

Probability to attend football game: $43\%=0.43$

Probability to attend dance and football: $23\%=0.23$

Calculation:

In the given problem, there is random selection of the person who will attend both football game and dance:

Consider,

Probability to attend football game: $P\left(A\right)=0.43$

Probability to attend dance and football: $P\left(B\right)=0.23$

Now, the probability value for person who will attend both football game and dance is calculated as:

  $\begin{array}{l}P\left(A\cap B\right)=P\left(A\right)\times P\left(B\right)\\ P\left(A\cap B\right)=0.43\times 0.23\\ P\left(A\cap B\right)=0.0989\end{array}$