
Concept explainers
(a)
Interpretation:
The respective reactant (methyl substituted piperidine) and respective product (diene) should be given.
Concept introduction:
Generally
These quaternary ammonium salt under goes an elimination reaction easily.
Hofmann elimination:
Quaternary ammonium ion undergoes elimination when using strong base like hydroxide ion this reaction is called as Hofmann elimination.
In the Hofmann elimination, abstraction of proton form β- carbon atom which is having more number of hydrogen to result the elimination product.
(b)
Interpretation:
The respective reactant (methyl substituted piperidine) and respective product (diene) should be given.
Concept introduction:
Hofmann elimination:
Quaternary ammonium ion undergoes elimination when using strong base like hydroxide ion this reaction is called as Hofmann elimination.
In the Hofmann elimination, abstraction of proton form β- carbon atom which is having more number of hydrogen to result the elimination product.
(c)
Interpretation:
The respective reactant (methyl substituted piperidine) and respective product (diene) should be given.
Concept introduction:
Hofmann elimination:
Quaternary ammonium ion undergoes elimination when using strong base like hydroxide ion this reaction is called as Hofmann elimination. Proton abstraction is takes place in β- carbon atom which is having more number of hydrogen.
(d)
Interpretation:
The respective reactant (methyl substituted piperidine) and respective product (diene) should be given.
Concept introduction:
Generally amines can’t undergo elimination reaction, therefore amines can be converted in to quaternary ammonium halide by treating with ethyl iodide in basic solution of potassium carbonate, and this ammonium halide is treating with silver oxide to give ammonium hydroxide salt.
These quaternary ammonium salt under goes an elimination reaction easily.
Hofmann elimination:
Quaternary ammonium ion undergoes elimination when using strong base like hydroxide ion this reaction is called as Hofmann elimination.
In the Hofmann elimination, abstraction of proton form β- carbon atom which is having more number of hydrogen to result the elimination product.

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Chapter 10 Solutions
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