BIOLOGY 12E CONNECT ACCESS CARD
BIOLOGY 12E CONNECT ACCESS CARD
12th Edition
ISBN: 9781264938513
Author: Raven
Publisher: MCG
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Chapter 10, Problem 5A

The main difference between bacterial cell division and eukaryotic cell division is that

a. because bacteria only have one chromosome, they can count the number of copies in the cell.

b. eukaryotes mark their chromosomes to identify them and bacteria do not.

c. bacterial DNA replication and chromosome segregation are concerted processes but in eukaryotes they are separated in time.

d. None of the above is correct.

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1) Look at the ideal results. Were your predictions accurate, and how did they compare with your results?   2) You used aseptic technique during this lab. Why is it important to work in a sterile manner when working with bacteria in the lab?   3) Why are the cells incubated at 42°C?
Overview of Transformation Protocol   -Prepare competent bacteria for transformation: Treat starter E. coli bacteria with CaCl2and Competent Cell Solution (CCS). Store on ice until transformation procedure. Competent cells are cells that are likely to take up foreign DNA and be transformed. This step increases the likelihood that the E. coli cells will take up the introduced vector and be transformed. -Transformation procedure: Obtain two microcentrifuge tubes containing your competent cells. Label one tube +DNA and one -DNA. Add CaCl2 to both tubes. Add the transformation mix containing the plasmid DNA to the tube labeled +DNA. Do not add any plasmid DNA to the -DNA tube. Incubate both tubes on ice for 10 minutes. Then, place both tubes in a 42\deg C water bath for 45 seconds. Replace the tubes in an ice bucket for 2 minutes. Add recovery broth to both tubes. Incubate both tubes in a 37 C water bath for 5 minutes.   Questions: 1) What differences would you expect to see between the…
Overview of Transformation Protocol   -Prepare competent bacteria for transformation: Treat starter E. coli bacteria with CaCl2and Competent Cell Solution (CCS). Store on ice until transformation procedure. Competent cells are cells that are likely to take up foreign DNA and be transformed. This step increases the likelihood that the E. coli cells will take up the introduced vector and be transformed. -Transformation procedure: Obtain two microcentrifuge tubes containing your competent cells. Label one tube +DNA and one -DNA. Add CaCl2 to both tubes. Add the transformation mix containing the plasmid DNA to the tube labeled +DNA. Do not add any plasmid DNA to the -DNA tube. Incubate both tubes on ice for 10 minutes. Then, place both tubes in a 42\deg C water bath for 45 seconds. Replace the tubes in an ice bucket for 2 minutes. Add recovery broth to both tubes. Incubate both tubes in a 37 C water bath for 5 minutes.   Questions: 1)What is the selectable marker in this experiment? How…
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