Chemistry In Focus
Chemistry In Focus
6th Edition
ISBN: 9781305084476
Author: Tro, Nivaldo J., Neu, Don.
Publisher: Cengage Learning
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Chapter 10, Problem 35E
Interpretation Introduction

Interpretation:

Whether the surface of the hot tub would receive enough solar energy or not is to be determined.

Concept Introduction:

Power input is the total surface area multiplied by the solar power. The percent of the input power that is converted to output power is called its efficiency. Percent efficiency is 100 multiplied by the ratio of power out and power in.

Percent efficiency=Power outPower in×100 …… (1)

Power is given by the expression as follows:

Power=energytime ……(2)

Average solar power=Power inputSurface area

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Consider a cloudless day in which the sun shines down across the united states. if 2659 KJ of energy reaches a square meter (m^2) of the united states in one hour, how much total solar energy reaches the entire united states per hour? the entire area of the united states is 9,158.960 km^2.
Consider a cloudless day on which the sun shines down across the United States. If 2247 kJ of energy reaches a square meter (m2) of the United States in one hour, how much total solar energy reaches the entire United States per hour? The entire area of the United States is 9,158,960 km². kJ/h solar energy per hour:
The Sun supplies about 1.0 kilowatt of energy for each squaremeter of surface area (1.0 kW/m2, where a watt = 1 J/s).Plants produce the equivalent of about 0.20 g of sucrose(C12H22O11) per hour per square meter. Assuming that thesucrose is produced as follows, calculate the percentage ofsunlight used to produce sucrose.12 CO2(g)+ 11 H2O(l)-----> C12H22O11 + 12 O2(g)ΔH = 5645 kJ
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