Campbell Biology in Focus (2nd Edition)
Campbell Biology in Focus (2nd Edition)
2nd Edition
ISBN: 9780321962751
Author: Lisa A. Urry, Michael L. Cain, Steven A. Wasserman, Peter V. Minorsky, Jane B. Reece
Publisher: PEARSON
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Chapter 10, Problem 11TYU
Summary Introduction

To explain:

How the triploid number accounts for Cavendish banana’s inability to form normal gametes as it is a triploid variety. Discuss how the absence of sexual reproductionmight make this species vulnerable to infection

Introduction:

Ploidy refers to the number of sets of chromosome present in a cell. Haploid refers to one set of chromosome (n), while diploid cells contain two set of chromosomes (2n). Generally, haploid cells are germ cells which are the product of reductional division (meiosis), rest of the body cells are diploid.

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Plasmogamy is the fusion of(a) two haploid cells including their nuclei.(b) two haploid cells without nuclear fusion.(c) sperm and egg.(d) sperm and two polar nuclei.   Please try to break the solutions into as many steps as practically possible and the steps should come one by one and they should be short and crisp and plagiarism-free.
Unlike mitosis, meiosis in male mammals results in the formation of a) one haploid gamete b) three diploid gametes c) four diploid gametes d) four haploid gametes Please I need a surely answer and a quicker response
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