Physics for Scientists and Engineers, Technology Update (No access codes included)
9th Edition
ISBN: 9781305116399
Author: Raymond A. Serway, John W. Jewett
Publisher: Cengage Learning
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Chapter 10, Problem 10.85AP
(a)
To determine
The speed of the center of mass of the rod just before it hits the horizontal surface.
(b)
To determine
The speed of the center of mass of the rod just before it hits the horizontal surface if the rod has a fixed pivoted at its lower end.
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Students have asked these similar questions
A long piece of wood of length h and mass M is held vertically with its end
bottom resting on a horizontal frictionless surface. Then the piece of wood is
free to fall freely. Determine the speed of its center of mass just before hitting
the horizontal surface.
A uniform bar of mass M and length L is suspended on a frictionless hinge. A horizontally launched blob of clay of mass m strikes the bottom end of the bar and gets stuck to it. After that, the bar swings upward. What is the minimum speed v of the blob of clay before impact that would enable the rod to swing full circle?
a)
a) A thin rod of mass M = 0.5 kg and length L= 8 m is attached to a frictionless table and is struck at a point L/4 from
its CM (as shown) by a clay ball of mass m = 1 kg moving at some speed. The ball sticks to the rod and rotates after the
collision. Consider the clay ball as a point object, therefore Iday = mr?. Calculate the moment of inertia relative to the
point of rotation Q immediately after the collision.
Hint: find r for the clay ball (distance from the point of rotation to the object). Apply the parallel axis theorem for the
rod Irod = ICM rod + Md?, find d for the rod (distance from the point of rotation Q to the center of mass of the rod).
b)
CMod.
b) A thin rod of mass M = 0.5 kg and length L = 8 m is initially at rest on a frictionless table and is struck at a point L/4
from its CM (as shown) by a clay ball of mass m = 1 kg moving at some speed. The ball sticks to the rod and rotates
after the collision. Consider the clay ball as a point object, therefore Iclay = mr2.…
Chapter 10 Solutions
Physics for Scientists and Engineers, Technology Update (No access codes included)
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