ALEKS 360 ACCESS CARD F/GEN. ORG.CHEM
3rd Edition
ISBN: 9781264452545
Author: SMITH
Publisher: MCG
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Question
Chapter 10, Problem 10.54P
Interpretation Introduction
Interpretation:
The reason for higher average amount of background radiation at higher elevations should be determined.
Concept Introduction:
The measurement through which level of ionizing radiation present in the environment at a particular place is termed as background radiation.
Background radiation emerges from a different sources including both natural and artificial.
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Instructions: Complete the questions in the space provided. Show all your work
1. You are trying to determine the rate law expression for a reaction that you are completing at 25°C. You measure
the initial reaction rate and the starting concentrations of the reactions for 4 trials.
BrO³¯ (aq) + 5Br¯ (aq) + 6H* (aq) → 3Br₂ (l) + 3H2O (l)
Initial rate
Trial
[BrO3]
[H*]
[Br]
(mol/L)
(mol/L) | (mol/L)
(mol/L.s)
1
0.10
0.10
0.10
8.0
2
0.20
0.10
0.10
16
3
0.10
0.20
0.10
16
4
0.10
0.10
0.20
32
a.
Based on the above data what is the rate law expression?
b. Solve for the value of k (make sure to include proper units)
2. The proposed reaction mechanism is as follows:
i.
ii.
BrО¸¯ (aq) + H+ (aq) → HBrO3 (aq)
HBrO³ (aq) + H* (aq) → H₂BrO3* (aq)
iii.
H₂BrO³* (aq) + Br¯ (aq) → Br₂O₂ (aq) + H2O (l)
[Fast]
[Medium]
[Slow]
iv.
Br₂O₂ (aq) + 4H*(aq) + 4Br(aq) → 3Br₂ (l) + H2O (l)
[Fast]
Evaluate the validity of this proposed reaction. Justify your answer.
е.
Д
CH3
D*, D20
C.
NaOMe,
Br
Br
Chapter 10 Solutions
ALEKS 360 ACCESS CARD F/GEN. ORG.CHEM
Ch. 10.1 - Complete the following table for two isotopes of...Ch. 10.1 - Prob. 10.2PCh. 10.1 - Prob. 10.3PCh. 10.1 - Identify Q in each of the following symbols. a....Ch. 10.2 - Prob. 10.5PCh. 10.2 - Prob. 10.6PCh. 10.2 - Prob. 10.7PCh. 10.2 - Prob. 10.8PCh. 10.2 - Prob. 10.9PCh. 10.2 - Prob. 10.10P
Ch. 10.2 - Prob. 10.11PCh. 10.2 - Prob. 10.12PCh. 10.3 - Prob. 10.13PCh. 10.3 - Prob. 10.14PCh. 10.3 - Prob. 10.15PCh. 10.3 - Prob. 10.16PCh. 10.4 - Prob. 10.17PCh. 10.4 - Prob. 10.18PCh. 10.4 - Prob. 10.19PCh. 10.5 - Prob. 10.20PCh. 10.5 - Prob. 10.21PCh. 10.5 - Prob. 10.22PCh. 10.6 - Prob. 10.23PCh. 10.6 - Prob. 10.24PCh. 10 - Compare fluorine-18 and fluorine-19 with regard to...Ch. 10 - Prob. 10.26PCh. 10 - Prob. 10.27PCh. 10 - Prob. 10.28PCh. 10 - Prob. 10.29PCh. 10 - Prob. 10.30PCh. 10 - Prob. 10.31PCh. 10 - Prob. 10.32PCh. 10 - Prob. 10.33PCh. 10 - Prob. 10.34PCh. 10 - Prob. 10.35PCh. 10 - Prob. 10.36PCh. 10 - Prob. 10.37PCh. 10 - Prob. 10.38PCh. 10 - Prob. 10.39PCh. 10 - Prob. 10.40PCh. 10 - Prob. 10.41PCh. 10 - Prob. 10.42PCh. 10 - Prob. 10.43PCh. 10 - Prob. 10.44PCh. 10 - Prob. 10.45PCh. 10 - Prob. 10.46PCh. 10 - Prob. 10.47PCh. 10 - Prob. 10.48PCh. 10 - Prob. 10.49PCh. 10 - Prob. 10.50PCh. 10 - Prob. 10.51PCh. 10 - Prob. 10.52PCh. 10 - Prob. 10.53PCh. 10 - Prob. 10.54PCh. 10 - Prob. 10.55PCh. 10 - Prob. 10.56PCh. 10 - Prob. 10.57PCh. 10 - Prob. 10.58PCh. 10 - Prob. 10.59PCh. 10 - Prob. 10.60PCh. 10 - Prob. 10.61PCh. 10 - Prob. 10.62PCh. 10 - Prob. 10.63PCh. 10 - Prob. 10.64PCh. 10 - Prob. 10.65PCh. 10 - Prob. 10.66PCh. 10 - Prob. 10.67PCh. 10 - Prob. 10.68PCh. 10 - Prob. 10.69PCh. 10 - Prob. 10.70PCh. 10 - Prob. 10.71PCh. 10 - Prob. 10.72PCh. 10 - Prob. 10.73PCh. 10 - Prob. 10.74PCh. 10 - Prob. 10.75PCh. 10 - Prob. 10.76PCh. 10 - Prob. 10.77PCh. 10 - Prob. 10.78PCh. 10 - Prob. 10.79PCh. 10 - Prob. 10.80PCh. 10 - Prob. 10.81PCh. 10 - Prob. 10.82PCh. 10 - Prob. 10.83PCh. 10 - Prob. 10.84PCh. 10 - Prob. 10.85PCh. 10 - Prob. 10.86PCh. 10 - Prob. 10.87PCh. 10 - Prob. 10.88PCh. 10 - Prob. 10.89PCh. 10 - Prob. 10.90PCh. 10 - Prob. 10.91PCh. 10 - Prob. 10.92PCh. 10 - Prob. 10.93CPCh. 10 - Prob. 10.94CP
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