Chapter 10, Problem 10.53FU

Interpretation Introduction

Interpretation:

The amount of energy required to vaporize 15.8 g N₂ at its boiling point needs to be calculated.

Concept Introduction:

The latent heat of vaporization is defined as the amount of heat required to vaporize 1 g of the substance. The unit is in J/g. For nitrogen gas, the heat of vaporization at its boiling point is 198 J/g.

Thus, the amount of heat required to vaporize 1 g of the nitrogen gas is 198 J.

It is mathematically represented as follows:

  $Q=mL$

Here, m is mass of nitrogen gas and L is latent heat of vaporization.

Answer to Problem 10.53FU

  $3128.4\text{ J}$

Explanation of Solution

The mass of the nitrogen gas is 15.8 g.

The amount of heat required to vaporize 1 g of the nitrogen gas is 198 J. This is the latent heat of vaporization.

Thus, at the boiling point, the heat required to vaporize 15.8 g of the nitrogen gas can be calculated as follows:

  $Q=mL$

Putting the values,

  $Q=\left(15.8\text{ g}\right)\left(198\text{ J/g}\right)=3128.4\text{ J}$

Therefore, the amount of heat required is $3128.4\text{ J}$ .

Conclusion

Therefore, the amount of heat required is $3128.4\text{ J}$ .