(a) Interpretation: The wavelength of light corresponding to 1.00 × 10 − 32 J energy is to be stated. The comparison of this wavelength to the diameter of the Earth, which is 1.27 × 10 7 m , is to be shown. Concept introduction: The energy for particle in a box is given by the expression as follows. E = n 2 h 2 8 m a 2 Where, • E is the energy of the particle • n is the number of energy level • h is Planck’s constant • m is the mass of the particle • a is the width of the box The expression of the energy for particle in a box involves n which shows that the energy is quantized for a particle in a box.
(a) Interpretation: The wavelength of light corresponding to 1.00 × 10 − 32 J energy is to be stated. The comparison of this wavelength to the diameter of the Earth, which is 1.27 × 10 7 m , is to be shown. Concept introduction: The energy for particle in a box is given by the expression as follows. E = n 2 h 2 8 m a 2 Where, • E is the energy of the particle • n is the number of energy level • h is Planck’s constant • m is the mass of the particle • a is the width of the box The expression of the energy for particle in a box involves n which shows that the energy is quantized for a particle in a box.
Solution Summary: The author explains that the energy for particle in a box is given by the expression as follows.
The wavelength of light corresponding to 1.00×10−32J energy is to be stated. The comparison of this wavelength to the diameter of the Earth, which is 1.27×107m, is to be shown.
Concept introduction:
The energy for particle in a box is given by the expression as follows.
E=n2h28ma2
Where,
• E is the energy of the particle
• n is the number of energy level
• h is Planck’s constant
• m is the mass of the particle
• a is the width of the box
The expression of the energy for particle in a box involves n which shows that the energy is quantized for a particle in a box.
Interpretation Introduction
(b)
Interpretation:
The width of a box that an electron needs to be in, to possess 1.00×10−32J energy is to be calculated.
Concept introduction:
The energy for particle in a box is given by the expression as follows.
E=n2h28ma2
Where,
• E is the energy of the particle
• n is the number of energy levels
• h is Planck’s constant
• m is the mass of the particle
• a is the width of the box
The expression of the energy for particle in a box involves n which shows that the energy is quantized for a particle in a box.
So I need help with understanding how to solve these types of problems. I'm very confused on how to do them and what it is exactly, bonds and so forth that I'm drawing. Can you please help me with this and thank you very much!
So I need help with this problem, can you help me please and thank you!
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