Physical Chemistry
Physical Chemistry
2nd Edition
ISBN: 9781133958437
Author: Ball, David W. (david Warren), BAER, Tomas
Publisher: Wadsworth Cengage Learning,
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Chapter 10, Problem 10.47E
Interpretation Introduction

(a)

Interpretation:

The wavelength of light corresponding to 1.00×1032J energy is to be stated. The comparison of this wavelength to the diameter of the Earth, which is 1.27×107m, is to be shown.

Concept introduction:

The energy for particle in a box is given by the expression as follows.

E=n2h28ma2

Where,

E is the energy of the particle

n is the number of energy level

h is Planck’s constant

m is the mass of the particle

a is the width of the box

The expression of the energy for particle in a box involves n which shows that the energy is quantized for a particle in a box.

Interpretation Introduction

(b)

Interpretation:

The width of a box that an electron needs to be in, to possess 1.00×1032J energy is to be calculated.

Concept introduction:

The energy for particle in a box is given by the expression as follows.

E=n2h28ma2

Where,

E is the energy of the particle

n is the number of energy levels

h is Planck’s constant

m is the mass of the particle

a is the width of the box

The expression of the energy for particle in a box involves n which shows that the energy is quantized for a particle in a box.

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Chapter 10 Solutions

Physical Chemistry

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