ORGANIC CHEMISTRY SAPLING ACCESS + ETEX
ORGANIC CHEMISTRY SAPLING ACCESS + ETEX
6th Edition
ISBN: 9781319306977
Author: LOUDON
Publisher: INTER MAC
bartleby

Concept explainers

Question
Book Icon
Chapter 10, Problem 10.46AP
Interpretation Introduction

(a)

Interpretation:

The increasing order of acidity of the alcohols is to be stated.

Concept introduction:

Acidity of a molecule is dependent on the value of pKa. This pKa value is known as the dissociation constant of an acid. The dissociation constant of an acid changes with the change in temperature. More is the value of pKa, lesser is the acidity of an acid. Strength of an acid also depends upon the stability of the anion generated after loosing a hydrogen ion.

Expert Solution
Check Mark

Answer to Problem 10.46AP

The increasing order of acidity of the alcohols is given below.

ORGANIC CHEMISTRY SAPLING ACCESS + ETEX, Chapter 10, Problem 10.46AP , additional homework tip  1

Explanation of Solution

Acidity of the molecules is dependent upon the stability of the ion formed after releasing hydrogen ion.

Sulfur atom present in 1- propanethiol is larger than the size of the oxygen atom. Therefore, negative charge present on sulfur atom is stabilized. Due to this 1- propanethiol is the strongest acid among the given molecules. Tertiary alcohols are more acidic than the secondary and primary alcohols. Therefore, tertbutyl alcohol is the stronger acid than isopropyl alcohol and propyl alcohol.

Order of the acidity is shown below in Figure 1.

ORGANIC CHEMISTRY SAPLING ACCESS + ETEX, Chapter 10, Problem 10.46AP , additional homework tip  2

Figure 1

Conclusion

The increasing order of acidity of the molecules is propyl alcohol<isopropyl alcohol<tertbutyl alcohol<propanethiol.

Interpretation Introduction

(b)

Interpretation:

The increasing order of acidity of the molecules is to be stated.

Concept introduction:

Acidity of a molecule is dependent on the value of pKa. This pKa value is known as the dissociation constant of an acid. The dissociation constant of an acid changes with the change in temperature. More is the value of pKa, lesser is the acidity of an acid. Strength of an acid also depends upon the stability of the anion generated after loosing a hydrogen ion.

Expert Solution
Check Mark

Answer to Problem 10.46AP

The increasing order of acidity of the molecules is given below.

ORGANIC CHEMISTRY SAPLING ACCESS + ETEX, Chapter 10, Problem 10.46AP , additional homework tip  3

Explanation of Solution

Acidity of the molecules is dependent upon the stability of the ion formed after releasing hydrogen ion. Sulfur atom present in 3- chloro -1- propanethiol is larger than the size of the oxygen atom. Therefore, negative charge present on sulfur atom is stabilized. Due to this, 3- chloro -1- propanethiol is the strongest acid among the given molecules. Position of the electronegative atom also determines the strength of an acid. Closer the electronegative atom to the negative charge generated after releasing the hydrogen ion, more is the strength of the acid.

Therefore, increasing order of the given molecules is shown below in Figure 2.

ORGANIC CHEMISTRY SAPLING ACCESS + ETEX, Chapter 10, Problem 10.46AP , additional homework tip  4

Figure 2

Conclusion

The increasing order of acidity of the given molecules is 2-chloroethanol<3-chloro-1-propanethiol<2-chloro- 1-propanethiol.

Interpretation Introduction

(c)

Interpretation:

The increasing order of acidity of the molecules is to be stated.

Concept introduction:

Acidity of a molecule is dependent on the value of pKa. This pKa value is known as the dissociation constant of an acid. The dissociation constant of an acid changes with the change in temperature. More is the value of pKa, lesser is the acidity of an acid. Strength of an acid also depends upon the stability of the anion generated after loosing a hydrogen ion.

Expert Solution
Check Mark

Answer to Problem 10.46AP

The increasing order of acidity of the molecules is stated below.

CH3N¨HCH2CH2CH2O¨¨H<CH3N¨HCH2CH2O¨¨H<(CH3)3N+CH2CH2O¨¨H

Explanation of Solution

Acidity of the molecules is dependent upon the stability of the ion formed after releasing hydrogen ion. Nitrogen atom which is positively charged, stabilizes the negative charge which is generated after releasing the hydrogen ion. Therefore, structure 3 is the most stable structure with most acidic character. Position of the electronegative atom also determines the strength of an acid. Closer the electronegative atom to the generated negative charge after releasing the hydrogen ion, more is the strength of the acid.

Therefore, increasing order of the given molecules is stated below.

CH3N¨HCH2CH2CH2O¨¨H<CH3N¨HCH2CH2O¨¨H<(CH3)3N+CH2CH2O¨¨H

Conclusion

The increasing order of acidity of the given molecules is CH3N¨HCH2CH2CH2O¨¨H<CH3N¨HCH2CH2O¨¨H<(CH3)3N+CH2CH2O¨¨H.

Interpretation Introduction

(d)

Interpretation:

The increasing order of acidity of the molecules is to be stated.

Concept introduction:

Acidity of a molecule is dependent on the value of pKa. This pKa value is known as the dissociation constant of an acid. The dissociation constant of an acid changes with the change in temperature. More is the value of pKa, lesser is the acidity of an acid. Strength of an acid also depends upon the stability of the anion generated after loosing a hydrogen ion.

Expert Solution
Check Mark

Answer to Problem 10.46AP

The increasing order of acidity of the molecules is stated below.

: O ¨¨CH2CH2O¨¨H<CH3CH2CH2O¨¨H<CH3 O ¨¨CH2CH2O¨¨H<CH3 O ¨¨CH2CH2CH2O ¨+H

Explanation of Solution

Acidity of the molecules is dependent upon the stability of the ion formed after releasing the hydrogen ion. In structure 4, a neutral species is generated after releasing the H+ ion. Therefore, the molecule in structure 4 is the most acidic in nature. Position of the electronegative atom also determines the strength of an acid. Closer the electronegative atom to the generated negative charge after releasing the hydrogen ion, more is the strength of an acid. Therefore, molecule 3 is less acidic than molecule in structure 4. In structure 1, oxygen has already a negative charge. Therefore, it is already in its stabilized form and acts as a weakest acid among the given molecules.

Therefore, increasing order of acidity of the given molecules is stated below.

: O ¨¨CH2CH2O¨¨H<CH3CH2CH2O¨¨H<CH3 O ¨¨CH2CH2O¨¨H<CH3 O ¨¨CH2CH2CH2 O ¨+H

Conclusion

The increasing order of acidity of the given molecules is : O ¨¨CH2CH2O¨¨H<CH3CH2CH2O¨¨H<CH3 O ¨¨CH2CH2O¨¨H<CH3 O ¨¨CH2CH2CH2 O ¨+H

Interpretation Introduction

(e)

Interpretation:

The increasing order of acidity of the molecules is to be stated.

Concept introduction:

Acidity of a molecule is dependent on the value of pKa. This pKa value is known as the dissociation constant of an acid. The dissociation constant of an acid changes with the change in temperature. More is the value of pKa, lesser is the acidity of an acid. Strength of an acid also depends upon the stability of the anion generated after loosing a hydrogen ion.

Expert Solution
Check Mark

Answer to Problem 10.46AP

The increasing order of acidity of the molecules is stated below.

ORGANIC CHEMISTRY SAPLING ACCESS + ETEX, Chapter 10, Problem 10.46AP , additional homework tip  5

Explanation of Solution

Acidity of the molecules is dependent upon the stability of the ion formed after releasing the hydrogen ion. In structure 3, Size of the sulfur atom is more as compared to the size of the oxygen atom. The H+ ion is held loosely with the sulfur atom. Therefore, the molecule in structure 3 easily releases the hydrogen ion and becomes the most acidic in nature. In structure 2 and 3, a neutral species is generated after releasing the H+ ion Therefore, molecule 2 and 3 are more acidic than molecule 1.

Therefore, increasing order of the given molecules is stated below in Figure 3.

ORGANIC CHEMISTRY SAPLING ACCESS + ETEX, Chapter 10, Problem 10.46AP , additional homework tip  6

Figure 3

Conclusion

The increasing order of acidity of the given molecules is shown above in Figure 3.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
1) Suppose 0.1 kg ice at 0°C (273K) is in 0.5kg water at 20°C (293K). What is the change in entropy of the ice as it melts at 0°?    To produce the original "water gas" mixture, carbon (in a combustible form known as coke) is reacted with steam: 131.4 kJ + H20(g) + C(s) → CO(g) + H2(g) From this information and the equations in the previous problem, calculate the enthalpy for the combustion or carbon to form carbon dioxide.   kindly show me how to solve both parts of the same  long problem. Thanks
we were assigned to dilute 900ppm in to 18ppm by using only 250ml vol flask. firstly we did calc and convert 900ppm to 0.9 ppm to dilute in 1 liter. to begin the experiment we took 0,225g of kmno4 and dissolved in to 250 vol flask. then further we took 10 ml sample sol and dissolved in to 100 ml vol flask and put it in to a spectrometer and got value of 0.145A . upon further calc we got v2 as 50ml . need to find DF, % error (expval and accptVal), molarity, molality. please write the whole report. thank you The format, tables, introduction, procedure and observation, result, calculations, discussion and conclusion
Q5. Predict the organic product(s) for the following transformations. If no reaction will take place (or the reaction is not synthetically useful), write "N.R.". Determine what type of transition state is present for each reaction (think Hammond Postulate). I Br₂ CH3 F2, light CH3 Heat CH3 F₂ Heat Br2, light 12, light CH3 Cl2, light No

Chapter 10 Solutions

ORGANIC CHEMISTRY SAPLING ACCESS + ETEX

Knowledge Booster
Background pattern image
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
  • Text book image
    Organic Chemistry
    Chemistry
    ISBN:9781305080485
    Author:John E. McMurry
    Publisher:Cengage Learning
    Text book image
    Organic Chemistry
    Chemistry
    ISBN:9781305580350
    Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
    Publisher:Cengage Learning
    Text book image
    Introduction to General, Organic and Biochemistry
    Chemistry
    ISBN:9781285869759
    Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
    Publisher:Cengage Learning
Text book image
Organic Chemistry
Chemistry
ISBN:9781305080485
Author:John E. McMurry
Publisher:Cengage Learning
Text book image
Organic Chemistry
Chemistry
ISBN:9781305580350
Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher:Cengage Learning
Text book image
Introduction to General, Organic and Biochemistry
Chemistry
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Cengage Learning