Concept explainers
(a)
Interpretation:
The fluorine atoms in the given compound which are the diastereotopic fluorines, the enantiotopic fluorines, the homotopic fluorines, and the constitutionally nonequivalent fluorines are to be identified.
Concept introduction:
The groups which are chemically nondistinguishable are termed as constitutionally equivalent. The groups which are chemically distinguishable are termed as constitutionally nonequivalent. The constitutionally equivalent groups can be further divided into three categories homotopic, enantiotopic, and diastereotopic.
(b)
Interpretation:
The fluorine atoms in the given compound which are the diastereotopic fluorines, the enantiotopic fluorines, the homotopic fluorines, and the constitutionally nonequivalent fluorines are to be identified.
Concept introduction:
The groups which are chemically nondistinguishable are termed as constitutionally equivalent. The groups which are chemically distinguishable are termed as constitutionally nonequivalent. The constitutionally equivalent groups can be further divided into three categories homotopic, enantiotopic, and diastereotopic.
(c)
Interpretation:
The fluorine atoms in the given compound which are the diastereotopic fluorines, the enantiotopic fluorines, the homotopic fluorines, and the constitutionally nonequivalent fluorines are to be identified.
Concept introduction:
The groups which are chemically nondistinguishable are termed as constitutionally equivalent. The groups which are chemically distinguishable are termed as constitutionally nonequivalent. The constitutionally equivalent groups can be further divided into three categories homotopic, enantiotopic, and diastereotopic.

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Chapter 10 Solutions
ORGANIC CHEMISTRY SAPLING ACCESS + ETEX
- (c) (4pts) Mechanism: heat (E1) CH3OH + 1.5pts each _E1 _ (1pt) Br CH3OH (d) (4pts) Mechanism: SN1 (1pt) (e) (3pts) 1111 I H 10 Ill!! H LDA THF (solvent) Mechanism: E2 (1pt) NC (f) Bri!!!!! CH3 NaCN (3pts) acetone Mechanism: SN2 (1pt) (SN1) -OCH3 OCH3 1.5pts each 2pts for either product 1pt if incorrect stereochemistry H Br (g) “,、 (3pts) H CH3OH +21 Mechanism: SN2 (1pt) H CH3 2pts 1pt if incorrect stereochemistry H 2pts 1pt if incorrect stereochemistryarrow_forwardA mixture of butyl acrylate and 4'-chloropropiophenone has been taken for proton NMR analysis. Based on this proton NMR, determine the relative percentage of each compound in the mixturearrow_forwardQ5: Label each chiral carbon in the following molecules as R or S. Make sure the stereocenter to which each of your R/S assignments belong is perfectly clear to the grader. (8pts) R OCH 3 CI H S 2pts for each R/S HO R H !!! I OH CI HN CI R Harrow_forward
