Chapter 10, Problem 10.38P

Give the IUPAC name for each compound.

a. c. e.

b. d. f.

Interpretation Introduction

(a)

Interpretation: The IUPAC name for the given compound is to be stated.

Concept introduction: The systematic naming of organic compound is given by IUPAC nomenclature. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing IUPAC name from structural formula are

1. First identify the longest carbon chain.

2. The next step is to identify the groups attached to the longest chain.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

4. Use prefix di, tri, tetra if same type of substituent is present.

5. Name the substituents in alphabetical order.

Answer to Problem 10.38P

The IUPAC name for the given compound is $6-\text{isopropyl}-3-\text{methylnon}-\text{3}-\text{ene}$.

Explanation of Solution

The given compound is,

Figure 1

The numbering of carbon atoms present in the longest carbon chain is shown below.

Figure 2

The longest carbon chain has nine carbon atoms. The root word used for nine carbon atoms is non and the suffix used for $\text{C}=\text{C}$ linkage is –ene. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. One methyl substituents is attached to the third carbon atom and one isopropyl substituents is attached to the sixth carbon atom. The double bond is present between third and fourth carbon atom.Thus, the IUPAC name of the given structure is $6-\text{isopropyl}-3-\text{methylnon}-\text{3}-\text{ene}$.

Conclusion

The IUPAC name for the given compound is $6-\text{isopropyl}-3-\text{methylnon}-\text{3}-\text{ene}$.

Interpretation Introduction

(b)

Interpretation: The IUPAC name for the given compound is to be stated.

Concept introduction: The systematic naming of organic compound is given by IUPAC nomenclature. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing IUPAC name from structural formula are

1. First identify the longest carbon chain.

2. The next step is to identify the groups attached to the longest chain.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

4. Use prefix di, tri, tetra if same type of substituent is present.

5. Name the substituents in alphabetical order.

Answer to Problem 10.38P

The IUPAC name for the given compound is $2-\text{isopropyl}-4-\text{methylpent}-1-\text{ene}$.

Explanation of Solution

The given compound is,

Figure 3

The numbering of carbon atoms present in longest chain of the given compound is shown below.

Figure 4

The longest carbon-carbon chain has five carbon atoms. The root word used for five carbon atoms is pent and the suffix used for $\text{C}=\text{C}$ linkage is –ene. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. One isopropyl substituent is attached to the second carbon atom and one methyl substituent is attached to the fourth carbon atom. The double bond is present between first and second carbon atom. Thus, the IUPAC name of the given structure is $2-\text{isopropyl}-4-\text{methylpent}-1-\text{ene}$.

Conclusion

The IUPAC name for the given compound is $2-\text{isopropyl}-4-\text{methylpent}-1-\text{ene}$.

Interpretation Introduction

(c)

Interpretation: The IUPAC name for the given compound is to be stated.

Concept introduction: The systematic naming of organic compound is given by IUPAC. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing IUPAC name from structural formula are

1. First identify the longest carbon chain.

2. The next step is to identify the groups attached to the longest chain.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

4. Use prefix di, tri, tetra if same type of substituent is present.

5. Name the substituents in alphabetical order.

Answer to Problem 10.38P

The IUPAC name for the given compound is $5-\left(\sec -\text{butyl}\right)-1,3,3-\text{trimethylcyclohex}-1-\text{ene}$.

Explanation of Solution

The given compound is,

Figure 5

The numbering of carbon atoms present in longest carbon chain of the given compound is shown below.

Figure 6

The longest carbon chain has six carbon atoms. The root word used for six carbon atoms is hex and the suffix used for $\text{C}=\text{C}$ linkage is –ene. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. One methyl substituents is attached to the first carbon atom and two methyl substituents are attached to the third carbon atom. One secondary butyl substituent is attached to the fifth carbon atom. The double bond is present between first and second carbon atom. Thus, the IUPAC name of the given structure is $5-\left(\sec -\text{butyl}\right)-1,3,3-\text{trimethylcyclohex}-1-\text{ene}$.

Conclusion

The IUPAC name for the given compound is $5-\left(\sec -\text{butyl}\right)-1,3,3-\text{trimethylcyclohex}-1-\text{ene}$.

Interpretation Introduction

(d)

Interpretation: The IUPAC name for the given compound is to be stated.

Concept introduction: The systematic naming of organic compound is given by IUPAC nomenclature. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing IUPAC name from structural formula are

1. First identify the longest carbon chain.

2. The next step is to identify the groups attached to the longest chain.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

4. Use prefix di, tri, tetra if same type of substituent is present.

5. Name the substituents in alphabetical order.

Answer to Problem 10.38P

The IUPAC name for the given compound is $4-\text{isopropylhept}-4-\text{ene}-3-\text{ol}$

Explanation of Solution

The given compound is,

Figure 7

The numbering of carbon atoms present in longest carbon chain of the given compound is shown below.

Figure 8

The longest carbon chain has seven carbon atoms. The root word used for seven carbon atoms is hept and the suffix used for $\text{C}=\text{C}$ linkage is –ene. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. One isopropyl substituents is attached to the fourth carbon atom. The double bond is present between fourth and fifth carbon atom. Another functional group present in the given structure is alcohol $\left(-\text{OH}\right)$. The suffix used for alcohol is –ol. Thus, the IUPAC name of the given structure is $4-\text{isopropylhept}-4-\text{ene}-3-\text{ol}$.

Conclusion

The IUPAC name for the given compound is $4-\text{isopropylhept}-4-\text{ene}-3-\text{ol}$.

Interpretation Introduction

(e)

Interpretation: The IUPAC name for the given compound is to be stated.

Concept introduction: The systematic naming of organic compound is given by IUPAC. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing IUPAC name from structural formula are

1. First identify the longest carbon chain.

2. The next step is to identify the groups attached to the longest chain.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

4. Use prefix di, tri, tetra if same type of substituent is present.

5. Name the substituents in alphabetical order.

Answer to Problem 10.38P

The IUPAC name for the given compound is $5-\left(\sec -\text{butyl}\right)\text{cyclohex-2-ene}-1-\text{ol}$.

Explanation of Solution

The given compound is,

Figure 9

The numbering of carbon atoms present in longest carbon chain of the given compound is shown below.

Figure 10

The longest carbon chain has six carbon atoms. The root word used for six carbon atoms is hex and the suffix used for $\text{C}=\text{C}$ linkage is –ene. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. One secondary butyl substituent is attached to the fifth carbon atom. The double bond is present between first and second carbon atom. Another functional group present in the given structure is alcohol $\left(-\text{OH}\right)$. The suffix used for alcohol is –ol. Thus, the IUPAC name of the given structure is $5-\left(\sec -\text{butyl}\right)\text{cyclohex-2-ene}-1-\text{ol}$.

Conclusion

The IUPAC name of the given structure is $5-\left(\sec -\text{butyl}\right)\text{cyclohex-2-ene}-1-\text{ol}$.

Interpretation Introduction

(f)

Interpretation: The IUPAC name for the given compound is to be stated.

Concept introduction: The systematic naming of organic compound is given by IUPAC nomenclature. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing IUPAC name from structural formula are

1. First identify the longest carbon chain.

2. The next step is to identify the groups attached to the longest chain.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

4. Use prefix di, tri, tetra if same type of substituent is present.

5. Name the substituents in alphabetical order.

Answer to Problem 10.38P

The IUPAC name for the given compound is $5-\text{ethyl}-3,4\dim \text{ethylnon}-2-\text{ene}$.

Explanation of Solution

The given compound is,

Figure 11

The numbering of carbon atoms present in longest carbon chain of the given compound is shown below.

Figure 12

The longest carbon chain has six carbon atoms. The root word used for six carbon atoms is hex and the suffix used for $\text{C}=\text{C}$ linkage is –ene. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. One methyl substituent is attached to the third and fourth carbon atom. One ethyl substituent is attached to the fifth carbon atom. The double bond is present between second and third carbon atom.. Thus, the IUPAC name of the given structure is $5-\text{ethyl}-3,4\dim \text{ethylnon}-2-\text{ene}$.

Conclusion

The IUPAC name for the given compound is $5-\text{ethyl}-3,4\dim \text{ethylnon}-2-\text{ene}$