(a) Interpretation: Rate of air and oxygen flow in mol/s unit should be calculated. Concept Introduction: Let us assume x represents rate of air flow (mol/s) and y represents rate of pure oxygen flow rate (mol/s) into the process. Component material balance equation will be used to determine rate of air flow and oxygen flow.

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Answer 1

Question

Chapter 10, Problem 10.38P

Interpretation Introduction

(a)

Interpretation:

Rate of air and oxygen flow in mol/s unit should be calculated.

Concept Introduction:

Let us assume x represents rate of air flow (mol/s) and y represents rate of pure oxygen flow rate (mol/s) into the process.

Component material balance equation will be used to determine rate of air flow and oxygen flow.

Interpretation Introduction

(b)

Interpretation:

Rate of heat transfer for this mixing process should be calculated.

Concept Introduction:

It is considered ideal gas law is followed for the entire mixing process, PV=nRT

This is an isothermal mixing process at constant pressure. Since no moving parts the system, so external work done is zero.
First law of thermodynamics equation, dU=dQ+dW

For isothermal process, dU=0

Therefore, dQ=−dW

Integrating for overall process, Q=−W

Here W is the total reversible work done in the mixing process to be calculated as follows:

W=WA+WB=−∫ V A V A+ V BPdV−∫ V B V A+ V BPdV=−∫ V A V A+ V BnARTdV/V−∫ V B V A+ V BnBRTdV/V=−nARTln VA+VB/VA−nBRTln VA+VB/VB=−nARTln nA+nB/nA−nBRTln nA+nB/nB=nARTln xA+nBRTln xB (applying ideal gas law equation)

Here nA, VA, xA refers to mole of air, volume of air and final mole fraction of air. Similarly, nB, VB, xB refers to mole of oxygen, volume of oxygen and final mole fraction of oxygen.

Rate of heat transfer, Q=−nARTln xA−nBRTln xB

Interpretation Introduction

(c)

Interpretation:

Rate of entropy generation (WK-1) should be calculated.

Concept Introduction:

Entropy of mixing can be calculated using following formula:

ΔS=Q/T=−nARln xA−nBRln xB

Here, n is number of moles, R is Universal gas constant and x is mole fraction.

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Answer 2

Question

Chapter 10, Problem 10.38P

Interpretation Introduction

(a)

Interpretation:

Rate of air and oxygen flow in mol/s unit should be calculated.

Concept Introduction:

Let us assume x represents rate of air flow (mol/s) and y represents rate of pure oxygen flow rate (mol/s) into the process.

Component material balance equation will be used to determine rate of air flow and oxygen flow.

Interpretation Introduction

(b)

Interpretation:

Rate of heat transfer for this mixing process should be calculated.

Concept Introduction:

It is considered ideal gas law is followed for the entire mixing process, PV=nRT

This is an isothermal mixing process at constant pressure. Since no moving parts the system, so external work done is zero.
First law of thermodynamics equation, dU=dQ+dW

For isothermal process, dU=0

Therefore, dQ=−dW

Integrating for overall process, Q=−W

Here W is the total reversible work done in the mixing process to be calculated as follows:

W=WA+WB=−∫ V A V A+ V BPdV−∫ V B V A+ V BPdV=−∫ V A V A+ V BnARTdV/V−∫ V B V A+ V BnBRTdV/V=−nARTln VA+VB/VA−nBRTln VA+VB/VB=−nARTln nA+nB/nA−nBRTln nA+nB/nB=nARTln xA+nBRTln xB (applying ideal gas law equation)

Here nA, VA, xA refers to mole of air, volume of air and final mole fraction of air. Similarly, nB, VB, xB refers to mole of oxygen, volume of oxygen and final mole fraction of oxygen.

Rate of heat transfer, Q=−nARTln xA−nBRTln xB

Interpretation Introduction

(c)

Interpretation:

Rate of entropy generation (WK-1) should be calculated.

Concept Introduction:

Entropy of mixing can be calculated using following formula:

ΔS=Q/T=−nARln xA−nBRln xB

Here, n is number of moles, R is Universal gas constant and x is mole fraction.

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Answer 3

Question

Chapter 10, Problem 10.38P

Interpretation Introduction

(a)

Interpretation:

Rate of air and oxygen flow in mol/s unit should be calculated.

Concept Introduction:

Let us assume x represents rate of air flow (mol/s) and y represents rate of pure oxygen flow rate (mol/s) into the process.

Component material balance equation will be used to determine rate of air flow and oxygen flow.

Interpretation Introduction

(b)

Interpretation:

Rate of heat transfer for this mixing process should be calculated.

Concept Introduction:

It is considered ideal gas law is followed for the entire mixing process, PV=nRT

This is an isothermal mixing process at constant pressure. Since no moving parts the system, so external work done is zero.
First law of thermodynamics equation, dU=dQ+dW

For isothermal process, dU=0

Therefore, dQ=−dW

Integrating for overall process, Q=−W

Here W is the total reversible work done in the mixing process to be calculated as follows:

W=WA+WB=−∫ V A V A+ V BPdV−∫ V B V A+ V BPdV=−∫ V A V A+ V BnARTdV/V−∫ V B V A+ V BnBRTdV/V=−nARTln VA+VB/VA−nBRTln VA+VB/VB=−nARTln nA+nB/nA−nBRTln nA+nB/nB=nARTln xA+nBRTln xB (applying ideal gas law equation)

Here nA, VA, xA refers to mole of air, volume of air and final mole fraction of air. Similarly, nB, VB, xB refers to mole of oxygen, volume of oxygen and final mole fraction of oxygen.

Rate of heat transfer, Q=−nARTln xA−nBRTln xB

Interpretation Introduction

(c)

Interpretation:

Rate of entropy generation (WK-1) should be calculated.

Concept Introduction:

Entropy of mixing can be calculated using following formula:

ΔS=Q/T=−nARln xA−nBRln xB

Here, n is number of moles, R is Universal gas constant and x is mole fraction.

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 10, Problem 10.38P

Interpretation Introduction

(a)

Interpretation:

Rate of air and oxygen flow in mol/s unit should be calculated.

Concept Introduction:

Let us assume x represents rate of air flow (mol/s) and y represents rate of pure oxygen flow rate (mol/s) into the process.

Component material balance equation will be used to determine rate of air flow and oxygen flow.

Interpretation Introduction

(b)

Interpretation:

Rate of heat transfer for this mixing process should be calculated.

Concept Introduction:

It is considered ideal gas law is followed for the entire mixing process, PV=nRT

This is an isothermal mixing process at constant pressure. Since no moving parts the system, so external work done is zero.
First law of thermodynamics equation, dU=dQ+dW

For isothermal process, dU=0

Therefore, dQ=−dW

Integrating for overall process, Q=−W

Here W is the total reversible work done in the mixing process to be calculated as follows:

W=WA+WB=−∫ V A V A+ V BPdV−∫ V B V A+ V BPdV=−∫ V A V A+ V BnARTdV/V−∫ V B V A+ V BnBRTdV/V=−nARTln VA+VB/VA−nBRTln VA+VB/VB=−nARTln nA+nB/nA−nBRTln nA+nB/nB=nARTln xA+nBRTln xB (applying ideal gas law equation)

Here nA, VA, xA refers to mole of air, volume of air and final mole fraction of air. Similarly, nB, VB, xB refers to mole of oxygen, volume of oxygen and final mole fraction of oxygen.

Rate of heat transfer, Q=−nARTln xA−nBRTln xB

Interpretation Introduction

(c)

Interpretation:

Rate of entropy generation (WK-1) should be calculated.

Concept Introduction:

Entropy of mixing can be calculated using following formula:

ΔS=Q/T=−nARln xA−nBRln xB

Here, n is number of moles, R is Universal gas constant and x is mole fraction.

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 5

Chapter 10, Problem 10.38P

Interpretation Introduction

(a)

Interpretation:

Rate of air and oxygen flow in mol/s unit should be calculated.

Concept Introduction:

Let us assume x represents rate of air flow (mol/s) and y represents rate of pure oxygen flow rate (mol/s) into the process.

Component material balance equation will be used to determine rate of air flow and oxygen flow.

Interpretation Introduction

(b)

Interpretation:

Rate of heat transfer for this mixing process should be calculated.

Concept Introduction:

It is considered ideal gas law is followed for the entire mixing process, PV=nRT

This is an isothermal mixing process at constant pressure. Since no moving parts the system, so external work done is zero.
First law of thermodynamics equation, dU=dQ+dW

For isothermal process, dU=0

Therefore, dQ=−dW

Integrating for overall process, Q=−W

Here W is the total reversible work done in the mixing process to be calculated as follows:

W=WA+WB=−∫ V A V A+ V BPdV−∫ V B V A+ V BPdV=−∫ V A V A+ V BnARTdV/V−∫ V B V A+ V BnBRTdV/V=−nARTln VA+VB/VA−nBRTln VA+VB/VB=−nARTln nA+nB/nA−nBRTln nA+nB/nB=nARTln xA+nBRTln xB (applying ideal gas law equation)

Here nA, VA, xA refers to mole of air, volume of air and final mole fraction of air. Similarly, nB, VB, xB refers to mole of oxygen, volume of oxygen and final mole fraction of oxygen.

Rate of heat transfer, Q=−nARTln xA−nBRTln xB

Interpretation Introduction

(c)

Interpretation:

Rate of entropy generation (WK-1) should be calculated.

Concept Introduction:

Entropy of mixing can be calculated using following formula:

ΔS=Q/T=−nARln xA−nBRln xB

Here, n is number of moles, R is Universal gas constant and x is mole fraction.

Answer 6

Chapter 10, Problem 10.38P

Interpretation Introduction

(a)

Interpretation:

Rate of air and oxygen flow in mol/s unit should be calculated.

Concept Introduction:

Let us assume x represents rate of air flow (mol/s) and y represents rate of pure oxygen flow rate (mol/s) into the process.

Component material balance equation will be used to determine rate of air flow and oxygen flow.

Answer 7

Chapter 10, Problem 10.38P

Interpretation Introduction

(a)

Interpretation:

Rate of air and oxygen flow in mol/s unit should be calculated.

Concept Introduction:

Let us assume x represents rate of air flow (mol/s) and y represents rate of pure oxygen flow rate (mol/s) into the process.

Component material balance equation will be used to determine rate of air flow and oxygen flow.

Answer 8

Interpretation Introduction

(b)

Interpretation:

Rate of heat transfer for this mixing process should be calculated.

Concept Introduction:

It is considered ideal gas law is followed for the entire mixing process, PV=nRT

This is an isothermal mixing process at constant pressure. Since no moving parts the system, so external work done is zero.
First law of thermodynamics equation, dU=dQ+dW

For isothermal process, dU=0

Therefore, dQ=−dW

Integrating for overall process, Q=−W

Here W is the total reversible work done in the mixing process to be calculated as follows:

W=WA+WB=−∫ V A V A+ V BPdV−∫ V B V A+ V BPdV=−∫ V A V A+ V BnARTdV/V−∫ V B V A+ V BnBRTdV/V=−nARTln VA+VB/VA−nBRTln VA+VB/VB=−nARTln nA+nB/nA−nBRTln nA+nB/nB=nARTln xA+nBRTln xB (applying ideal gas law equation)

Here nA, VA, xA refers to mole of air, volume of air and final mole fraction of air. Similarly, nB, VB, xB refers to mole of oxygen, volume of oxygen and final mole fraction of oxygen.

Rate of heat transfer, Q=−nARTln xA−nBRTln xB

Answer 9

Interpretation Introduction

(b)

Interpretation:

Rate of heat transfer for this mixing process should be calculated.

Concept Introduction:

It is considered ideal gas law is followed for the entire mixing process, PV=nRT

This is an isothermal mixing process at constant pressure. Since no moving parts the system, so external work done is zero.
First law of thermodynamics equation, dU=dQ+dW

For isothermal process, dU=0

Therefore, dQ=−dW

Integrating for overall process, Q=−W

Here W is the total reversible work done in the mixing process to be calculated as follows:

W=WA+WB=−∫ V A V A+ V BPdV−∫ V B V A+ V BPdV=−∫ V A V A+ V BnARTdV/V−∫ V B V A+ V BnBRTdV/V=−nARTln VA+VB/VA−nBRTln VA+VB/VB=−nARTln nA+nB/nA−nBRTln nA+nB/nB=nARTln xA+nBRTln xB (applying ideal gas law equation)

Here nA, VA, xA refers to mole of air, volume of air and final mole fraction of air. Similarly, nB, VB, xB refers to mole of oxygen, volume of oxygen and final mole fraction of oxygen.

Rate of heat transfer, Q=−nARTln xA−nBRTln xB

Answer 10

Interpretation Introduction

(c)

Interpretation:

Rate of entropy generation (WK-1) should be calculated.

Concept Introduction:

Entropy of mixing can be calculated using following formula:

ΔS=Q/T=−nARln xA−nBRln xB

Here, n is number of moles, R is Universal gas constant and x is mole fraction.

Answer 11

Interpretation Introduction

(c)

Interpretation:

Rate of entropy generation (WK-1) should be calculated.

Concept Introduction:

Entropy of mixing can be calculated using following formula:

ΔS=Q/T=−nARln xA−nBRln xB

Here, n is number of moles, R is Universal gas constant and x is mole fraction.

Answer 12

Expert Solution & Answer

Answer 13

Expert Solution & Answer

Answer 14

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Answer 15

Ch. 10 - Prob. 10.1P Ch. 10 - Prob. 10.2P Ch. 10 - Prob. 10.3P Ch. 10 - What is the ideal work for the separation of an...Ch. 10 - Prob. 10.5P Ch. 10 - Prob. 10.6P Ch. 10 - Prob. 10.7P Ch. 10 - Prob. 10.8P Ch. 10 - Prob. 10.9P Ch. 10 - Prob. 10.10P

(c) Interpretation: Rate of entropy generation (WK-1) should be calculated. Concept Introduction: Entropy of mixing can be calculated using following formula: ΔS=Q/T=−nARln xA−nBRln xB Here, n is number of moles, R is Universal gas constant and x is mole fraction.

Want to see the full answer?

Chapter 10 Solutions

(c)

Interpretation:

Rate of entropy generation (WK-1) should be calculated.

Concept Introduction:

Entropy of mixing can be calculated using following formula:

ΔS=Q/T=−nARln xA−nBRln xB

Here, n is number of moles, R is Universal gas constant and x is mole fraction.