The work required for the separation of air in the given steady-flow process if the thermodynamic efficiency is 5%. Concept introduction: Here, pressure and temperature are constant. In the given conditions, the work has to be obtained for de-mixing that is the separation of the gases from the given mixture. To understand the process, the enthalpy change of de-mixing and entropy change of de-mixing needs to be calculated. And, work can be calculated by: W i d e a l = Δ H − T σ Δ S Where, W = work ?H = change in entropy T = temperature ?S = change in entropy

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Chapter 10, Problem 10.5P

Interpretation Introduction

Interpretation:

The work required for the separation of air in the given steady-flow process if the thermodynamic efficiency is 5%.

Concept introduction:

Here, pressure and temperature are constant.

In the given conditions, the work has to be obtained for de-mixing that is the separation of the gases from the given mixture.

To understand the process, the enthalpy change of de-mixing and entropy change of de-mixing needs to be calculated.

And, work can be calculated by:

Wideal=ΔH−TσΔS

Where, W = work

?H = change in entropy

T = temperature

?S = change in entropy

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