Chemistry
Chemistry
12th Edition
ISBN: 9780078021510
Author: Raymond Chang Dr., Kenneth Goldsby Professor
Publisher: McGraw-Hill Education
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Chapter 10, Problem 10.124QP

Given that the order of molecular orbitals for NO is similar to that for O2, arrange the following species in increasing bond orders: NO2−, NO, NO, NO+, NO2+.

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Interpretation Introduction

Interpretation: The given species have to be arranged in the increasing order of their bond order.

Concept Introduction:

Bond order:

Bond order determines the number of bonds in the pair of two atoms. So, it is the quantitative measure of a bond.

The bond order can be calculated as follows:

Bondorder=(Numberofelectronsinbondingmolecularorbital)(Numberofelectronsinantibondingmolecularorbital)2

Trends in the bond order:

The species with the negative charge means that electrons are getting added in the anti-bonding molecular orbital. So the number of electrons in the anti-bonding molecular orbital increases accordingly. Ultimately, the bond order decreases. Whereas, the species with the positive charge means that electrons are being removed from the anti-bonding molecular orbital. So the number of electrons in the anti-bonding molecular orbital decreases accordingly. Ultimately, the bond order increases.

Answer to Problem 10.124QP

The given species can be arranged in the increasing order of their bond order as follows:

NO2-<NO-<NO=NO2+<NO+

Explanation of Solution

Given: The order of molecular orbitals of NO is similar to that of O2.

The molecular orbitals of O2:

The molecular orbital configuration of O2 molecule is:

(σ1s)2(σ*1s)2(σ2s)2(σ*2s)2(σ2pz)2(π2px2=π2py2)(π*2px1=π*2py1)*Antibondingmolecularorbital

Bond order of NO:

The molecular orbitals of NO:

(σ1s)2(σ*1s)2(σ2s)2(σ*2s)2(σ2pz)2(π2px2=π2py2)(π*2px1)(π*2py0)*Antibondingmolecularorbital

The bond order of NO can be calculated as follows:

Bondorder=(Numberofelectronsinbondingmolecularorbital)(Numberofelectronsinantibondingmolecularorbital)2

Bondorder=(10)52=52=2.5

Similarly, the bond orders can be calculated for each of the given species as follows:

Bond order of NO2-:

The molecular orbitals of NO2-:

(σ1s)2(σ*1s)2(σ2s)2(σ*2s)2(σ2pz)2(π2px2=π2py2)(π*2px2)(π*2py1)*Antibondingmolecularorbital

The bond order of NO2- can be calculated as follows:

Bondorder=(Numberofelectronsinbondingmolecularorbital)(Numberofelectronsinantibondingmolecularorbital)2

Bondorder=(10)72=32=1.5

Bond order of NO-:

The molecular orbitals of NO-:

(σ1s)2(σ*1s)2(σ2s)2(σ*2s)2(σ2pz)2(π2px2=π2py2)(π*2px1)(π*2py1)*Antibondingmolecularorbital

The bond order of NO- can be calculated as follows:

Bondorder=(Numberofelectronsinbondingmolecularorbital)(Numberofelectronsinantibondingmolecularorbital)2

Bondorder=(10)62=42=2

Bond order of NO+:

The molecular orbitals of NO+:

(σ1s)2(σ*1s)2(σ2s)2(σ*2s)2(σ2pz)2(π2px2=π2py2)(π*2px0)(π*2py0)*Antibondingmolecularorbital

The bond order of NO+ can be calculated as follows:

Bondorder=(Numberofelectronsinbondingmolecularorbital)(Numberofelectronsinantibondingmolecularorbital)2

Bondorder=(10)42=62=3

Bond order of NO2+:

The molecular orbitals of NO2+:

(σ1s)2(σ*1s)2(σ2s)2(σ*2s)2(σ2pz)2(π2px2)(π2py1)(π*2px0)(π*2py0)*Antibondingmolecularorbital

The bond order of NO2+ can be calculated as follows:

Bondorder=(Numberofelectronsinbondingmolecularorbital)(Numberofelectronsinantibondingmolecularorbital)2

Bondorder=(9)42=52=2.5

The calculated bond orders can be tabulated as follows:

Given moleculeBond order.
NO2-1.5
NO-2
NO2.5
NO+3
NO2+2.5

Based on this tabulation, the given species can be arranged in the increasing order of their bond order as follows:

NO2-<NO-<NO=NO2+<NO+

Conclusion

The given species have been arranged in the increasing order of their bond order.

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Chapter 10 Solutions

Chemistry

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