Chapter 10, Problem 10.115QE

Interpretation Introduction

Interpretation:

The molecular orbital diagram and bond order of the ${\text{NO}}^{\text{+}}$ and ${\text{NO}}^{-}$ has to be given and the bond order has to be compared.

Concept Introduction:

Bond order of a molecule or ion is calculates by the following formula,

Bond order $\text{=}\frac{\left({\text{N}}_{\text{b}}\right)\text{-}\left({\text{N}}_{\text{a}}\right)}{\text{2}}$

Where, ${\text{N}}_{\text{b}}$ is number of electrons in bonding orbital.

${\text{N}}_{\text{a}}$ is number of electrons in antibonding orbital.