Compound that is expected to have highest boiling point has to be identified. Concept Introduction: The dipole moment is produced by two equal but opposite charges separated by a distance. The one with molecular dipole moment will exhibit high boiling point. Hydrogen bonding is a special type of dipole-dipole interaction in a polar bond which has hydrogen atom and a highly electronegative atom such as Nitrogen, Oxygen and Fluorine. The compounds that possess hydrogen bonding will exhibit high boiling point. In hydrocarbons, the boiling point appears to increase with increase in molecular weight. Branched hydrocarbon causes decrease in boiling point due to a smaller surface area.

Question

Want to see the full answer?

Answer 1

Question

Chapter 1, Problem 76IP

Interpretation Introduction

Interpretation:

Compound that is expected to have highest boiling point has to be identified.

Concept Introduction:

The dipole moment is produced by two equal but opposite charges separated by a distance. The one with molecular dipole moment will exhibit high boiling point.

Hydrogen bonding is a special type of dipole-dipole interaction in a polar bond which has hydrogen atom and a highly electronegative atom such as Nitrogen, Oxygen and Fluorine.

The compounds that possess hydrogen bonding will exhibit high boiling point.

In hydrocarbons, the boiling point appears to increase with increase in molecular weight.

Branched hydrocarbon causes decrease in boiling point due to a smaller surface area.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

A student proposes the following two-step synthesis of an ether from an alcohol A: 1. strong base A 2. R Is the student's proposed synthesis likely to work? If you said the proposed synthesis would work, enter the chemical formula or common abbreviation for an appropriate strong base to use in Step 1: If you said the synthesis would work, draw the structure of an alcohol A, and the structure of the additional reagent R needed in Step 2, in the drawing area below. If there's more than one reasonable choice for a good reaction yield, you can draw any of them. ☐ Click and drag to start drawing a structure. Yes No ロ→ロ 0|0 G Х D : ☐ ப

टे Predict the major products of this organic reaction. Be sure to use wedge and dash bonds when necessary, for example to distinguish between different major products. ☐ ☐ : ☐ + NaOH HO 2 Click and drag to start drawing a structure.

Shown below are five NMR spectra for five different C6H10O2 compounds. For each spectrum, draw the structure of the compound, and assign the spectrum by labeling H's in your structure (or in a second drawing of the structure) with the chemical shifts of the corresponding signals (which can be estimated to nearest 0.1 ppm). IR information is also provided. As a reminder, a peak near 1700 cm-1 is consistent with the presence of a carbonyl (C=O), and a peak near 3300 cm-1 is consistent with the presence of an O–H. Extra information: For C6H10O2 , there must be either 2 double bonds, or 1 triple bond, or two rings to account for the unsaturation. There is no two rings for this problem. A strong band was observed in the IR at 1717 cm-1