
Interpretation: For the given pair of compounds, the compound with higher boiling point has to be identified.
Concept Introduction:
The boiling points for the given set of compounds will be identified by knowing dipole-dipole interactions, hydrogen bonding, and number of carbon atoms and extent of branching within the given set of compounds.
A dipole-dipole interaction is the attraction between two polar molecules. When they approach each other, the negative end one molecule attracts the positive end of the other.
The interaction between highly electronegative atom and hydrogen atom is called hydrogen bonding. Electronegative atom should have lone pair of electrons to form hydrogen bonding. It is the process of interaction only i.e., no bond formation is involved.
Boiling points can be distinguished by the molecular weight of the compounds. It is based on the number of heavier atoms involved in bond formation. Linear or branching manner can also involve in the determination of boiling points. The compound with less branching structure has more boiling points and vice versa.
To find: Get the higher boiling point of a compound in the given pair of the compounds namely, 3-hexanol and neopentane

Want to see the full answer?
Check out a sample textbook solution
Chapter 1 Solutions
ORGANIC CHEMISTRY, WITH SOL. MAN/ STUDY
- Understanding the general acid-base properties of amino acids O Proteins Imagine each of the molecules shown below was found in an aqueous solution. Can you tell whether the solution is acidic, basic, or neutral? molecule The solution is... 010 H3N-CH-C-OH CH HO CH3 O acidic O basic neutral O (unknown) H3N HO 0 O acidic O basic neutral ○ (unknown) H3N-CH-C-O CH2 CH3-CH-CH3 O acidic O basic Oneutral ○ (unknown) O= X H2N-CH-C-O CH3 CH CH3 acidic O basic O neutral ○ (unknown) ? 000arrow_forwardImagine each of the molecules shown below was found in an aqueous solution. Can you tell whether the solution is acidic, basic, or neutral? molecule 0=0 H3N-CH-C-o HO CH2 OH The solution is... O acidic O basic O neutral O (unknown) H₂N acidic O basic O neutral ○ (unknown) + H3N O OH O acidic O basic O neutral O (unknown) H2N-CH-C-O CH3 O acidic O basic neutral ○ (unknown) X ? olo HEarrow_forwardRecognizing ampli Draw an a amino acid with a methyl (-CH3) side chain. Explanation Check Click and drag to start drawing a structure. X Carrow_forward
- Write the systematic name of each organic molecule: structure name × HO OH ☐ OH CI CI O CI OH OHarrow_forwardく Check the box under each a amino acid. If there are no a amino acids at all, check the "none of them" box under the table. Note for advanced students: don't assume every amino acid shown must be found in nature. COO H3N-C-H CH2 HO CH3 NH3 O CH3-CH CH2 OH Onone of them Explanation Check + H3N O 0. O OH + NH3 CH2 CH3-CH H2N C-COOH H O HIC + C=O H3N-C-O CH3- - CH CH2 OH Х 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center Accesarrow_forwardWrite the systematic name of each organic molecule: structure HO-C-CH2-CH3 O -OH CH3-CH2-CH2-CH2-CH2-C-OH CH3 CH3-CH-CH2-C-OH Explanation Check S namearrow_forward
- theres 2 productsarrow_forwardDraw the major product of this solvolysis reaction. Ignore any inorganic byproducts. + CH3CH2OH Drawing Q Atoms, Bonds and Rings OCH2CH3 || OEt Charges OH 00-> | Undo Reset | Br Remove Done Drag To Pan +arrow_forwardDraw the major product of this SN1 reaction. Ignore any inorganic byproducts. CH3CO2Na CH3CO2H Drawing + Br Q Atoms, Bonds and Rings OAC Charges OH ОАс Na ဂ Br Undo Reset Remove Done Drag To Pan +arrow_forward
- Organic Functional Groups entifying positions labeled with Greek letters in acids and derivatives 1/5 ssible, replace an H atom on the a carbon of the molecule in the drawing area with a ce an H atom on the ẞ carbon with a hydroxyl group substituent. ne of the substituents can't be added for any reason, just don't add it. If neither substi er the drawing area. O H OH Oneither substituent can be added. Check D 1 Accessibility ado na witharrow_forwardDifferentiate between electrophilic and nucleophilic groups. Give examples.arrow_forwardAn aldehyde/ketone plus an alcohol gives a hemiacetal, and an excess of alcohol gives an acetal. The reaction is an equilibrium; in aldehydes, it's shifted to the right and in ketones, to the left. Explain.arrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY





