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(a)
Interpretation:
To classify the bond present in the given molecules as covalent, polar covalent or ionic.
Concept introduction:
The bonds present in the atoms may be either covalent, ionic and coordination. All these is been decided by the electronegativity difference present in the atoms that share the bonds. If the electronegativity difference between two atoms in the bond is greater than 1.7 means the bond is ionic. If the difference is between 0.5 and 1.7 means the bond is polar covalent. If the difference is lesser than 0.5 means the bond is said to be covalent. The electronegativity value for the atoms is
Sodium = 0.9
Bromine = 2.8
Oxygen = 3.5
Hydrogen = 2.1
Carbon = 2.5
To Classify the bonds present in the given compounds.
(b)
Interpretation:
To classify the bond present in the given molecules as covalent, polar covalent or ionic.
Concept introduction:
The bonds present in the atoms may be either covalent, ionic and coordination. All these is been decided by the electronegativity difference present in the atoms that share the bonds. If the electronegativity difference between two atoms in the bond is greater than 1.7 means the bond is ionic. If the difference is between 0.5 and 1.7 means the bond is polar covalent. If the difference is lesser than 0.5 means the bond is said to be covalent. The electronegativity value for the atoms is
Sodium = 0.9
Bromine = 2.8
Oxygen = 3.5
Hydrogen = 2.1
Carbon = 2.5
To Classify: The bonds present in the given compound
(c)
Interpretation:
To classify the bond present in the given molecules as covalent, polar covalent or ionic.
Concept introduction:
The bonds present in the atoms may be either covalent, ionic and coordination. All these is been decided by the electronegativity difference present in the atoms that share the bonds. If the electronegativity difference between two atoms in the bond is greater than 1.7 means the bond is ionic. If the difference is between 0.5 and 1.7 means the bond is polar covalent. If the difference is lesser than 0.5 means the bond is said to be covalent. The electronegativity value for the atoms is
Sodium = 0.9
Bromine = 2.8
Oxygen = 3.5
Hydrogen = 2.1
Carbon = 2.5
To Classify: The bonds present in the given compounds
(d)
Interpretation:
To classify the bond present in the given molecules as covalent, polar covalent or ionic.
Concept introduction:
The bonds present in the atoms may be either covalent, ionic and coordination. All these is been decided by the electronegativity difference present in the atoms that share the bonds. If the electronegativity difference between two atoms in the bond is greater than 1.7 means the bond is ionic. If the difference is between 0.5 and 1.7 means the bond is polar covalent. If the difference is lesser than 0.5 means the bond is said to be covalent. The electronegativity value for the atoms is
Sodium = 0.9
Bromine = 2.8
Oxygen = 3.5
Hydrogen = 2.1
Carbon = 2.5
To Classify: The bonds present in the given compounds.
(e)
Interpretation:
To classify the bond present in the given molecules as covalent, polar covalent or ionic.
Concept introduction:
The bonds present in the atoms may be either covalent, ionic and coordination. All these is been decided by the electronegativity difference present in the atoms that share the bonds. If the electronegativity difference between two atoms in the bond is greater than 1.7 means the bond is ionic. If the difference is between 0.5 and 1.7 means the bond is polar covalent. If the difference is lesser than 0.5 means the bond is said to be covalent. The electronegativity value for the atoms is
Sodium = 0.9
Bromine = 2.8
Oxygen = 3.5
Hydrogen = 2.1
Carbon = 2.5
To find: To classify the bonds present in the given compound
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Chapter 1 Solutions
ORGANIC CHEMISTRY, WITH SOL. MAN/ STUDY
- Challenging samples: 1. Metal complexes with low volatility are often difficult to analyze when performing atomic absorption measurements because the atomization efficiency is reduced to unacceptably low levels. Devise a strategy or strategies for eliminating the problem of a non-volatile metal complex? Explain how you would do that. 2. Devise a strategy to overcome unwanted ionization of the analyte? Explain what it would be. 3. Devise a general method that can be used to account for the presence of unknown matrix effects.arrow_forwardDon't used hand raitingarrow_forwardDon't used hand raiting don't used Ai solutionarrow_forward
- Homework: Atomic Structure This homework is due at the beginning of class next lecture period and is worth 6 points. Please place the number of protons and neutrons in the nucleus and then put the number of electrons in the correct shell. Also give the correct atomic mass. Also, state if the atom is an ion (cation or anion). H* 1. Number of protons Number of electrons Number of neutrons Atomic mass 2. 26 13AI +++ Number of protons Number of neutrons Number of electrons Atomic massarrow_forwardDon't used hand raitingarrow_forwardI need help working this problem out step by step, I was trying to use my example from the txt book but all I know how to do is set it up. I need to be shown step by step as I am a visual learner. Please help me.arrow_forward
- Don't used hand raitingarrow_forwardDon't used Ai solution and don't used hand raitingarrow_forward& Calculate the molar enthalpy of combustion (A combH) of 1.80 g of pyruvic acid (CH3COCOOH; 88.1 g mol-1) at 37 °C when they are combusted in a calorimeter at constant volume with a calorimeter constant = 1.62 kJ °C-1 and the temperature rose by 1.55 °C. Given: R = 8.314 J mol −1 °C-1 and the combustion reaction: AN C3H4O3 + 2.502(g) → 3CO2(g) + 2H2O(l)arrow_forward
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