Pushing Electrons
4th Edition
ISBN: 9781133951889
Author: Weeks, Daniel P.
Publisher: Cengage Learning
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Textbook Question
Chapter 1, Problem 65EQ
The loss of a proton attached to the oxygen atom of
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2. Provide a clear arrow-pushing mechanism for the following reactions. Do not skip proton
transfers, do not combine steps, and make sure your arrows are clear enough to be interpreted
without ambiguity.
a.
CH3
Ph
OEt
هد
Ph
CH3
Hint: the species on the left is an ynolate, which behaves a lot like an enolate.
b.
CH3
H3C
CH3
CH3
H3C
an unexpected product,
containing a single 9-
membered ring
the expected product,
containing two fused rings
H3C-I
(H3C)2CuLi
an enolate
Chapter 1 Solutions
Pushing Electrons
Ch. 1 - 1. Hydrogen is a Group I element and each...Ch. 1 - Methanol has the molecular formula CH4O. Its...Ch. 1 - 3. The skeleton of chloromethane is...Ch. 1 - 4. Methanol’s skeleton is
Connecting all bonded...Ch. 1 - 5. The structure for chloromethane is
It...Ch. 1 - Prob. 6EQCh. 1 - 7. Dimethyl ether
No. of electrons in...Ch. 1 - Methylamine (CH5N) No. of electrons in structure...Ch. 1 - Methanethiol (CH4S) No. of electrons in structure...Ch. 1 - Methylal (C3H8O2) No. of electrons in structure...
Ch. 1 - Prob. 11EQCh. 1 - Adding electrons to the skeleton by making single...Ch. 1 - This is done by removing an unshared pair from...Ch. 1 - Prob. 14EQCh. 1 - Prob. 15EQCh. 1 - Prob. 16EQCh. 1 - The skeleton of acetyl chloride is . Write the...Ch. 1 - Three constitutional isomers exist for the formula...Ch. 1 - A number of constitutional isomers exist for the...Ch. 1 - Using the method outlined above, derive the...Ch. 1 - Prob. 21EQCh. 1 - Prob. 22EQCh. 1 - Prob. 23EQCh. 1 - Prob. 24EQCh. 1 - The skeleton of benzyldimethylamine is
The...Ch. 1 - The skeleton is benzaldoxime is The number of...Ch. 1 - Prob. 27EQCh. 1 - Derive Lewis structures for the compounds below....Ch. 1 - Prob. 29EQCh. 1 - Derive Lewis structures for the compounds below....Ch. 1 - Prob. 31EQCh. 1 - Derive Lewis structures for the compounds below....Ch. 1 - The Lewis structure of acetone is Circling the...Ch. 1 - Chloromethane has the Lewis...Ch. 1 - In the Lewis structure for chloromethane, the...Ch. 1 - Prob. 36EQCh. 1 - The oxygen atom in acetone possesses ____ unshared...Ch. 1 - Nitrobenzene has the skeleton
The number of...Ch. 1 - Prob. 39EQCh. 1 - Compute and add on the formal charges I these...Ch. 1 - Prob. 41EQCh. 1 - Prob. 42EQCh. 1 - Prob. 43EQCh. 1 - Prob. 44EQCh. 1 - Prob. 45EQCh. 1 - Prob. 46EQCh. 1 - Prob. 47EQCh. 1 - Compute and add on the formal charges in these...Ch. 1 - Prob. 49EQCh. 1 - Prob. 50EQCh. 1 - The n-propyl cation can be formed from a molecule...Ch. 1 - Prob. 52EQCh. 1 - Prob. 53EQCh. 1 - Methanol, CH3OH, is a compound in which the formal...Ch. 1 - When a proton becomes bonded to diethyl ether, by...Ch. 1 - Tetrahydrofuran has the structure
When a proton...Ch. 1 - Prob. 57EQCh. 1 - Prob. 58EQCh. 1 - The structure of pyridine is
When a proton...Ch. 1 - The carbon atom owns one electron from each of ...Ch. 1 - The n-butyl anion can be formed from When the CLi...Ch. 1 - The isobutyl anion can be formed from When the CNa...Ch. 1 - Prob. 63EQCh. 1 - Ethanol, , is a compound in which the formal...Ch. 1 - The loss of a proton attached to the oxygen atom...Ch. 1 - A very strong base can remove a proton from...Ch. 1 - Prob. 67EQCh. 1 - Prob. 68EQCh. 1 - Prob. 69EQCh. 1 - The homolysis of the OO bond in diacetyl peroxide...Ch. 1 - Prob. 71EQCh. 1 - Prob. 72EQCh. 1 - Prob. 73EQCh. 1 - Prob. 74EQCh. 1 - Prob. 75EQCh. 1 - Heterolytic cleavage of the CO bond to yield a...Ch. 1 - Prob. 77EQCh. 1 - Prob. 78EQCh. 1 - Prob. 79EQCh. 1 - Prob. 80EQ
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- b. H3C CH3 1. 2. H3O+ H3C MgBr H3Carrow_forwardPredict the major products of this reaction: excess H+ NaOH ? A Note that the first reactant is used in excess, that is, there is much more of the first reactant than the second. If there won't be any products, just check the box under the drawing area instead. Explanation Check Click and drag to start drawing a structure. © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use Privarrow_forward1. For each of the reaction "railroads" below, you are either asked to give the structure(s) of the starting material(s) or product(s), or provide reagents/conditions to accomplish the transformation, as indicated by the boxes. a. NaOMe H+ .CO,H HO₂C MeOH (excess) MeOH H3C Br يع CH3 1. LiAlH4 2. H3O+ 3. PBг3 H3C 1. Et-Li 2. H3O+ -CO₂Me -CO₂Me OH CH3 CH3 ল CH3arrow_forward
- Predict the intermediate 1 and final product 2 of this organic reaction: NaOMe ག1, ད།་, - + H You can draw 1 and 2 in any arrangement you like. 2 work up Note: if either 1 or 2 consists of a pair of enantiomers, just draw one structure using line bonds instead of 3D (dash and wedge) bonds at the chiral center. Explanation Check Click and drag to start drawing a structure. Х © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Parrow_forwardWhat is the total energy cost associated with the compound below adopting the shown conformation? CH3 HH DH CH3arrow_forwardΗΝ, Draw Final Product C cyclohexanone pH 4-5 Edit Enamine H3O+ CH3CH2Br THF, reflux H Edit Iminium Ionarrow_forward
- How many hydrogen atoms are connected to the indicated carbon atom?arrow_forwardIdentify the compound with the longest carbon - nitrogen bond. O CH3CH2CH=NH O CH3CH2NH2 CH3CH2C=N CH3CH=NCH 3 The length of all the carbon-nitrogen bonds are the samearrow_forwardIdentify any polar covalent bonds in epichlorohydrin with S+ and 8- symbols in the appropriate locations. Choose the correct answer below. Η H's+ 6Η Η Η Η Η Ηδ Η Ο Ο HH +Η Η +Η Η Η -8+ CIarrow_forward
- H H:O::::H H H HH H::O:D:D:H HH HH H:O:D:D:H .. HH H:O:D:D:H H H Select the correct Lewis dot structure for the following compound: CH3CH2OHarrow_forwardRank the following compounds in order of decreasing boiling point. ннннн -С-С-Н . н-с- ННННН H ΗΤΗ НННН TTTĪ н-с-с-с-с-о-н НННН НН C' Н н-с-с-с-с-н НН || Ш НННН H-C-C-C-C-N-H ННННН IVarrow_forwardRank the following compounds in order of decreasing dipole moment. |>||>||| ||>|||>| |>|||>|| |||>||>| O ||>>||| H F H F H c=c || H c=c F F IIIarrow_forward
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