Chapter 1, Problem 5RE

To determine

To Express: The inequalities in terms of the interval. $\left[-2,6\right)$ .

Answer to Problem 5RE

In this interval $\left[-2,6\right)$ , $x$ is a member of family of real numbers such that $x$ is a number of the interval $\{x\in R\backslash -2\le x\prec 6\}$ .

  

Explanation of Solution

Given information:

The inequality

Formula used:

The notation of number line shows the given interval $\left[\right)$ shows that closed and a open interval.

Calculation:

It is provided that the notation $\left[-2,6\right)$ ,shows that the real numbers are here starting form -2 and ending to 5.999 not equal to 6.

So the interval is , $\{x\in R\backslash -2\le x\prec 6\}$ .

This is the written statement of this notation and here x is a member of family of real numbers such that x is a number of the interval $\left[-2,6\right)$ .

Also this equation is written as: $\{x\in R\backslash x\in \left[-2,6\right)\}$ .

The notation of these inequalities are here:

  

Thus, this inequality is an closed and open interval , it means it starts form -2 and ended to one point less then 6 because 6 is an open interval.