ORGANIC CHEMISTRY-STUD.SOLNS.MAN+SG(LL)
4th Edition
ISBN: 9781119659587
Author: Klein
Publisher: WILEY
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Textbook Question
Chapter 1, Problem 55PP
Nicotine is an addictive substance found in tobacco. Identify the hybridization state and geometry of each the nitrogen atoms in nicotine:
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Students have asked these similar questions
Two important industrial chemicals, ethene, C2H4, and propene, C3H6, are produced by the steam (or thermal) cracking process: For each of the four carbon compounds, do the following:
Draw a Lewis structure.
Predict the geometry about the carbon atom.
Determine the hybridization of each type of carbon atom.
Identify the hybridization state, molecular geometry and approximate bond angle at the indicatednitrogen atom in the following
compound.
O sp²,bent, 109°
O sp²,bent, 120°
O sp3, tetrahedral, 109.5°
O sp3, trigonal pyramidal, ~109.5°
O sp2, trigonal pyramidal, 120°
CH3 HH CH₂.
H₂=C₂C=C₂C₂O₂H
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H³N¬C-C¬-H
H
HH
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Molecule G
Lewis structure
Hybridization
PFs
Number of o and n
bonds
Number of valence
electrons
Number of bonded atoms
Molecular shape
on central atom
Number of lone pairs
on central atom
Bonded-atom lone-
Polarity
pair arrangement
Central atom
Bond angles
Bond order
steric number
P-F:
Molecule H
Lewis structure
Hybridization
TeF6
Number of valence
Number of o and n
electrons
bonds
0:
Number of bonded atoms
Molecular shape
on central atom
Number of lone pairs
Bonded-atom lone-
Polarity
on central atom
pair arrangement
Central atom
Bond angles
Bond order
steric number
Тe-F:
Chapter 1 Solutions
ORGANIC CHEMISTRY-STUD.SOLNS.MAN+SG(LL)
Ch. 1.2 - Prob. 1LTSCh. 1.2 - Prob. 2ATSCh. 1.2 - Prob. 2LTSCh. 1.3 - Prob. 3LTSCh. 1.3 - Prob. 4PTSCh. 1.3 - Prob. 5PTSCh. 1.4 - Prob. 4LTSCh. 1.4 - Prob. 7PTSCh. 1.4 - Prob. 8PTSCh. 1.4 - Prob. 9ATS
Ch. 1.5 - Prob. 5LTSCh. 1.5 - Prob. 10PTSCh. 1.5 - Prob. 11ATSCh. 1.5 - Prob. 12ATSCh. 1.6 - Prob. 6LTSCh. 1.6 - Prob. 14ATSCh. 1.7 - Prob. 7LTSCh. 1.7 - Prob. 17ATSCh. 1.10 - Prob. 18CCCh. 1.10 - Prob. 20CCCh. 1.10 - Prob. 8LTSCh. 1.10 - Prob. 21PTSCh. 1.10 - Nemotin is a compound that was first isolated from...Ch. 1.10 - Prob. 23CCCh. 1.11 - Prob. 9LTSCh. 1.11 - Prob. 24PTSCh. 1.11 - Prob. 25PTSCh. 1.11 - Prob. 26PTSCh. 1.11 - Prob. 27ATSCh. 1.12 - Prob. 10LTSCh. 1.12 - Prob. 29ATSCh. 1.13 - Prob. 11LTSCh. 1.13 - Prob. 31ATSCh. 1 - Prob. 32PPCh. 1 - Prob. 33PPCh. 1 - Prob. 34PPCh. 1 - Prob. 35PPCh. 1 - Prob. 36PPCh. 1 - Prob. 37PPCh. 1 - Prob. 38PPCh. 1 - Prob. 39PPCh. 1 - Prob. 40PPCh. 1 - Prob. 41PPCh. 1 - Prob. 42PPCh. 1 - Prob. 44PPCh. 1 - Prob. 45PPCh. 1 - Prob. 46PPCh. 1 - Prob. 47PPCh. 1 - Prob. 48PPCh. 1 - Prob. 49PPCh. 1 - Prob. 50PPCh. 1 - Prob. 51PPCh. 1 - Prob. 52PPCh. 1 - Prob. 53PPCh. 1 - Prob. 54PPCh. 1 - Nicotine is an addictive substance found in...Ch. 1 - Prob. 56PPCh. 1 - Prob. 57PPCh. 1 - Prob. 59PPCh. 1 - Prob. 63ASPCh. 1 - Prob. 64ASPCh. 1 - Prob. 66ASPCh. 1 - Prob. 69ASPCh. 1 - Prob. 71ASPCh. 1 - Prob. 72ASPCh. 1 - Prob. 75IP
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- Identify the type of hybridization, approximate bond angles for the N, C, and O atoms, and shortest carbon-to-oxygen bond length in alanine, an amino acid, whose Lewis structure isarrow_forwardMethylcyanoacrylate is the active ingredient in super glues. Its Lewis structure is (a) Give values for the three bond angles indicated. (b) Indicate the most polar bond in the molecule. (c) Circle the shortest carbon-oxygen bond. (d) Circle the shortest carbon-carbon bond.arrow_forwardcarbon is the master of hybridization, name 3 different compounds that showcase 3 different hybridization variants in the carbon atom. Include compond names, lewis diagram and the hybridization of the carbon atom. For each of the following compounds draw the lewis diagram. Include VSEPR family, the VSEPR shape? Determine the color of light emitted from an electron in a hydrogen atom that falls from n = 6 to n = 2.arrow_forward
- Harry creates a compound that contains only 1 pi (π) bond in total. The central atom has 4s2, 3d10, and 4p5. There are only 3 surrounding atoms with the electron configuration: 1s2 2s2 2p5. What is the formula and VSEPR shape for this compound? Explain how this is possible with respect to hybridized orbitals and how electrons are moved around to create this compound.arrow_forwardIdentify the hybridization state, molecular geometry and approximate bond angle around the carbon atomfor the molecule shown in box below. sp², tetrahedral, 109° sp², trigonal planar, 120° sp³, tetrahedral, 109.5° sp³, trigonal pyramidal, <109.5° O sp², trigonal pyramidal, 180° HCOOHarrow_forwardWhen looking at the hybridized orbital diagram, we can see which orbitals( and their electrons) will lead to sigma, pi and lone pair of electrons. Indicate where you would find each of the following :arrow_forward
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