Concept explainers
a.
Interpretation: All the constitutional isomers that have molecular formulas
Concept Introduction: The molecules that possess the same molecular formula but differ in the structural arrangement of atoms in the molecule are said to be isomers of each other.
a.
Answer to Problem 32PP
Explanation of Solution
For the first isomer structure, all two-carbon atoms are written in a straight chain and the chlorine atom is bonded to one of the carbon atoms as:
There is no other possibility for the different structural formula
b.
Interpretation: All the constitutional isomers that have molecular formulas
Concept Introduction: The molecules that possess the same molecular formula but differ in the structural arrangement of atoms in the molecule are said to be isomers of each other.
b.
Answer to Problem 32PP
Isomer I:
Isomer II:
Explanation of Solution
The different structural the arrangement of atoms in the molecule
- All two-carbon atoms are written in a straight chain and two chlorine atoms are bonded to one of the carbon atoms resulting in:
- Interchanging the position of one hydrogen atom at first carbon with one chlorine atom of the second carbon atom.
Isomer I:
Isomer II:
c.
Interpretation: All the constitutional isomers that have molecular formulas
Concept Introduction: The molecules that possess the same molecular formula but differ in the structural arrangements of atoms in the molecule are said to be isomers of each other.
c.
Answer to Problem 32PP
Isomer I:
Isomer II:
Explanation of Solution
The different structural arrangement of atoms in the molecule
- All two-carbon atoms are written in a straight chain and three chlorine atoms are bonded to one of the carbon atoms resulting in:
- Interchanging the position of one hydrogen atom at first carbon with one chlorine atom of the second carbon atom.
Isomer I:
Isomer II:
d.
Interpretation: All the constitutional isomers that have molecular formulas
Concept Introduction: The molecules that possess the same molecular formula but differ in the structural arrangements of atoms in the molecule are said to be isomers of each other.
d.
Answer to Problem 32PP
Isomer I:
Isomer II:
Isomer III:
Isomer IV:
Isomer V:
Explanation of Solution
The different structural arrangement of atoms in the molecule
- All six-carbon atoms are written in a straight chain resulting in:
- Five-carbon atoms are written in a straight chain and a methyl group is attached to the second carbon resulting in:
- Five-carbon atoms are written in a straight chain and a methyl group is attached to the third carbon resulting in:
- Four-carbon atoms are written in a straight chain and a methyl group is attached to the second and third carbon resulting in:
- Four-carbon atoms are written in a straight chain and two methyl groups are attached to the second carbon resulting in:
Isomer I:
Isomer II:
Isomer III:
Isomer IV:
Isomer V:
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Chapter 1 Solutions
ORGANIC CHEMISTRY-STUD.SOLNS.MAN+SG(LL)
- Which of the following C-C bonds is the shortest? A. в D E Select one: O a. A O b. B O c. C O d. D О е. Еarrow_forwardDetermine the geometry around all second-row elements in each compound. :0: a. CH3-C-CH3 b. CHg-Q-CH3 C. TỈNH, Predict the indicated bond angles in each compound. H b. CH₂ C CI a. CH₂=C=C-CI H C. CH3 C CI H d. CH3-C=N:arrow_forwardSelect one: 1 O b. H 1.008 3 Li 6.94 4 Be 9.012 5 10 sigma bonds, 6 pi bonds 6 13 sigma bonds, 3 pi bonds 7 со | | C-C-C-C-N O c. 11 sigma bonds, 5 pi bonds O d. 10 sigma bonds, 3 pi bonds The compound with molecular formula C5H-NO has the simple bond connections below with the hydrogens left out. Complete the Lewis structure for this molecule, adding the hydrogens anywhere appropriate and making sure that all atoms have zero formal charges while keeping all electrons paired. How many sigma and pi bonds are present in the molecule? 2 8 B C NOF Ne 10.81 12.011 14.007 15.999 18.998 20.180 9 He 4.003 10arrow_forward
- 112arrow_forwardGive each atom the appropriate formal charge: a. CH3 - O - CH3 H b. H - C- H H c. CH3 CH3 - N - CH3 CH3 d. H H H - N - B - H H - Harrow_forward7. Which is the shortest bondin the following compound? H. H-C=C-C=C_C-H 111 H H H Il III IV A. I B. II C. III D. IV E.I and III have the same lengtharrow_forward
- Count the total number of o bonds and a bonds in the compound below: H. H H H H H o bond(s) a bond(s)arrow_forwarda, +1 b. -1 C. +2 7. 8. Draw the following compounds by representing them as covalent bonds using VSEPR Theory: a. CO2 b. H2SO4 с. СН3ОН d. N2O3 as eitherarrow_forwardHow many electron charge clouds, also called electron groups, surround the indicated carbon atom (the one with the arrow pointing to it) in the sweetner aspartame? 06 3 ○ 8 4 02 :0 I I : 0-1 H C H C H- N C H H H HIC H C C 0: C C H H H H Н. := : 0=0 H―Z: O CIN C-C- :0: H H -C- H Harrow_forward
- Which best describes the overall shape of benzophenone? 4 27 O a. It is planar because all of the carbons are trigonal planar. O b. It is non-planar because all of the carbon atoms are tetrahedral. O c. It is non-planar because all of the carbons are trigonal planar. Od. It is planar because all of the carbons are tetrahedral.arrow_forward19arrow_forwarddont provide handwriting solution .....arrow_forward
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