Chapter 1, Problem 1.86P

Interpretation Introduction

Interpretation:

The total mass of the elements present in the earth’s crust is to be calculated.

Concept introduction:

The conversion of one unit into another can be done using a proper conversion factor. Conversion factors are the ratios that relate the two different units of a quantity. It is also known as dimensional analysis or factor label method.

In the unit conversion problems, the given information is multiplied by the conversion factors to obtain the desired information. The unit conversion can be done as follows:

$\left(\cancel{\text{beginning unit}}\right)\left(\frac{\text{Final unit}}{\cancel{\text{beginning unit}}}\right)=\text{Final unit}$

The conversion factor to convert ${\text{km}}^{\text{3}}$ to ${\text{m}}^{\text{3}}$ is as follows:

${\left(1\text{ km}\right)}^{\text{3}}={\left(1000\text{ m}\right)}^3$

The conversion factor to convert ${\text{m}}^{\text{3}}$ to ${\text{cm}}^{\text{3}}$ is as follows:

${\left(1\text{ m}\right)}^{\text{3}}={\left(100\text{ cm}\right)}^3$

The conversion factor to convert $\text{kg}$ to $\text{g}$ is as follows:

$1\text{ kg}=1000\text{ g}$

The conversion factor to convert $\text{g}$ to $\text{kg}$ is as follows:

$1000\text{ g}=1\text{ kg}$

The conversion factor to convert $\text{kg}$ to the metric ton is as follows:

$1000\text{ kg}=1\text{ t}$