The difference in height between the columns of a manometer is 2 00 mm , with a fluid of density 900kg/m 3 . What is the pressure difference? What is the height difference if the same pressure difference is measured using mercury (density =13600kg/m 3 ) as manometer fluid?
The difference in height between the columns of a manometer is 2 00 mm , with a fluid of density 900kg/m 3 . What is the pressure difference? What is the height difference if the same pressure difference is measured using mercury (density =13600kg/m 3 ) as manometer fluid?
The difference in height between the columns of a manometer is
2
00
mm
, with a fluid of density
900kg/m
3
. What is the pressure difference? What is the height difference if the same pressure difference is measured using mercury (density
=13600kg/m
3
) as manometer fluid?
cutting
Instructions:
Do not copy the drawing.
Draw In third-angle orthographic projection, and to scale 1:1,
the following views of the hinge:
A sectional front view on A-A
A top view
⚫ A right view (Show all hidden detail)
Show the cutting plane in the top view
. Label the sectioned view
Note:
All views must comply with the SABS 0111 Code of Practice for
Engineering Drawing.
Galaxy A05s
Assessment criteria:
⚫ Sectional front view
026
12
042
66
[30]
11
10
1. Plot the moment (M), axial (N), and shear (S) diagrams as functions of z.
a)
b)
F₁ = 1250 N
F₁ = 600 N
M₁ = 350 000 N mm
F2 = 500 N
200 N
a = 600 mm
b=1000 mm
a=750 mm
b = 1000 mm
d)
M₁ = 350 000 N mm
F₁ = 600 N
F₂ =200 N
a = 600 mm
b = 1000 mm
M₁ 175 000 Nmm
F = 900 N
a-250 mm
b-1000 mm
-250 mm.
Figure 1: Schematics problem 1.
Given the following cross-sections (with units in mm):
b)
t=2
b=25
h=25
t = 1.5
b=20
b=25
t=2
I
t = 1.5
a=10
b=15
h-25
b=15
t=3
T
h=25
Figure 3: Cross-sections for problem 2.
1. For each of them, calculate the position of the centroid of area with respect to the given coordinate system
and report them in the table below.
2. For each of them, calculate the second moments of inertia I...
and I, around their respective centroid
of area and report them in the table below. Note: use the parallel axes theorem as much as possible to
minimize the need to solve integrals.
Centroid position
x
y
box
Moment of inertia
lyy
by
a)
b)
c)
d)
e)
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