You have run a gel with 5 uL of amplified DNA in addition to 1 uL of 6X loading dye.Comparing the brightness of this band to your marker, you estimated that your amplified DNA isapproximately 62 ng. What was the concentration of your amplified DNA that was loaded? Youdo not need to account for the volume of loading dye in your calculations.

Agarose Gel Electrophoresis (AGE), is an biochemistry technique which is used to estimate DNA…

Answered: You have run a gel with 5 uL of…

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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Similar questions

Calculate the transformation efficiency of an experiment conducted using 10ul of 0.005 ug/ul plasmid, you plated 100ul out of a total volume of 500ul and the count of transformed colonies was 186.
Could you please explain these: 1. Why analyze the unknowns in a (short) serial dilution rather than at a single concentration? 2. Which technique can detect lower concentrations of DNA? Compare the detection limit of the fluorescence approach and the absorbance approach
Three pieces of cut DNA were isolated using gel electrophoresis.The DNA that is the longest will be closest to the positive or negative electrode?
In hybridizing microarrays, we use a solution that contains {3X SSC, 0.5% SDS, 5ug/ml salmon sperm DNA, 5% glycerol}. Describe how to make 100ul of this solution using stocks of 20X SSC, 10% SDS, and 10 mg/ml salmon sperm DNA, sheared, in water. Note that Molecular Biology Grade H2O must be used in making up this solution.
You have two tubes, each with a pair of DNA fragments inside them. Tube #1 has fragments that are 500bp and 1000 bp in length. Tube #2 has fragments that are 7500bp and 8000bp in size. If you were to perform agarose gel electrophoresis and run the contents of each tube in two separate lanes on the same gel, what would you expect to see? O That the difference between the distances migrated by the two fragments in Tube #1 was much greater than the difference between the distances migrated by the two fragments in Tube #2. O That the difference between the distances migrated by the two fragments in Tube #1 was the same as difference between the distances migrated by the two fragments in Tube #2. O That the difference between the distances migrated by the two fragments in Tube #1 was much less than the difference between the distances migrated by the two fragments in Tube #2. O It is not possible to estimate what we would expect to see.
You used agarose gel electrophoresis to separate DNA fragments of different size and the experiment worked well. However, you wanted to re run the experiment but this time you made the gel with a higher percentage of Agarose. How might this affect your results compared to the first run? a. There would be no difference between the runs since it is the current, not the agarose that causes migration. b. The higher concentration of agarose would cause the DNA to break apart. c. You can't predict how the concetration of agarose would affect migration. d. The DNA fragments would migrate further down the gel than they did the first time. e. The DNA fragments wouldn't migrate as far down the gel as they did the first time.
Can you please help with 1c please picture with 1 graph is for question 1a) picture with 4 graphs is for question 1b) 1a) E. coli DNA and binturong DNA are both 50% G-C. If you randomly shear E. coli DNA into 1000 bp fragments and put it through density gradient equilibrium centrifugation, you will find that all the DNA bands at the same place in the gradient, and if you graph the distribution of DNA fragments in the gradient you will get a single peak (see below). If you perform the same experiment with binturong DNA, you will find that a small fraction of the DNA fragments band separately in the gradient (at a different density) and give rise to a small "satellite" peak on a graph of the distribution of DNA fragments in the gradient (see below). Why do these two DNA samples give different results, when they're both 50% G-C? 1b) If you denatured the random 1000 bp fragments of binturong DNA that you produced in question 1a by heating them to 95ºC, and then cooled them down to 60ºC…
How much 4x loading dye should be added to 11 uL of DNA? Report you answer in units of uL, with one digit after the decimal point.
What will be the Tm of DNA that has cytosine plus guanine content of 30% compared to that of DNA that has a cytosine plus guanine content of 50% if both are heated under the same experimental conditions? lower higher same impossible to determine from information given
How many microliters of pGLO plasmid will you need for a PCR reaction is you need 200 nanograms and the plasmid concentration is 0.05 micrograms/microliter?
After plasmid isolation, you take 0.5 uL of the sample and mix it with 1 uL of TE buffer. The absorbance of this sample at 260 nm is 0.8 and the average extinction coefficient of double-stranded DNA at 260 nm is 0.020 (μg/ml)−1 cm−1. What is the concentration of the undiluted sample? 120 μg/mL 80 μg/mL 40 μg/mL 12 μg/mL
Download BLOSUM30 and BLOSUMB0 substitu- tion matrices and place them side by side on your computer screen. What are the differences between the two matrices? Why do you see these differences?

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