You are givenn items sorted based on hi ratio and the knapsack capacity is W. Now, what is the time complexity of fractional knapsack problem? O(n log n) O(n) O(n*n) O(nW) You are given 4 items as {value, weight} pairs in this format {{20, 5}, {60, 20},{25, 10}, {X,25}}. You can assume that the array is sorted ratio. The capacity of knapsack is 39. The item no. 4 (whose weight is 25 ) is taken fractionally to fill upto the knapsack value weight based on the capacity. That fraction is represented in format. What is the lowest possible value of a?

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
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You are given n items sorted based on value ratio and the knapsack capacity is W. Now, what
is the time complexity of fractional knapsack problem?
weight
O(n log n)
O(n)
O(n*n)
O(nW)
You are given 4 items as {value, weight} pairs in this format {{20, 5}, {60, 20}, {25, 10}, {X, 25}}. You can assume that the array is sorted
value
weight
ratio. The capacity of knapsack is 39. The item no. 4 (whose weight is 25 ) is taken fractionally to fill upto the knapsack
based on the
capacity. That fraction is represented in format. What is the lowest possible value of a?
For the question above, assume the total value stored in the knapsack is 132 after you have filled upto the knapsack capacity. What is the value
of X (in other words, the value of the item no. 4) ?
Give your answer to at least two decimal places.
Transcribed Image Text:You are given n items sorted based on value ratio and the knapsack capacity is W. Now, what is the time complexity of fractional knapsack problem? weight O(n log n) O(n) O(n*n) O(nW) You are given 4 items as {value, weight} pairs in this format {{20, 5}, {60, 20}, {25, 10}, {X, 25}}. You can assume that the array is sorted value weight ratio. The capacity of knapsack is 39. The item no. 4 (whose weight is 25 ) is taken fractionally to fill upto the knapsack based on the capacity. That fraction is represented in format. What is the lowest possible value of a? For the question above, assume the total value stored in the knapsack is 132 after you have filled upto the knapsack capacity. What is the value of X (in other words, the value of the item no. 4) ? Give your answer to at least two decimal places.
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